Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
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Chapter 6, Problem 8STP
To determine

To Choose: the correct option.

Expert Solution & Answer
Check Mark

Answer to Problem 8STP

The option C. 0.80 A is the correct answer.

Explanation of Solution

Formula used:

Ohm’s law equation:

  I=VR

Where I is the current in a circuit in amperes, V is the voltage difference across the circuit in volts and R is the resistance of the circuit in ohms.

Calculation:

The given circuit is a parallel circuit as it has two branches through which current flows.

In a parallel circuit, the voltage difference is same in each branch.

Hence, voltage difference across the lightbulb B, V=12 V

Resistance of the bulb B, RB=15 Ω

Substitute the values of voltage difference and resistance in the ohm’s law equation:

  IB=VRBIB=12 V15 ΩIB=0.80 A

Conclusion:

The current through lightbulb B in the given circuit is 0.80 A_ . Hence, the option C. 0.80 A is the correct answer.

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