Chapter 6, Problem 6.16P

Interpretation Introduction

Interpretation:

A force of 2500 N is applied on the material with the diameter of 8mm. The initial length of this material is 50mm after the elongation, the final length of this material is 50.15mm.Stress and strain of this material are to be determined.

Concept introduction:

Concept of stress and strain will be used for this calculation. The stress and strain are given by formula, respectively-

$\sigma =\frac{F}{A}$

$\epsilon =\frac{\Delta l}{l}$