Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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4. Consider only the four following quantum levels for the H atoms (n = 4, n = 3, n = 2, and
n = 1). The emission spectrum of an excited H atom will consist of transitions between these
levels.
(a) How many emission lines are possible, considering only the four quantum levels above?
(b) Photons of the highest energy will be emitted in a transition from the level with
n = to the level with n = _______
(c) The emission line having the longest wavelength corresponds to a transition from the
level with n=
to the level with n =
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Transcribed Image Text:4. Consider only the four following quantum levels for the H atoms (n = 4, n = 3, n = 2, and n = 1). The emission spectrum of an excited H atom will consist of transitions between these levels. (a) How many emission lines are possible, considering only the four quantum levels above? (b) Photons of the highest energy will be emitted in a transition from the level with n = to the level with n = _______ (c) The emission line having the longest wavelength corresponds to a transition from the level with n= to the level with n =
Expert Solution
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Step 1: Important relation required to solve the problem

Answer:

According to Bohr's model energy of any level n in hydrogen atom is:

straight E subscript straight n equals negative fraction numerator 2.18 cross times 10 to the power of negative 18 end exponent over denominator straight n squared end fraction straight J

Energy of photon:

straight E subscript photon equals hc over straight lambda

Here: h and c are constants and lambda is the wavelength of photon.

Formula for the calculation of total spectral lines:

Total space spectral space lines equals fraction numerator straight n left parenthesis straight n minus 1 right parenthesis over denominator 2 end fraction

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