Explanation Given: Pressure of feedwater ( P 1 ) is 1000 kPa . Temperature of feedwater ( T 1 ) is 50 ° C . Pressure of superheated steam ( P 2 ) is 1000 kPa . Temperature of superheated steam ( T 2 ) is 200 ° C . Pressure of mixing chamber ( P 3 ) is 1000 kPa . Calculation: Refer Table A-4, “Saturated water-Temperature table”, obtain the enthalpy of feedwater at the temperatures of 50 ° C . h 1 = h f @ 5 0 ° C = 209.34 kJ / kg Refer Table A-5, “Saturated water-Pressure table”, obtain the enthalpy of mixture at the pressure of 1000 kPa . h 3 = h f @ 1000 kPa = 762.51 kJ / kg Refer Table A-6, “Superheated water”, obtain the enthalpy of superheated steam at the temperature of 200 ° C and pressure of 1000 kPa . h 2 = 2828.3 kJ / kg Here, the hot and cold streams of water are mixed in a rigid mixing chamber and operates at steady state. Hence, the inlet and exit mass flow rates are equal. m ˙ 1 + m ˙ 2 = m ˙ 3 Calculate the ratio of the mass flow rates of the feedwater and the superheated vapor ( m ˙ 1 / m ˙ 2 ) using the steady-flow energy balance equation

5th Edition

ISBN: 9780078027680

Author: Yunus A. Cengel Dr., Robert H. Turner, John M. Cimbala

Publisher: McGraw-Hill Education

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Chapter 6, Problem 65P

To determine

The ratio of the mass flow rates of the feedwater and the superheated vapor.

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Fundamentals of Thermal-Fluid Sciences

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