Biology (MindTap Course List)
Biology (MindTap Course List)
11th Edition
ISBN: 9781337392938
Author: Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher: Cengage Learning
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Chapter 7, Problem 16TYU
Summary Introduction

To design: An experiment that will help to decide whether malonate is acting as a competitive inhibitor or a noncompetitive inhibitor.

Introduction: Enzymes are biological protein catalysts that alter the speed of the reaction in the biological system. The chemical reactions that are catalyzed by these enzymes are studied under enzyme kinetics. The reaction rate is measured based on the rate at which the substrate of the enzymes combines with the enzyme and forms the products.

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5. By using Excel or GoogleSheets. graph the Lineweaver-Burk plots for the behavior of an enzyme for which the following experimental data are available. What are the Km and Kwax values for the inhibited and uninhibited reactions? Is the inhibitor competitive or noncompetitive? [S] (mM) V, No Inhibitor (mmol min-) V, Inhibitor Present (mmol min-') 1 × 10-4 5 × 10-4 1.5 x 10-3 2.5 x 10-3 5 x 10-3 0.026 0.010 0.092 0.136 0.040 0.086 0.150 0.120 0.165 0.142
1. Substrates and reactive groups in an enzyme’s active site must be precisely aligned in order for a productive reaction to occur. Why, then, is some conformational flexibility also a requirement for catalysis?       2.  Some plants contain compounds that inhibit serine proteases. It has been hypothesized that these compounds protect the plant from proteolytic enzymes of insects and microorganisms that would damage the plant. Tofu, or bean curd, possesses these compounds. Manufacturers of tofu treat it to eliminate serine protease inhibitors. Why is this treatment necessary?
MAKE A GRAPH FOR ME ON GRAPH PAPER CALL IT ENZYMES VS RATE OF REACTION USING TABLE BELOW  GRAPH paper INSERTED BELOW rules: data points must be an x or circled dot, must be on grid paper , the independant variable on the x  axis and dependant variable on the y axis, must include titles Regarding the data points: - H2O2 + MnO2 Control #1: (Control #1, 5)- H2O2 + sand control #2: (Control #2, 0)- Plant versus Animal Liver Catalase: (Liver, 4)- Potato: Plant vs. Animal Catalase: (Potato, 3)- Substance Enzyme Concentration (Used Liver): (Liver Used, 4)- Substance Enzyme Concentration (Used H2O2): (Used H2O2, 1) - Boiling Water Bath Temperature: (Boiling Water Bath, 5)- Ice Water Bath Temperature: (Ice Water Bath, 2)- HCl, or pH 3: (H 3, 4)- NaOH at pH 12: (pH 12, 2)- pH 7 (H2O): (assuming average of pH readings; pH 7, not specified) The following explains how to display the graph: Title: Factors versus Enzyme Activity Rate - Labels on X- and Y-axes: Factors and Rate of Enzyme…
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Enzyme Kinetics; Author: MIT OpenCourseWare;https://www.youtube.com/watch?v=FXWZr3mscUo;License: Standard Youtube License