Chapter 6, Problem 6.27P

Interpretation Introduction

(a)

Interpretation:

The cross-sectional area of the hoist of a cable is 80mm². Crate of 500 kg is lifted by this hoist and the length of cable is 30 m. It is assumed that the deformation is elastic. The stress of cable is to be determined.

Concept Introduction:

Following formulas will be used for the calculation of stress of cable.

$\sigma (stress)=\frac{F}{A}$

And

$W=mg$

Interpretation Introduction

(b)

Interpretation:

The cross-sectional area of the hoist of a cable is 80mm². Crate of 500 kg is lifted by this hoist and the length of cable is 30 m. It is assumed that the deformation is elastic. Elongation of cable is to be determined considering that it is made from steel. And modulus of elasticity (E) is 200GPa.

Concept Introduction:

Concept of Hooke's law will be used. Hooke's law gives the following relation-

$\sigma =E\epsilon$

Interpretation Introduction

(c)

Interpretation:

The cross-sectional area of the hoist of a cable is 80mm². Crate of 500 kg is lifted by this hoist and the length of cable is 30 m. It is assumed that the deformation is elastic. Elongation of cable is to be determined considering that it is made from polypropylene. And modulus of elasticity (E) is 1.2GPa.

Concept Introduction:

Concept of Hooke's law will be used. Hooke's law gives the following relation-

$\sigma =E\epsilon$