Fluid Mechanics
Fluid Mechanics
8th Edition
ISBN: 9780073398273
Author: Frank M. White
Publisher: McGraw-Hill Education
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Chapter 8, Problem 8.101P
To determine

(a)

Terminal velocity.

Expert Solution
Check Mark

Answer to Problem 8.101P

The required value of the terminal velocity is 1.95m/s.

Explanation of Solution

Given Information:

SG=7.85D=2cmT=20oCCD=0.47

Formula used:

(m+mh)dVdt=WnetCDρ2V2A

A=π4D2

Wnet=(ρsteelρwater)gπ6D3

Vf=2WnetCDρA

Calculation:

To solve this problem, for water we are taking the value of ρ=998kg/m3.

We know the hydrodynamic mass to the differential equation, (m+mh)dVdt=WnetCDρ2V2A ;

And the area of the sphere is, A=π4D2 ;

And, Wnet=(ρsteelρwater)gπ6D3 ;

Now separate the variables and integrate;

V=2WnetCDρAtanh(t W net C DρA2 (m+ m h ) 2)

Since the terminal velocity is the coefficient of the tanh functions in the previous equation;

Hence, Vf=2WnetCDρA ;

Put the values in the above equation;

Vf=2(7850998)(9.81)(π/6)( 0.02)3(0.47)(998)(π/4)( 0.02)2

1.95m/s.

To determine

(b)

Time to reach 99 percent of terminal velocity and examine the result.

Expert Solution
Check Mark

Answer to Problem 8.101P

The required value of the time is 0.642s

The value of the time that we have got is 6% than when mh=0.

Explanation of Solution

Given information:

SG=7.85D=2cmT=20oCCD=0.47Vterminal=1.95m/st99%=0.605s

Formula used:

tWnetCDρA2( m+mh )2=2.647

Calculation:

We have note that, (2.647)=0.99, we find the time to approach 99% of Vf to be;

tWnetCDρA2( m+mh )2=2.647

Put the values in the above equation;

t(7834998)(9.81)(π/6)( 0.02)3(0.47)(998)(π/4)( 0.02)22[ ( 7834+998/2 )( π/6 ) ( 0.02) 3 ]2=4.122t

t=2.647/4.1220.642s

Which is 6% than when mh=0.

