Chapter 8.7, Problem 7ST2

To determine

To Find : The value of x to the nearest integer.

Answer to Problem 7ST2

The value of x is 109.

Explanation of Solution

Given information:

  

First apply the sin formula in the left right angle triangle,

  $\begin{array}{l}\sin 51°=\frac{\text{Perpendicular}}{70}\\ \begin{array}{l}\text{Perpendicular }=70\times 0.777\hfill \\ \text{Perpendicular }=54.4\hfill \end{array}\end{array}$

Again apply the sin formula in the rightmost right angle triangle,

  $\begin{array}{l}\sin 30°=\frac{\text{Perpendicular}}{x}\hfill \\ x=\frac{54.4}{0.5}\hfill \\ x=109\hfill \end{array}$

Therefore the value of x is 109.