(a)
Interpretation:
The diameter of nickel wire is 0.15 in and the yield and tensile strength is 45,000 psi and 55,000 psi respectively. A force of 850-lb is applied on this wire. In this case, the plastic deformation of wire is to be determined.
Concept Introduction:
In this concept of the engineering, stress will be used. The formula of engineering stress is given as-
(b)
Interpretation:
The diameter of nickel wire is 0.15 in and the yield and tensile strength is 45,000 psi and 55,000 psi respectively. A force of 850-lb is applied on this wire. In this case, the experience of necking by the wire is to be determined.
Concept Introduction:
In this concept of the engineering, stress will be used. The formula of engineering stress is given as-
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