Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 8, Problem 20P
Interpretation Introduction
Interpretation:
The values of
Concept introduction:
When any reaction is at equilibrium then a constant expresses a relationship between the reactant side and the product side. This constant is known as equilibrium constant. It is denoted by
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G6P(ag)
F6P(aq)
AG°=+1.7kJ/mol at 25 °C
Consider the reaction:
Estimate the fraction of F6P (Fructose 6 Phosphate) in equilibrium with G6P
(Glucose 6 Phosphate) at 25 °C, where the fraction is defined as
[F6P]/([F6P]+[G6P]). Show ALL your work.
Enzyme X exhibits maximum activity at pH = 6.3. X shows a fairly sharp decrease in its activity when the pH goes much lower than 5.8. One likely interpretation of this pH activity is that:
a Glu residue on the enzyme is involved in the reaction.
a Tyr residue on the enzyme is involved in the reaction.
a His residue on the enzyme is involved in the reaction
the enzyme uses NADH has a cofactor.
the enzyme uses coenzyme A has a cofactor.
Consider a general reaction
enzyme
A(aq)
B(aq)
The AGo of the reaction is -9.150 kJ mol-. Calculate the equilibrium constant for the reaction at 25 °C.
Keg =
What is AG for the reaction at body temperature (37.0 °C) if the concentration of A is 1.9 M and the concentration of B is
0.50 M?
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6/14/2021
Chapter 8 Solutions
Biochemistry
Ch. 8 - Prob. 1PCh. 8 - Prob. 2PCh. 8 - Prob. 3PCh. 8 - Prob. 4PCh. 8 - Prob. 5PCh. 8 - Prob. 6PCh. 8 - Prob. 7PCh. 8 - Prob. 8PCh. 8 - Prob. 9PCh. 8 - Prob. 10P
Ch. 8 - Prob. 11PCh. 8 - Prob. 12PCh. 8 - Prob. 13PCh. 8 - Prob. 14PCh. 8 - Prob. 15PCh. 8 - Prob. 16PCh. 8 - Prob. 17PCh. 8 - Prob. 18PCh. 8 - Prob. 19PCh. 8 - Prob. 20PCh. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - Prob. 26PCh. 8 - Prob. 27PCh. 8 - Prob. 28PCh. 8 - Prob. 29PCh. 8 - Prob. 30PCh. 8 - Prob. 31PCh. 8 - Prob. 32PCh. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Prob. 35PCh. 8 - Prob. 36PCh. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - Prob. 39PCh. 8 - Prob. 40PCh. 8 - Prob. 41PCh. 8 - Prob. 42PCh. 8 - Prob. 43PCh. 8 - Prob. 44PCh. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - Prob. 47PCh. 8 - Prob. 48PCh. 8 - Prob. 49P
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Similar questions
- fructose-6-phosphate + ATP fructose-1,6- biphosphate + ADP AG° = 30.5 and 16.3 respectively Standard Free Energy change: -14.2 kj/mol ATP: 3mM, ADP: 0.4mM, fructose-1,6-biphosphate: 7mM %3D At what concentration of fructose-1,6-biphosphate would the reaction proceed backwards at 35°C?arrow_forward13. Calculate the equilibrium constant K'eg, for each of the following reactions at pH 7.0 and 25°C. glucose + Pi a. Glucose 6-phosphate + H20 enz. Glucose 6-phosphatase; AG'O=-13.8kJ/molarrow_forwardHelp me pleasearrow_forward
- - The phosphate transfer potentials for glucose-1-phosphate and glucose- 6-phosphate are 20.9 kJ/mol and 13.8 kJ/mol, respectively. (a) What is the equilibrium constant for the reaction shown below at 25 °C? CH,OH CH,OPO,2- H H H H OH H ОН Н 6-PO,2- HO OH н он Glucose-6-phosphate H OH Glucose-1-phosphate (b) If a mixture was prepared containing 1 M glucose-6-phosphate and 1 x 10M glucose-1-phosphate, what would be the thermodynami- cally favored direction for the reaction? 1arrow_forwardConsider the following equilibrium at 25ºC :Glucose-1-Phosphate Glucose-6-PhophateUsing the equilibrium concentrations of [Glucose-1-Phosphate] = 0.35 M and [Glucose-6-Phosphate] = 1.65 M, calculate BOTH K′eqand Gº′ for this reaction. Is this reaction exergonicor endergonic? R = 8.314 J/K·molarrow_forwardSelect the incorrect statement. With regards to free energy ΔG of the reaction below E+S ⇌ ES Negative ΔG mean the reaction toward is facourable More negative value of ΔG indicates stronger binding to S to E It is possible to compute disassociation constant from the ΔG value alone It is possible to calculate the term ( ΔH – T ΔS) from the value of ΔGalone ΔG = 0 indicates (ES)/(E)(S) =1 None of the abovearrow_forward
- Calculate the equilibrium concentration of H2O for the following esterification reaction performed in ethanol(C2H5OH) C2H5OH + CH3CO2H ⇌CH3CO2C2H5 + H2O KC= 4.0 At equilibrium: [CH3CO2H] = 0.75 M; [CH3CO2C2H5 ]= 2.2 Marrow_forwardThe ΔG°' for hydrolysis of ATP to ADP + Pi is -30.5 kJ/mol. -Calculate the equilibrium constant for this reaction (show your work) Is this reaction at equilibrium in the cell? why?arrow_forwardCarbonic anhydrase catalyzes the hydration of CO. CO2 + H2O ¬ H½CO3 The Km of this enzyme for CO, is 1.20×104 µ.M. When [CO,] = 3.60×104 µM, the rate of reaction was 4.50 umol·mL! sec-1 a What is Vmax for this enzyme? umol·mL-!sec-!arrow_forward
- ver is given. A +B C+ D 1) Calculate AG for the above react un and indicáte whether the reaction is favorable or unfavorable [A] = 0.9 M 20°C AG° = 4 KJ/mol %3D [B] = 15mM [C] = 4mM [D] = 3 M R= 8.314 J/moleK %3D %3D 4.7 and explain how you know.arrow_forwardBased on the definition of kcat, substitute a value that can be measured and yet still represents the value associated with the original concentration of the R. What would the rate or velocity of the reaction be equal to under these circumstances? How can cells increase Vmax? What variable that we could change would directly impact Vmax? Would the value of KM be affected by the ways you determined that Vma,x could be increased? What does this indicate about KM? Thinking about how catalysts work, about the Michaelis-Menten Equation, and the definition of kcat, what specifically does the enzyme change in the reaction mechanism to increase the rate? If an enzyme follows the 2 step mechanism proposed by Michaelis-Menten, what do you know about this enzyme? Be very specific and comprehensive. Please answer very soon will give rating surelyarrow_forwardAssume that in a certain cell, the ratio of products/reactants or Keg = 809.5 (Keq is dimensionless) for the reaction Glucose + 2ATP > Glucose-1,6-diP + 2ADP, at a particular instant, the concentrations of each compound were Glucose =2.4M, ATP =11.1M, ADP -12.8M and G-6-P -28.4M. Calculate the difference (dimensionless) between Keq and the ratio of products/ractants at this instance, in this cell, to five decimal placesarrow_forward
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