Explanation Given: Pressure ( P ) is 900 kPa . Initial temperature ( T 1 ) is 1200 K . Final temperature ( T 2 ) is 800 K . Gas constant ( R ) is 0.30 kJ/kg ⋅ K Work output ( W ˙ o u t ) is 650 kW . Specific heat at constant pressure ( c p ) is 1.13 kJ/kg ⋅ K . Conclusion: Consider the system is in steady state. Hence, the inlet and exit mass flow rates are equal. The mass flow rate is as follows. m ˙ 1 = m ˙ 2 = m ˙ Write the energy rate balance equation for one inlet and one outlet system. [ Q ˙ 1 + W ˙ 1 + m ˙ ( h 1 + V 1 2 2 + g z 1 ) ] − [ Q ˙ 2 + W ˙ 2 + m ˙ ( h 2 + V 2 2 2 + g z 2 ) ] = Δ E ˙ system The system is at steady state. Hence, the rate of change in net energy of the system becomes zero. Δ E ˙ system = 0 Neglect the heat transfer potential and kinetic energies. The turbine gives the work output. [ 0 + 0 + m ˙ ( h 1 + 0 + 0 ) ] − [ 0 + W ˙ out + m ˙ ( h 2 + 0 + 0 ) ] = 0 m ˙ h 1 − ( W ˙ out + m ˙

5th Edition

ISBN: 9780078027680

Author: Yunus A. Cengel Dr., Robert H. Turner, John M. Cimbala

Publisher: McGraw-Hill Education

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Chapter 6, Problem 140RQ

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The inlet volume flow rate of the gas at turbine.

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Chapter 6, Problem 139RQ

Chapter 6, Problem 141RQ

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Fundamentals of Thermal-Fluid Sciences

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