Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Textbook Question
Chapter 6.6, Problem 14P
For a reaction with
a) The reaction is exothermic.
b)
c)
d) the bonds in the starting material are stronger than the bonds in the product; and
e) the product is favored at equilibrium.
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2) The equilibrium constant Ke for the reaction A B is 1 x 105 at room temperature (25°C).
a) You make a solution containing compound A at a concentration of 1 M and compound B at a
concentration of 1 mM of B, and let the reaction proceed to equilibrium. What are the equilibrium
concentrations of A and B?
b) Calculate the standard free-energy change (AG) for this reaction.
c) What is the standard free-energy change (AG) for the inverse reaction (BA)?
For a reaction with ?H° = 40 kJ/mol, decide which of the following statements is (are) true. Correct any false statement to make it true. (a) The reaction is exothermic; (b) ?G° for the reaction is positive; (c) Keq is greater than 1; (d) the bonds in the starting materials are stronger than the bonds in the product; and (e) the product is favored at equilibrium.
Considering each of the following values and neglecting entropy, tell whether the starting material or product is favored at equilibrium:
(a) ΔHo = 80 kJ/mol;
(b) ΔHo = −40 kJ/mol.
Chapter 6 Solutions
Organic Chemistry (6th Edition)
Ch. 6.2 - Prob. 2PCh. 6.3 - Problem 6.3 By taking into account...Ch. 6.3 - Problem 6.4 Use curved arrows to show the movement...Ch. 6.3 - Problem 6.5 Follow the curved arrows and draw the...Ch. 6.4 - Prob. 6PCh. 6.4 - Problem 6.7 Use the values in Table 6.2 to...Ch. 6.4 - Prob. 8PCh. 6.5 - aWhich Keq corresponds to a negative value of G,...Ch. 6.5 - Given each of the following values, is the...Ch. 6.5 - Given each of the following values, is the...
Ch. 6.5 - The equilibrium constant for the conversion of the...Ch. 6.6 - Prob. 13PCh. 6.6 - For a reaction with H=40kJ/mol, decide which of...Ch. 6.6 - For a reaction with H=20kJ/mol, decide which of...Ch. 6.7 - Draw an energy diagram for a reaction in which the...Ch. 6.7 - Prob. 17PCh. 6.7 - Prob. 18PCh. 6.8 - Problem 6.19 Consider the following energy...Ch. 6.8 - Draw an energy diagram for a two-step reaction,...Ch. 6.9 - Which value if any corresponds to a faster...Ch. 6.9 - Prob. 22PCh. 6.9 - Problem 6.23 For each rate equation, what effect...Ch. 6.9 - Prob. 24PCh. 6.10 - Identify the catalyst in each equation. a....Ch. 6 - Draw the products of homolysis or heterolysis of...Ch. 6 - Explain why the bond dissociation energy for bond...Ch. 6 - Classify each transformation as substitution,...Ch. 6 - Prob. 29PCh. 6 - 6.31 (a) Add curved arrows for each step to show...Ch. 6 - Prob. 35PCh. 6 - 6.39. a. Which value corresponds to a negative...Ch. 6 - Prob. 40PCh. 6 - For which of the following reaction is S a...Ch. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - 6.44 Consider the following reaction: .
Use curved...Ch. 6 - Prob. 45PCh. 6 - 6.50 The conversion of acetyl chloride to methyl...Ch. 6 - Prob. 50PCh. 6 - Prob. 53P
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- Discuss the conditions needed to have a reaction with gaseous reagents and gaseous products so that The value of Kp increases with increasing temperature The value of ΔG° increases with increasing temperature The value of k increases with increasing temperature The conversion of one of the reagents increases with increasing pressurearrow_forwardWhich value (if any) corresponds to a faster reaction: (a) Ea = 40 kJ/mol or Ea = 4 kJ/mol; (b) a reaction temperature of 0 °C or a reaction temperature of 25 °C; (c) Keq = 10 or Keq = 100; (d) ΔH° = −10 kJ/mol or ΔH° = 10 kJ/mol?arrow_forwardWhich value (if any) corresponds to a faster reaction: (a) Ea = 40 kJ/mol or Ea = 4 kJ/mol;(b) a reaction temperature of 0 °C or a reaction temperature of 25 °C; (c) Keq = 10 or Keq = 100; (d) ΔHo = −10 kJ/mol or ΔHo = 10 kJ/mol?arrow_forward
- Given each of the following values, is the starting material or product favored at equilibrium?A.) Keq = 5.5b.) ΔGo = 40 kJ/molarrow_forwardWhich of the following describes the effect of raising the temperature of an exothermic reaction which has not yet reached equilibrium? The rate of reaction slows and less product is produced. The rate of reaction slows, but more product is produced. The rate of reaction speeds up, but less product is produced. The rate of reaction speeds up and more product is produced.arrow_forwardIn which reaction is carbon reduced? A) CO(g) + ½ O₂(g) → CO₂(g) B) CO₂(g) + H₂O(l) → H₂CO₃(aq) C) CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) D) C₂H₂(g) + H₂(g) → C₂H₄(g)arrow_forward
- 4. Ethylene reacts with bromine to produce 1,2,- dibromoethane. At equilibrium, the concentration of each compound were found to be: C₂H4 = 0.5M; Br₂ = 4M; C₂H4Br2 = 1.7M Calculate the value of the equilibrium constant.arrow_forwardGiven: 2MNO(s) + O2(g) → 2MnO2(s) ArH = –269.6 kJ · mol-1arrow_forwardThe ΔHac of nitrogen dioxide is -937.86 kJ/mole. The ΔHf of nitrogen dioxide is +33.2 kJ/mole. Propose a reasonable explanation for this differencearrow_forward
- In the reaction: 2A ⇆ B + 3C For the reaction, ΔH = -23 kcal/mol and Keq = 26 X 10 -26 Is the reaction exothermic or endothermic? Are products or reactants favored? Using Le Chatelier’s Principle, what happens to the equilibrium if the concentration of C is increased? Using Le Chatelier’s Principle, what happens to the equilibrium if the concentration of A is increased?arrow_forwardCalculate the value (calories) for the heat of reaction. NaOH(s) ─HCl→ Na+(aq) + Cl-(aq) + H2O(l) Useful Information: Volume of HCl: .055 LVolume of water: .045 LVolume total: .1 LMolarity of HCl: 2.12 MMass of NaOH: 4.00 gΔT for reaction C: 21.3°C Specific Heat Capacity of Sodium Chloride: .94 cal g^-1 C^-1arrow_forwardWhich of the following describes the effect of raising the temperature of an exothermic reaction which has not yet reached equilibrium? a The rate of reaction slows and less product is produced b The rate of reaction slows, but more product is produced c The rate of reaction speeds up, but less product is produced d The rate of reaction speeds up and more product is producedarrow_forward
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