Chemical Principles: The Quest for Insight
7th Edition
ISBN: 9781464183959
Author: Peter Atkins, Loretta Jones, Leroy Laverman
Publisher: W. H. Freeman
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Chapter 8, Problem 8E.6E
(a)
Interpretation Introduction
Interpretation:
The electronic configuration of
(b)
Interpretation Introduction
Interpretation:
The difference in the molecular orbitals of
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4. (a) Draw the shape of the atomic valence orbitals formed by the overlaping of two fluoride 2p atomic orbitals.
(b) Draw the molecular orbital diagrams for F2 and F2*. Identify their bond order and magnetic properties.
(c) An unstable nucleus exhibit radioactivity.
(i) Explain how the number of protons and neutrons in a radioactive nucleus can be used to predict its probable mode
decay.
(ii) Illustrate your answer in (i) with a schematic graph.
The sulfate ion can be represented with four S-O bonds or with two S-O and two So=O bonds.(a) Which representation is better from the standpoint of formal charges?(b) What is the shape of the sulfate ion, and what hybrid orbitals of S are postulated for the σ bonding?(c) In view of the answer to part (b), what orbitals of S must be used for the π bonds? What orbitals of O?(d) Draw a diagram to show how one atomic orbital from S and one from O overlap to form a π bond.
Borane (BH3) is unstable under normal conditions, but it has been detected at lowpressure.(a) Draw the Lewis structure for borane.(b) Draw a diagram of the bonding in BH3, and label the hybridization of each orbital.(c) Predict the H¬B¬H bond angle
Chapter 8 Solutions
Chemical Principles: The Quest for Insight
Ch. 8 - Prob. 8A.1ASTCh. 8 - Prob. 8A.1BSTCh. 8 - Prob. 8A.2ASTCh. 8 - Prob. 8A.2BSTCh. 8 - Prob. 8A.1ECh. 8 - Prob. 8A.2ECh. 8 - Prob. 8A.3ECh. 8 - Prob. 8A.4ECh. 8 - Prob. 8A.5ECh. 8 - Prob. 8A.6E
Ch. 8 - Prob. 8A.7ECh. 8 - Prob. 8A.8ECh. 8 - Prob. 8A.9ECh. 8 - Prob. 8A.10ECh. 8 - Prob. 8A.11ECh. 8 - Prob. 8A.12ECh. 8 - Prob. 8A.13ECh. 8 - Prob. 8A.14ECh. 8 - Prob. 8A.15ECh. 8 - Prob. 8A.16ECh. 8 - Prob. 8A.17ECh. 8 - Prob. 8A.18ECh. 8 - Prob. 8A.19ECh. 8 - Prob. 8A.20ECh. 8 - Prob. 8B.1ASTCh. 8 - Prob. 8B.1BSTCh. 8 - Prob. 8B.2ASTCh. 8 - Prob. 8B.2BSTCh. 8 - Prob. 8B.1ECh. 8 - Prob. 8B.2ECh. 8 - Prob. 8B.3ECh. 8 - Prob. 8B.4ECh. 8 - Prob. 8B.5ECh. 8 - Prob. 8B.6ECh. 8 - Prob. 8B.7ECh. 8 - Prob. 8B.8ECh. 8 - Prob. 8C.1ASTCh. 8 - Prob. 8C.1BSTCh. 8 - Prob. 8C.2BSTCh. 8 - Prob. 8C.1ECh. 8 - Prob. 8C.2ECh. 8 - Prob. 8C.3ECh. 8 - Prob. 8C.4ECh. 8 - Prob. 8C.5ECh. 8 - Prob. 8C.6ECh. 8 - Prob. 8D.1ASTCh. 8 - Prob. 8D.1BSTCh. 8 - Prob. 8D.2ASTCh. 8 - Prob. 8D.2BSTCh. 8 - Prob. 8D.1ECh. 8 - Prob. 8D.2ECh. 8 - Prob. 8D.3ECh. 8 - Prob. 8D.4ECh. 8 - Prob. 8D.5ECh. 8 - Prob. 8D.6ECh. 8 - Prob. 8D.7ECh. 8 - Prob. 8D.8ECh. 8 - Prob. 8E.1ASTCh. 8 - Prob. 8E.1BSTCh. 8 - Prob. 8E.2ASTCh. 8 - Prob. 8E.2BSTCh. 8 - Prob. 8E.1ECh. 8 - Prob. 8E.2ECh. 8 - Prob. 8E.3ECh. 8 - Prob. 8E.4ECh. 8 - Prob. 8E.5ECh. 8 - Prob. 8E.6ECh. 8 - Prob. 8E.7ECh. 8 - Prob. 8E.8ECh. 8 - Prob. 8F.1ASTCh. 8 - Prob. 8F.1BSTCh. 8 - Prob. 8F.2ASTCh. 8 - Prob. 8F.2BSTCh. 8 - Prob. 8F.1ECh. 8 - Prob. 8F.2ECh. 8 - Prob. 8F.3ECh. 8 - Prob. 8F.4ECh. 8 - Prob. 8F.5ECh. 8 - Prob. 8F.6ECh. 8 - Prob. 8G.1ASTCh. 8 - Prob. 8G.1BSTCh. 8 - Prob. 8G.2ASTCh. 8 - Prob. 8G.2BSTCh. 8 - Prob. 8G.1ECh. 8 - Prob. 8G.2ECh. 8 - Prob. 8G.3ECh. 8 - Prob. 8G.4ECh. 8 - Prob. 8G.5ECh. 8 - Prob. 8G.6ECh. 8 - Prob. 8G.7ECh. 8 - Prob. 8G.8ECh. 8 - Prob. 8G.9ECh. 8 - Prob. 8G.10ECh. 8 - Prob. 8H.1ASTCh. 8 - Prob. 8H.1BSTCh. 8 - Prob. 8H.2ASTCh. 8 - Prob. 8H.2BSTCh. 8 - Prob. 8H.1ECh. 8 - Prob. 8H.2ECh. 8 - Prob. 8H.3ECh. 8 - Prob. 8H.4ECh. 8 - Prob. 8H.5ECh. 8 - Prob. 8H.6ECh. 8 - Prob. 8H.7ECh. 8 - Prob. 8H.8ECh. 8 - Prob. 8H.10ECh. 8 - Prob. 8H.11ECh. 8 - Prob. 8H.12ECh. 8 - Prob. 8I.1ASTCh. 8 - Prob. 8I.1BSTCh. 8 - Prob. 8I.2ASTCh. 8 - Prob. 8I.2BSTCh. 8 - Prob. 8I.1ECh. 8 - Prob. 8I.2ECh. 8 - Prob. 8I.3ECh. 8 - Prob. 8I.5ECh. 8 - Prob. 8I.6ECh. 8 - Prob. 8I.7ECh. 8 - Prob. 8I.8ECh. 8 - Prob. 8I.9ECh. 8 - Prob. 8I.10ECh. 8 - Prob. 8I.11ECh. 8 - Prob. 8I.12ECh. 8 - Prob. 8I.13ECh. 8 - Prob. 8I.14ECh. 8 - Prob. 8I.15ECh. 8 - Prob. 8I.16ECh. 8 - Prob. 8J.1ASTCh. 8 - Prob. 8J.1BSTCh. 8 - Prob. 8J.1ECh. 8 - Prob. 8J.2ECh. 8 - Prob. 8J.3ECh. 8 - Prob. 8J.4ECh. 8 - Prob. 8J.5ECh. 8 - Prob. 8J.6ECh. 8 - Prob. 8J.7ECh. 8 - Prob. 8J.8ECh. 8 - Prob. 8.3ECh. 8 - Prob. 8.4ECh. 8 - Prob. 8.5ECh. 8 - Prob. 8.6ECh. 8 - Prob. 8.7ECh. 8 - Prob. 8.8ECh. 8 - Prob. 8.9ECh. 8 - Prob. 8.11ECh. 8 - Prob. 8.12ECh. 8 - Prob. 8.13ECh. 8 - Prob. 8.14ECh. 8 - Prob. 8.15ECh. 8 - Prob. 8.17ECh. 8 - Prob. 8.18ECh. 8 - Prob. 8.19ECh. 8 - Prob. 8.20ECh. 8 - Prob. 8.21ECh. 8 - Prob. 8.22ECh. 8 - Prob. 8.25ECh. 8 - Prob. 8.29ECh. 8 - Prob. 8.31CE
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- (a) Construct a molecular orbital energy diagram of N₂. (b) Use this diagram to explain why the first ionization of N₂ is greater than that of N. (b) Use this diagram to predict which is more favorable: the first electron affinity of N₂ or that of N.arrow_forward(a) Why do stable xenon fluorides have an even number of F atoms? (b) Why do the ionic species XeF₃⁺ and XeF₇⁻ have odd numbers of F atoms? (c) Predict the shape of XeF₃⁺ .arrow_forward(a) Draw the best Lewis structure(s) for the nitrite ion, NO2-.(b) With what allotrope of oxygen is it isoelectronic?(c) What would you predict for the lengths of the bondsin NO2- relative to N¬O single bonds and doublebonds?arrow_forward
- Describe the molecular shape of the following: (a) NCl2+arrow_forwardCompounds such as NaBH4, Al(BH4)3, and LiAlH4 are complex hydrides used as reducing agents in many syntheses. (a) Give the oxidation state of each element in these compounds. (b) Write a Lewis structure for the polyatomic anion in NaBH4, and predict its shape.arrow_forward(a) Draw the shape of the atomic valence orbitals formed by the overlaping of two fluoride 2p atomic orbitals. (b) Draw the molecular orbital diagrams for F2 and F2+. Identify their bond order and magnetic properties.arrow_forward
- Predict the electron pair geometry and the molecular structure of each of the following molecules or ions:(a) SF6(b) PCl5(c) BeH2(d) CH3+arrow_forwardDescribe the molecular structure around the indicated atom or atoms:(a) the sulfur atom in sulfuric acid, H2SO4 [(HO)2SO2](b) the chlorine atom in chloric acid, HClO3 [HOClO2](c) the oxygen atom in hydrogen peroxide, HOOH(d) the nitrogen atom in nitric acid, HNO3 [HONO2](e) the oxygen atom in the OH group in nitric acid, HNO3 [HONO2](f) the central oxygen atom in the ozone molecule, O3(g) each of the carbon atoms in propyne, CH3CCH(h) the carbon atom in Freon, CCl2F2(i) each of the carbon atoms in allene, H2CCCH2arrow_forwardThe species CO, CN-, and C22- are isoelectronic.(a) Draw their Lewis structures.(b) Draw their MO diagrams (assume 2s-2p mixing, as in N2), and give the bond order and electron configuration for each.arrow_forward
- Chlorine dioxide gas (ClO2) is used as a commercial bleachingagent. It bleaches materials by oxidizing them. In thecourse of these reactions, the ClO2 is itself reduced. (a)What is the Lewis structure for ClO2? (b) Why do you thinkthat ClO2 is reduced so readily? (c) When a ClO2 moleculegains an electron, the chlorite ion, ClO2-, forms. Draw theLewis structure for ClO2-. (d) Predict the O—Cl—O bondangle in the ClO2- ion. (e) One method of preparing ClO2is by the reaction of chlorine and sodium chlorite:Cl2(g) + 2 NaClO2(s)------>2 ClO2(g) + 2 NaCl(s)If you allow 15.0 g of NaClO2 to react with 2.00 L of chlorinegas at a pressure of 1.50 atm at 21 °C, how many gramsof ClO2 can be prepared?arrow_forwardConsider the SCl2 molecule. (a) What is the electron configuration of an isolated S atom? (b) What is the electron configuration of an isolated Cl atom? (c) What hybrid orbitals should be constructed on the S atom to make the S-Cl bonds in SCl2 ? (d) What valence orbitals if any, remain unhybridized on the S atom in SCL2 ?arrow_forward. For each of the following, draw the Lewis structure, predict the ONO bond angle, and give the hybridization of the nitrogen. You may wish to review the chapters on chemical bonding and advanced theories of covalent bonding for relevant examples. (a) NO2 (b) NO-2arrow_forward
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