Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 7, Problem 41Q
To determine
The diameter of Venus.
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Imagine you grew up on Mars, whose semi-major axis is 1.5 AU. In observing the planets over your lifetime from the Martian surface, what is the largest angular separation you would see between the Earth and the Sun? Take the orbits of the Earth and Mars to be circular.
Venus can be as bright as apparent magnitude −4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 7 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 ✕ 105 AU).
[fill in the blank] times fainter
What would its apparent magnitude be?
Venus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination
phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. ote: 1 pc = 2.1 x 10° AU).
times fainter
What would its apparent magnitude be?
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Chapter 7 Solutions
Universe: Stars And Galaxies
Ch. 7 - Prob. 1QCh. 7 - Prob. 2QCh. 7 - Prob. 3QCh. 7 - Prob. 4QCh. 7 - Prob. 5QCh. 7 - Prob. 6QCh. 7 - Prob. 7QCh. 7 - Prob. 8QCh. 7 - Prob. 9QCh. 7 - Prob. 10Q
Ch. 7 - Prob. 11QCh. 7 - Prob. 12QCh. 7 - Prob. 13QCh. 7 - Prob. 14QCh. 7 - Prob. 15QCh. 7 - Prob. 16QCh. 7 - Prob. 17QCh. 7 - Prob. 18QCh. 7 - Prob. 19QCh. 7 - Prob. 20QCh. 7 - Prob. 21QCh. 7 - Prob. 22QCh. 7 - Prob. 23QCh. 7 - Prob. 24QCh. 7 - Prob. 25QCh. 7 - Prob. 26QCh. 7 - Prob. 27QCh. 7 - Prob. 28QCh. 7 - Prob. 29QCh. 7 - Prob. 30QCh. 7 - Prob. 31QCh. 7 - Prob. 32QCh. 7 - Prob. 33QCh. 7 - Prob. 34QCh. 7 - Prob. 35QCh. 7 - Prob. 36QCh. 7 - Prob. 37QCh. 7 - Prob. 38QCh. 7 - Prob. 39QCh. 7 - Prob. 40QCh. 7 - Prob. 41Q
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- Estimate the distance between Venus and Earth in km and AU. Express your answer using two significant figures.arrow_forwardVenus can be as bright as apparent magnitude −4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 7 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 ✕ 105 AU). What would its apparent magnitude be?arrow_forwardI need help with this question! There is only one part to it!arrow_forward
- The chart shows the length of time for each planet, in Earth days, to make one complete revolution around the Sun. Orbital Period of Planets iY the Solar System Orbital Period (Earth days) 88 225 365 687 4333 10 759 30 685 60 189 Planet Mercury Venus Earth Mars Jupiter Satum Uranus Neptune Source: NASA Use the data table above to compare the length of a year on Mars and Neptune. (HS-ESS1-4) a. One year on Neptune is almost 100 times longer than a year on Mars. b. One year on these two planets is nearly equal. c. One year on Mars is almost 100 times longer than a year on Neptune. d. One year these two planets is roughly equal to a year on Earth. Use the data table above to determine which of the following statements is TRUE. (HS-ESS1-4) a. There is no relationship between a planet's distance from the Sun and its length of year. b. The closer a planet is to the Sun, the longer the planet's year. c. One year on all planets is about 365 days long. d. The farther away a planet is from the…arrow_forwardVenus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 x 105 AU). times fainter What would its apparent magnitude be?arrow_forwardNo handwrittenarrow_forward
- Venus can be as bright as apparent magnitude 4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 1 pc? What would its apparent magnitude be? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law, Section 9-2a; also, review the definition of apparent visual magnitudes, Chapter 2.) (Note: 1 pc = 2.1 105 AU.)arrow_forwardWhich is the phase of Venus when it is closest? Which when farthest? How do you know?arrow_forwardAgain using Appendix F, which planets might you expect to have extreme seasons? Whyarrow_forward
- Thinking about the Scale of the Solar System As we discussed, the radius of the Earth is approximately 6370 km. The Sun, on the other hand, is approximately 700,000 km in radius and located, on average, one astronomical unit (1 au=1.5x108 km) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis. You hold a standard desk globe, which has a diameter of 12 inches, and you want to build a model of the Sun, Earth, and their separation that keeps all sizes and lengths in proportion to one another. a) How big would the Sun be in this scale model? Give your answer in feet and meters. b) The nearest star to the Solar System outside of the Sun is Proxima Centauri, which is approximately 4.2 light years away (a light year is the distance light travels in one year, or approximately 9.5x1012 km). Given the scale model outlined above, how far would a model Proxima Centauri be placed from you? Give your answer in miles and km.arrow_forwardNeptune is an average distance of 4.5×10^9 km from the Sun. - How many astronomical units (AU) is Neptune from the Sun? One AU is 1.50×10^8 km. - Estimate the length of the Neptunian year using your answer from part (a).arrow_forwardUse the small-angle formula to calculate the angular diameter (in arc minutes) of Mars (d = 6.79 ✕ 103 km) as seen from Earth if Mars were at the location of the Sun (D = 1.5 ✕ 108 km).arrow_forward
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