The infrared spectrum for methanol. CH 3 OH, is illustrated below. It shows the amount of light in the infrared region that methanol transmits as a function of wavelength. The vertical axis is the amount of light transmitted. At points near the top of the graph, most of the incident light is being transmitted by the sample (or, conversely, little light is absorbed). Therefore, the ″peaks″ or ″bands″ that descend from the top indicate light absorbed; the longer the band, the more light is being absorbed. The horizontal scale is in units of ″wavenumbers,″ abbreviated cm −1 . The energy of light is given by Planck′s law as E = hc /λ; that is, E is proportional to 1/λ. Therefore, the horizontal scale is in units of 1/λ and reflects the energy of the light incident on the sample. (a) One point on the horizontal axis is marked as 2000 cm −1 . What is the wavelength of light at this point? (b) Which is the low energy end of this spectrum (left or right), and which is the high energy end? (c) The broad absorption at about 3300-3400 cm −1 indicates that infrared radiation is interacting with the OH group of the methanol molecule. The narrower absorptions around 2800-3000 cm −1 are for interactions with C—H bonds. Which interaction requires more energy, with O—H or with C—H?
The infrared spectrum for methanol. CH 3 OH, is illustrated below. It shows the amount of light in the infrared region that methanol transmits as a function of wavelength. The vertical axis is the amount of light transmitted. At points near the top of the graph, most of the incident light is being transmitted by the sample (or, conversely, little light is absorbed). Therefore, the ″peaks″ or ″bands″ that descend from the top indicate light absorbed; the longer the band, the more light is being absorbed. The horizontal scale is in units of ″wavenumbers,″ abbreviated cm −1 . The energy of light is given by Planck′s law as E = hc /λ; that is, E is proportional to 1/λ. Therefore, the horizontal scale is in units of 1/λ and reflects the energy of the light incident on the sample. (a) One point on the horizontal axis is marked as 2000 cm −1 . What is the wavelength of light at this point? (b) Which is the low energy end of this spectrum (left or right), and which is the high energy end? (c) The broad absorption at about 3300-3400 cm −1 indicates that infrared radiation is interacting with the OH group of the methanol molecule. The narrower absorptions around 2800-3000 cm −1 are for interactions with C—H bonds. Which interaction requires more energy, with O—H or with C—H?
The infrared spectrum for methanol. CH3OH, is illustrated below. It shows the amount of light in the infrared region that methanol transmits as a function of wavelength. The vertical axis is the amount of light transmitted. At points near the top of the graph, most of the incident light is being transmitted by the sample (or, conversely, little light is absorbed). Therefore, the ″peaks″ or ″bands″ that descend from the top indicate light absorbed; the longer the band, the more light is being absorbed. The horizontal scale is in units of ″wavenumbers,″ abbreviated cm−1. The energy of light is given by Planck′s law as E = hc/λ; that is, E is proportional to 1/λ. Therefore, the horizontal scale is in units of 1/λ and reflects the energy of the light incident on the sample.
(a) One point on the horizontal axis is marked as 2000 cm−1. What is the wavelength of light at this point?
(b) Which is the low energy end of this spectrum (left or right), and which is the high energy end?
(c) The broad absorption at about 3300-3400 cm−1 indicates that infrared radiation is interacting with the OH group of the methanol molecule. The narrower absorptions around 2800-3000 cm−1 are for interactions with C—H bonds. Which interaction requires more energy, with O—H or with C—H?
this is an organic chemistry question please answer accordindly!!
please post the solution in your hand writing not an AI generated answer please draw the figures and structures if needed to support your explanation hand drawn only!!!! answer the question in a very simple and straight forward manner thanks!!!!!
im reposting this please solve all parts and draw it not just word explanations!!
2B: The retrosynthetic cut below provides two options for a Suzuki coupling, provide the identities of A, B,
C and D then identify which pairing is better and justify your choice.
O₂N.
Retro-Suzuki
NO2
MeO
OMe
A
+
B
OR
C
+
D
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell