McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
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Chapter 8, Problem 22CR
To determine

To find: the value of x

Expert Solution & Answer
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Answer to Problem 22CR

The value of x is x=25.75

Explanation of Solution

Given Information: Two right angled triangles with common altitude and some of the angles and sides being marked on the figure.

Formula used:

In a right triangle the sine of the angle is the ratio of the measure of side opposite to the angle to the hypotenuse.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 8, Problem 22CR , additional homework tip  1

It can be expressed as,

  sinB=ac

Similarly, the tangent of an angle is the ratio of opposite side to the adjacent side of the triangle expressed as,

  tanB=ab

Calculation: Consider the triangle given below.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 8, Problem 22CR , additional homework tip  2

Here, considering the triangle with acute angle 530,

  tan53°=xz .

  x=ztan53° ......(1)

Now, considering the other right triangle,

  sin76°=z20z=20sin76°

Referring to the table of trigonometric values in Page 311 in the textbook, the value of z can be obtained as,

  z=20×0.9703=19.406

Now, substituting the value of z in (1) gives the value of x as,

  x=19.406tan53°

Again , with the use of the table of trigonometric values in Page 311 in the textbook, the value of x can be obtained as,

  x=19.406tan53°=19.406×1.327=25.7526

Chapter 8 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

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