Chapter 6.2, Problem 13PPS

To determine

To find: Values of x and y.

Answer to Problem 13PPS

  $\begin{array}{l}x=-1\\ y=0\end{array}$

Explanation of Solution

Given information:

  $\begin{array}{l}3x+4y=-3\\ x+2y=-1\end{array}$

  $3x+4y=-3$ ----(1)

  $x+2y=-1$

  $\Rightarrow x=-1-2y$ ------(2)

Substitute the value of $x$ from equation-(2) in equation-(1)

We get

  $\begin{array}{l}3x+4y=-3\\ \Rightarrow 3\left(-1-2y\right)+4y=-3\\ \Rightarrow 3\left(-1\right)-3\left(2y\right)+4y=-3\\ \Rightarrow -3-6y+4y=-3\\ \Rightarrow 6y-4y=-3+3\\ \Rightarrow 2y=0\\ \Rightarrow y=0\end{array}$

Substitute value of $y$ in equation-(2)

We get

  $\begin{array}{l}x=-1-2y\\ \Rightarrow x=-1-2\left(0\right)\\ \Rightarrow x=-1-0\\ \Rightarrow x=-1\end{array}$

Therefore, values of x and y are

  $\begin{array}{l}x=-1\\ y=0\end{array}$