Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
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Chapter 6, Problem 46R
To determine

To calculate: the resistance of each circuit.

To graph the current versus the resistance of each circuit and describe the shape of the line obtained.

Expert Solution & Answer
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Answer to Problem 46R

The resistance of the circuits are

  RA=2.6 ΩRB=10 ΩRC=30 ΩRD=3.33 Ω

The current versus resistance of each circuit:

  Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education), Chapter 6, Problem 46R , additional homework tip  1

The graph shows that resistance decreases with increase in current.

Explanation of Solution

Given data:

The table:

  Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education), Chapter 6, Problem 46R , additional homework tip  2

Voltage difference across each circuit, V=6 V

Formula used:

Ohm’s law equation:

  I=VR

Where I is the current in a circuit in amperes, V is the voltage difference across the circuit in volts and R is the resistance of the circuit in ohms.

Calculation:

As per the problem,

From the given table, consider

  • Circuit A
  •   V=6 VIA=2.3 A

Substitute the values voltage difference and current in the rearranged ohm’s law equation to get resistance:

  IA=VRARA=VIARA=6 V2.3 A=2.6 Ω

  • Circuit B
  •   V=6 VIB=0.6 A

Substitute the values voltage difference and current in the rearranged ohm’s law equation to get resistance:

  RB=VIBRB=6 V0.6 A=10 Ω

  • Circuit C
  •   V=6 VIC=0.2 A

Substitute the values voltage difference and current in the rearranged ohm’s law equation to get resistance:

  RC=VICRC=6 V0.2 A=30 Ω

  • Circuit D
  •   V=6 VID=1.8 A

Substitute the values voltage difference and current in the rearranged ohm’s law equation to get resistance:

  RD=VIDRD=6 V1.8 A=3.33 Ω

Tabulate the resistance of each corresponding to the current in the circuit:

  Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education), Chapter 6, Problem 46R , additional homework tip  3

Graph the current versus resistance of each circuit:

  Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education), Chapter 6, Problem 46R , additional homework tip  4

The graph shows that resistance decreases with increase in current.

Conclusion:The resistance of the circuits are

  RA=2.6 ΩRB=10 ΩRC=30 ΩRD=3.33 Ω

The current versus resistance for each circuit graph shows that resistance decreases with increase in current.

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