For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curl F ⋅ N over the given surface and the circulation integral around its boundary, assuming all boundaries are oriented clockwise as viewed from above. 330. F ( x , y , z ) = ( x + 2 z ) i + ( y − x ) j + ( z − y ) k ; S is a triangular region with vertices ( 3 , 0 , 0 ) , ( 0 , 3 / 2 , 0 ) , and ( 0 , 0 , 3 ) .
For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curl F ⋅ N over the given surface and the circulation integral around its boundary, assuming all boundaries are oriented clockwise as viewed from above. 330. F ( x , y , z ) = ( x + 2 z ) i + ( y − x ) j + ( z − y ) k ; S is a triangular region with vertices ( 3 , 0 , 0 ) , ( 0 , 3 / 2 , 0 ) , and ( 0 , 0 , 3 ) .
For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curl
F
⋅
N
over the given surface and the circulation integral around its boundary, assuming all boundaries are oriented clockwise as viewed from above.
330.
F
(
x
,
y
,
z
)
=
(
x
+
2
z
)
i
+
(
y
−
x
)
j
+
(
z
−
y
)
k
;
S
is a triangular region with vertices
(
3
,
0
,
0
)
,
(
0
,
3
/
2
,
0
)
, and
(
0
,
0
,
3
)
.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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