
To write: the sum under sigma notation and evaluate it by graphing utility.

Answer to Problem 108E
The sum can be written as 7∑j=0(−1)j(12)j .
And
7∑j=0(−1)j(12)j=85128
Explanation of Solution
Given information:
A finite series expression is given as
1−12+14−18+...−1128
Concept used:
A finite series of the form a1+a2+a3+...+an can be written in sigma notation as
n∑j=1aj
Calculation:
Consider the series expression.
1−12+14−18+...−1128
Here, the series can be rewritten as
(−1)0(12)0+(−1)1(12)1+(−1)2(12)2+(−1)3(12)3+...+(−1)7(12)7
So, the lower index is 0 and upper index is 7.
Consider the variable j to write the index lower limit and upper limit for the sum.
So, the series can be written in sigma notation as
(−1)0(12)0+(−1)1(12)1+(−1)2(12)2+(−1)3(12)3+...+(−1)7(12)7=7∑j=0(−1)j(12)j
Follow the below steps to evaluate the sum by graphing utility
- Choose the SUM feature from MATH menu
- Choose SEQUENCE feature from OPERATION menu
- Enter the expression for the sequence (−1)j(12)j , variable of the sequence (j) , lower limit of the summation (0) , upper limit of the summation (7)
- Press the button ENTER
The calculator will display the result as 85128 .
Hence, the value of the sum is
7∑j=1(−1)j(12)j=85128
Chapter 8 Solutions
Precalculus with Limits: A Graphing Approach
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