(a)
Interpretation:
The mechanism for the addition of a proton from trifluoromethanesulfonic acid to the
Concept introduction:
Carbon-carbon double and triple bonds are electron-rich. They can undergo heterolytic bond breaking. The pi bond can break, and the electron pair can be used to form a bond with an electrophile such as a proton. The electrophile bonds to one of the carbon atoms. The other carbon atom gets a 1+ charge and is called a carbocation. The reaction mechanism is drawn by showing the movement of electron pairs with curved arrows. The curved arrow starts from an electron-rich atom or center of an electron-rich region (a pi bond) and ends on an electron-poor atom, an electrophile, to show the formation of a new sigma bond. If a pi bond is formed, the arrow must end in the region between the corresponding atoms.
(b)
Interpretation:
It is to be determined which of the two carbocations formed on the addition of a proton to the given alkyne is more stable.
Concept introduction:
Carbocations are positively charged carbon atoms that are electron poor. The carbon is two electrons short of an octet. The charge and the incomplete octet make the carbocation an unstable species. The stability of a carbocation depends on the number of alkyl groups bonded to it and increases in the order
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Organic Chemistry: Principles and Mechanisms (Second Edition)
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- The pictured reaction shows an alkyl bromide being converted into an alkene. Choose all reagents that would produce the pictured alkene as the major product. A) NaOH/H2O B) H2O C) tBuOK/tBuOH D) EtONa/EtOHarrow_forwardThe following molecules are subject to substitution (SN1 or SN2) reaction conditions. a) Identify if the leaving group (-Br) is attached to a 3°, 2°, 1°, or methyl Carbon. b) Rank the molecule with respect to their SN1 reactivity, with 1 being the fastest and 4 being the slowest. c) Rank the molecule with respect to their SN2 reactivity, with 1 being the fastest and 4 being the slowest. Br Br CH3B Br a. type of Carbon on C-Br b. SN1 reactivity (1 fastest, 4 slowest) c. SN2 reactivity (1 fastest, 4 slowest)arrow_forward5. a) Determine the major product that is formed when the alkyl halide reacts with a hydroxide ion in an elimination reaction. CH,CH,CH,CH,CCH, Br b) For the major elimination product obtained in 5a), which stereoisonmer (cis or trans) is obtained in greater yield? Draw the two isomers and provide the names of the compounds.arrow_forward
- (a) Add curved arrows for each step to show how A is converted to the epoxy ketone C. (b) Classify the conversion of A to C as a substitution, elimination, or addition. (c) Draw one additional resonance structure for B.arrow_forwardDehydration of 1,2,2-trimethylcyclohexanol with H2SO4 affords 1-tertbutylcyclopentene as a minor product. (a) Draw a stepwise mechanismthat shows how this alkene is formed. (b) Draw other alkenes formed inthis dehydration. At least one must contain a five-membered ring.arrow_forwardDraw an energy diagram for each reaction in Problem 20.28, paying attention to the relative energies of the overall reactants, overall products, and any intermediates.arrow_forward
- Draw all of the substitution and elimination products formed from thegiven alkyl halide with each reagent: (a) CH3OH; (b) KOH. Indicate thestereochemistry around the stereogenic centers present in the products,as well as the mechanism by which each product is formed.arrow_forwardDraw a detailed, step-wise mechanism for the reaction shown below. SHOW ALL BOND-FORMING AND BOND-BREAKING STEPS. SHOW ALL INTERMEDIATES. 1) NaOH 2) H3O* H3C H3C HOarrow_forwardGive the product and mechanism for the following reaction. Be sure to include all mechanism arrows, lone pairs, and formal charges in your mechanism. The product is an alkene.arrow_forward