Chapter 8.5, Problem 6CE

To determine

To express: $\tan S$ as a ratio for the given triangle.

Answer to Problem 6CE

  $\tan S=\frac{8}{15}$

Explanation of Solution

Given:

The triangle:

Concept Used:

  $\tan A=\frac{opposite}{adjacent}$

Consider the given triangle:

Now,

  $\begin{array}{c}\tan S=\frac{\text{leg opposite to}\angle S}{\text{leg adjacent to}\angle \text{S}}\\ =\frac{TR}{TS}\\ =\frac{8}{15}\end{array}$