Chapter 6.2, Problem 19PPS

To determine

To find: Values of x and y.

Answer to Problem 19PPS

No solution.

Explanation of Solution

Given information:

  $\begin{array}{l}3x+y=-5\\ 6x+2y=10\end{array}$

  $3x+y=-5$

  $y=-5-3x$ -----(1)

  $6x+2y=10$ ------(2)

Substitute the value of $y$ from equation-(1) in equation-(2)

We get

  $\begin{array}{l}y=-5-3x\\ 6x+2y=10\\ \Rightarrow 6x+2\left(-5-3x\right)=10\\ \Rightarrow 6x+2\left(-5\right)+2\left(-3x\right)=10\\ \Rightarrow 6x-10-6x=10\\ \Rightarrow -10=10\end{array}$

Which is not true

So there will be no solution.

As both the given equations are parallel lines they do not intersect each other.

  $3x+y=-5$

  $\begin{array}{l}6x+2y=10\\ \Rightarrow 2\left(3x+y\right)=10\\ \Rightarrow 3x+y=\frac{10}{2}\\ \Rightarrow 3x+y=5\end{array}$

Therefore, values of x and y are no solution.