Chapter 8.6, Problem 60E

(a)

To determine

To find: a probability that the person selected a person who does not favor the amendment.

Answer to Problem 60E

The probability is 0.58.

Explanation of Solution

Given information:

One hundred college students were interviewed to determine their political party affiliations and whether they favored a balanced budget amendment to the U.S Construction. The results of the study are listed in the table, where $D$ represent Democrat and $R$ represents Republican.

Given table

  

Calculation:

There are total 34 students who do not favor the amendment.

So, the probability a student will be selected is,

  $\begin{array}{l}\frac{34}{100}\\ =0.34\end{array}$

Therefore, the probability is 0.58.

(b)

To determine

To find: a probability that the person selected a Republican.

Answer to Problem 60E

The probability is 0.45.

Explanation of Solution

Given information:

One hundred college students were interviewed to determine their political party affiliations and whether they favored a balanced budget amendment to the U.S Construction. The results of the study are listed in the table, where $D$ represent Democrat and $R$ represents Republican.

Given table

  

Calculation:

There are total 45 republican students.

So, the probability a student will be selected is,

  $\begin{array}{l}\frac{45}{100}\\ =0.45\end{array}$

Therefore, the probability is 0.45.

(c)

To determine

To find: a probability that the person selected a Democrat who favors the amendment.

Answer to Problem 60E

The probability is 0.23.

Explanation of Solution

Given information:

One hundred college students were interviewed to determine their political party affiliations and whether they favored a balanced budget amendment to the U.S Construction. The results of the study are listed in the table, where $D$ represent Democrat and $R$ represents Republican.

Given table

  

Calculation:

There are total 23 democratic students.

So, the probability a student will be selected is,

  $\begin{array}{l}\frac{23}{100}\\ =0.23\end{array}$

Therefore, the probability is 0.23.