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Chapter 8 Solutions

Fluid Mechanics

Ch. 8 - Prob. 8.11PCh. 8 - Prob. 8.12PCh. 8 - P8.13 Starting at the stagnation point in Fig....Ch. 8 - P8.14 A tornado may be modeled as the circulating...Ch. 8 - Hurricane Sandy, which hit the New Jersey coast on...Ch. 8 - Prob. 8.16PCh. 8 - P8.17 Find the position (x, y) on the upper...Ch. 8 - Prob. 8.18PCh. 8 - Prob. 8.19PCh. 8 - Plot the streamlines of the flow due to a line...Ch. 8 - P8.21 At point A in Fig. P8.21 is a clockwise line...Ch. 8 - P8.22 Consider inviscid stagnation flow, (see...Ch. 8 - P8.23 Sources of strength m = 10 m2/s are placed...Ch. 8 - P8.24 Line sources of equal strength m = Ua, where...Ch. 8 - Prob. 8.25PCh. 8 - Prob. 8.26PCh. 8 - Prob. 8.27PCh. 8 - Sources of equal strength m are placed at the four...Ch. 8 - Prob. 8.29PCh. 8 - Prob. 8.30PCh. 8 - A Rankine half-body is formed as shown in Fig....Ch. 8 - Prob. 8.32PCh. 8 - P8.33 Sketch the streamlines, especially the body...Ch. 8 - Prob. 8.34PCh. 8 - Prob. 8.35PCh. 8 - Prob. 8.36PCh. 8 - Prob. 8.37PCh. 8 - Consider potential flow of a uniform stream in the...Ch. 8 - A large Rankine oval, with a = 1 m and h = 1 m, is...Ch. 8 - Prob. 8.40PCh. 8 - Prob. 8.41PCh. 8 - Prob. 8.42PCh. 8 - P8.43 Water at 20°C flows past a 1-rn-diameter...Ch. 8 - Prob. 8.44PCh. 8 - Prob. 8.45PCh. 8 - P8.46 A cylinder is formed by bolting two...Ch. 8 - Prob. 8.47PCh. 8 - Prob. 8.48PCh. 8 - Prob. 8.49PCh. 8 - It is desired to simulate flow past a...Ch. 8 - Prob. 8.51PCh. 8 - P8.52 The Flettner rotor sailboat in Fig. E8.3...Ch. 8 - P8.52 The Flettner rotor sailboat in Fig. E8.3 has...Ch. 8 - Prob. 8.54PCh. 8 - Prob. 8.55PCh. 8 - Prob. 8.56PCh. 8 - Prob. 8.57PCh. 8 - Prob. 8.58PCh. 8 - Prob. 8.59PCh. 8 - Prob. 8.60PCh. 8 - Prob. 8.61PCh. 8 - Prob. 8.62PCh. 8 - The superposition in Prob. P8.62 leads to...Ch. 8 - Consider the polar-coordinate stream function...Ch. 8 - Prob. 8.65PCh. 8 - Prob. 8.66PCh. 8 - Prob. 8.67PCh. 8 - Prob. 8.68PCh. 8 - Prob. 8.69PCh. 8 - Prob. 8.70PCh. 8 - Prob. 8.71PCh. 8 - Prob. 8.72PCh. 8 - Prob. 8.73PCh. 8 - Prob. 8.74PCh. 8 - Prob. 8.75PCh. 8 - Prob. 8.76PCh. 8 - Prob. 8.77PCh. 8 - Prob. 8.78PCh. 8 - Prob. 8.79PCh. 8 - Prob. 8.80PCh. 8 - Prob. 8.81PCh. 8 - Prob. 8.82PCh. 8 - Prob. 8.83PCh. 8 - Prob. 8.84PCh. 8 - Prob. 8.85PCh. 8 - Prob. 8.86PCh. 8 - Prob. 8.87PCh. 8 - Prob. 8.88PCh. 8 - Prob. 8.89PCh. 8 - NASA is developing a swing-wing airplane called...Ch. 8 - Prob. 8.91PCh. 8 - Prob. 8.92PCh. 8 - Prob. 8.93PCh. 8 - Prob. 8.94PCh. 8 - Prob. 8.95PCh. 8 - Prob. 8.96PCh. 8 - Prob. 8.97PCh. 8 - Prob. 8.98PCh. 8 - Prob. 8.99PCh. 8 - Prob. 8.100PCh. 8 - Prob. 8.101PCh. 8 - Prob. 8.102PCh. 8 - Prob. 8.103PCh. 8 - Prob. 8.104PCh. 8 - Prob. 8.105PCh. 8 - Prob. 8.106PCh. 8 - Prob. 8.107PCh. 8 - P8.108 Consider two-dimensional potential flow...Ch. 8 - Prob. 8.109PCh. 8 - Prob. 8.110PCh. 8 - Prob. 8.111PCh. 8 - Prob. 8.112PCh. 8 - Prob. 8.113PCh. 8 - Prob. 8.114PCh. 8 - Prob. 8.115PCh. 8 - Prob. 8.1WPCh. 8 - Prob. 8.2WPCh. 8 - Prob. 8.3WPCh. 8 - Prob. 8.4WPCh. 8 - Prob. 8.5WPCh. 8 - Prob. 8.6WPCh. 8 - Prob. 8.7WPCh. 8 - Prob. 8.1CPCh. 8 - Prob. 8.2CPCh. 8 - Prob. 8.3CPCh. 8 - Prob. 8.4CPCh. 8 - Prob. 8.5CPCh. 8 - Prob. 8.6CPCh. 8 - Prob. 8.7CPCh. 8 - Prob. 8.1DPCh. 8 - Prob. 8.2DPCh. 8 - Prob. 8.3DP
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