Concept explainers
Refer to Exercise 8.88. Another common insecticide, diazinon, yielded LC50 measurements in three experiments of 7.8, 1.6, and 1.3.
- a Estimate the
mean LC50 for diazinon, with a 90% confidence interval. - b Estimate the difference between the mean LC50 for DDT and that for diazinon, with a 90% confidence interval. What assumptions are necessary for the method that you used to be valid?
8.88 The Environmental Protection Agency (EPA) has collected data on LC50 measurements (concentrations that kill 50% of test animals) for certain chemicals likely to be found in freshwater rivers and lakes. (See Exercise 7.13 for additional details.) For certain species of fish, the LC50 measurements (in parts per million) for DDT in 12 experiments were as follows:
Estimate the true mean LC50 for DDT with confidence coefficient .90. Assume that the LC50 measurements have an approximately
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Mathematical Statistics with Applications
- The price X (dollars per pound) and consumption y (in pounds per capita) of beef were samples for 10 randomly selected years. The following data should be used to answer the question that follows. n = 10 Ex = 36.19 Ex² = 134.17 2.9 < x < 6.2 Ey = 774.7 Iy? = 60739.23 Exy = 2832.21 %3D Using this data, a student calculated SSy = 28.43 SSx = 3.2 SSyy = 717. Which one of %3D the following represents the equation of the regression line between price and consumption O y-hat = 25.22x -13.8 O y-hat = 25.22x +13.8 O y-hat 8.88x + 453.37 O y-hat = 8.88x +45.34arrow_forwardC6. The GSS 2014 asked respondents to identify what was important for "truly being American." When asked "How important to have American ancestry?" answers were measured on a 4-point scale: 1 = very important, 2 = fairly important, 3 = not very important, and 4 = not important at all. We selected a sample of 20 GSS respondents and present their individual responses. Complete the five-step model for these data, using alpha = .01 to assess the significance of the model. %3D Black Other White 1 4 2 2 1 3 1 4. ANALYS | 2.arrow_forwardSuppose that you run a correlation and find the correlation coefficient is -0.589 and the regression 6.1x +58.29. The center of your x-data was 5.9 and the center of your y-data equation is y was 22.4. If the critical value is .396, use the appropriate method to predict the y value when a is 8.2 Submit Questionarrow_forward
- You have recorded the height and weight of 27 people. Suppose that your data meet the assumptions of correlation (data are normally distributed for both variables). You find that the Pearson correlation coefficient r = 0.4. Test whether height and weight are significantly correlated. Show your work. What is the critical value for this test? Write your complete finding with all statistical details.arrow_forwardRun a regression analysis on the following bivariate set of data with y as the response variable. Verify that the correlation is significant at an α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 43 on the response variable.arrow_forwardYou run a regression analysis on a bivariate set of data ( n = 39). With regression equation a 24.8 and j = 43.4, you obtain the y = 2.058x with a correlation coefficient of r = 0.251. You want to 27.113 predict what value (on average) for the response variable will be obtained from a value of 180 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.)arrow_forward
- You run a regression analysis on a bivariate set of data (n = 120). With i = 66.3 and y = 50.6, you obtain the regression equation y = 4.097x – 11.636 with a correlation coefficient of r = 0.56. You want to predict what value (on average) for the response variable will be obtained from a value of 120 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.)arrow_forward67.7 and y 50.7, you You run a regression analysis on a bivariate set of data (n obtain the regression equation 38). With a y = - 0.572x – 33.548 with a correlation coefficient of r = - 0.976. You want to predict what value (on average) for the response variable will be obtained from a value of 50 as the explanatory variable. What is the predicted response value? y =arrow_forwardYou may need to use the appropriate technology to answer this question. We want to test whether or not the addition of 3 variables to a model will be statistically significant. You are given the following information based on a sample of 25 observations. y = 62.480 1.838x₁ + 25.660x₂ - SSE = 745; SSR = 596 The model was also estimated including the 3 variables. The results are: ŷ ý = 59.220 – 1.766x + 25.635X, + 16.239Xg + 15.296X4 – 18.729x5 SSE = 540; SSR = 801 (a) State the null and alternative hypotheses. O Ho: One or more of the parameters is not equal to zero. H₂: B3 = P4=B5 O Ho: B₁ = B₂= B3 =B4=B5= H₂: One or more of the parameters is not equal to zero. O Ho: One or more of the parameters is not equal to zero. H₂: B₁ = B₂= B3 = P4 = B 5 = 0 ⒸH₁: B3 =B4 = ß5 = 0 H₂: One or more of the parameters is not equal to zero. ✓ (b) Test the null hypothesis at the 5% level of significance. Find the value of the test statistic. (Round your answer to two decimal places.) 5.64 X Find the…arrow_forward
- I have asked this question twice and both times it has been wrong. Answer given F=.82 and .77 both these are incorrect. A bakery is considering buying one of two gas ovens. The bakery requires that the temperature remain constant during a baking operation. A study was conducted to measure the variance in temperature of the ovens during the baking process. The variance in temperature before the thermostat restarted the flame for the Monarch oven was 3.3 for 22 measurements. The variance for the Kraft oven was 4 for 25 measurements. Does this information provide sufficient reason to conclude that there is a difference in the variances for the two ovens? Assume measurements are normally distributed and use a 0.02 level of significance.arrow_forwardIn the regression equation, ŷ = 2.164 + 1.3657x, and n = 6, the mean of x is 8.667, SSxx= 89.333 and Se= 3.44. A 95% confidence interval for the average of y when x=8 is ______. a) (9.13, 17.05) b) (2.75, 23.43) c) (10.31, 15.86) d) (3.56, 22.62) e) (12.09, 14.09)arrow_forwardIn the regression equation, y = 2.164 + 1.3657x, n = 6, the mean of x is 8.667, SSxx = 89.333 and Se = 3.44. A 95% confidence interval for the average of y when x = 8 is _________. (9.13, 17.05) (2.75, 23.43) (3.56, 22.62) (10.31, 15.86) (12.09, 14.09)arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill