Physical Chemistry
3rd Edition
ISBN: 9780321812001
Author: ENGEL, Thomas/ Reid
Publisher: Pearson College Div
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Question
Chapter 8, Problem 8.14NP
Interpretation Introduction
Interpretation:The maximum pressure at which the freeze drying can be carried out needs to be determined.
Concept introduction:
Freeze drying is a low temperature dehydration process that freezes the product by lowering the pressure then removes the ice through sublimation.
Sublimation is the process by which solid changes into gas phase without passing through the intermediate liquid state.
The Clausius-Clapeyron Equation is represented as follows:
Here, P is pressure, R is Universal gas constant, T is temperature and
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Physical Chemistry
Ch. 8 - Prob. 8.1CPCh. 8 - Prob. 8.2CPCh. 8 - Prob. 8.3CPCh. 8 - Prob. 8.4CPCh. 8 - Prob. 8.5CPCh. 8 - Prob. 8.6CPCh. 8 - Prob. 8.7CPCh. 8 - Prob. 8.8CPCh. 8 - Prob. 8.9CPCh. 8 - Prob. 8.10CP
Ch. 8 - Prob. 8.11CPCh. 8 - Prob. 8.12CPCh. 8 - Prob. 8.13CPCh. 8 - Prob. 8.14CPCh. 8 - Prob. 8.15CPCh. 8 - Prob. 8.16CPCh. 8 - Prob. 8.17CPCh. 8 - Prob. 8.18CPCh. 8 - Prob. 8.19CPCh. 8 - Prob. 8.20CPCh. 8 - Prob. 8.21CPCh. 8 - Prob. 8.1NPCh. 8 - Prob. 8.2NPCh. 8 - Prob. 8.3NPCh. 8 - Prob. 8.4NPCh. 8 - Prob. 8.5NPCh. 8 - Prob. 8.6NPCh. 8 - Prob. 8.7NPCh. 8 - Prob. 8.8NPCh. 8 - Prob. 8.9NPCh. 8 - Prob. 8.10NPCh. 8 - Prob. 8.11NPCh. 8 - Prob. 8.12NPCh. 8 - Prob. 8.13NPCh. 8 - Prob. 8.14NPCh. 8 - Prob. 8.15NPCh. 8 - Prob. 8.16NPCh. 8 - Prob. 8.17NPCh. 8 - Prob. 8.18NPCh. 8 - Prob. 8.20NPCh. 8 - Prob. 8.21NPCh. 8 - Prob. 8.22NPCh. 8 - Prob. 8.23NPCh. 8 - Prob. 8.24NPCh. 8 - Prob. 8.25NPCh. 8 - Prob. 8.26NPCh. 8 - Prob. 8.27NPCh. 8 - Prob. 8.28NPCh. 8 - Prob. 8.29NPCh. 8 - Prob. 8.30NPCh. 8 - Prob. 8.31NPCh. 8 - Prob. 8.32NPCh. 8 - Prob. 8.33NPCh. 8 - Prob. 8.34NPCh. 8 - Prob. 8.35NPCh. 8 - Prob. 8.36NPCh. 8 - Prob. 8.37NPCh. 8 - Prob. 8.38NPCh. 8 - Prob. 8.39NPCh. 8 - Prob. 8.40NPCh. 8 - Prob. 8.41NPCh. 8 - Prob. 8.42NPCh. 8 - Prob. 8.43NPCh. 8 - Prob. 8.44NPCh. 8 - Prob. 8.45NP
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