Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 7, Problem 5P
To determine
The scalar product for any two vectors
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As an illustration of why it matters which variables you hold fixed when taking partial derivatives, consider the following mathematical example. Let w = xy and x = yz.
Write w purely in terms of x and z, and then purely in terms of y and z.
Consider two vectors à = (1, – 3,0) and B = (0 ,0,7). Let C be their cross product: Č = à ×
В.
a) Calculate the Cartesian components of C.
b) What is the angle between vectors B and C?
In Lagrangian mechanics, the Lagrangian technique tells us that when dealing with
particles or rigid bodies that can be treated as particles, the Lagrangian can be defined
as:
L = T-V where T is the kinetic energy of the particle, and V the potential energy of the
particle. It is also advised to start with Cartesian coordinates when expressing the
kinetic energy and potential energy components of the Lagrangian
e.g. T = m (x² + y² + 2²). To express the kinetic energy and potential energy in
some other coordinate system requires a set of transformation equations.
3.1 Taking into consideration the information given above, show that the Lagrangian
for a pendulum of length 1, mass m, free to with angular displacement - i.e.
angle between the string and the perpendicular is given by:
3.2
4.1
4.1.1
4.1.2
4.1.3
4.1.4
4.2
L = T-V = ²² +mg | Cos
Write down the Lagrange equation for a single generalised coordinate q.
State name the number of generalised coordinates in problem 3.1.
Hence write…
Chapter 7 Solutions
Physics for Scientists and Engineers
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- In Lagrangian mechanics, the Lagrangian technique tells us that when dealing with particles or rigid bodies that can be treated as particles, the Lagrangian can be defined as: L = T-V where T is the kinetic energy of the particle, and V the potential energy of the particle. It is also advised to start with Cartesian coordinates when expressing the kinetic energy and potential energy components of the Lagrangian e.g. T = m (x² + y² + ²). To express the kinetic energy and potential energy in some other coordinate system requires a set of transformation equations. 3.1 Taking into consideration the information given above, show that the Lagrangian for a pendulum of length 1, mass m, free to with angular displacement - i.e. angle between the string and the perpendicular is given by: L=T-V = 1²0² + mg | Cos 0 3.2 Write down the Lagrange equation for a single generalised coordinate q. State name the number of generalised coordinates in problem 3.1. Hence write down the Lagrange equation of…arrow_forwardIn Lagrangian mechanics, the Lagrangian technique tells us that when dealing with particles or rigid bodies that can be treated as particles, the Lagrangian can be defined as: L = T-V where T is the kinetic energy of the particle, and V the potential energy of the particle. It is also advised to start with Cartesian coordinates when expressing the kinetic energy and potential energy components of the Lagrangian e.g. T = m (x² + y² + ż²). To express the kinetic energy and potential energy in some other coordinate system requires a set of transformation equations. 3.1 Taking into consideration the information given above, show that the Lagrangian for a pendulum of length 1, mass m, free to with angular displacement 0- i.e. angle between the string and the perpendicular is given by: L=T-V=1²0² + mg | Cosarrow_forwarda. Prove the triple product identity Ax(B×C)= B(A·C)-C(A·B). Begin by adopting a Cartesian coordinate system. Without loss of generality, you may orient your coordinate system such that the x axis is along B, so that B = Bi. You then have the freedom to place the y axis in the plane defined by B and C. (But wait- what happens if B and C point in the same direction, so that no such plane is defined?) Very Strong Hint: I did this in class. Look in the book!arrow_forward
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