Basics Of Engineering Economy
2nd Edition
ISBN: 9780073376356
Author: Leland Blank, Anthony Tarquin
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 6, Problem 37P
To determine
Selection of independent alternative on the basis of overall
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Street lighting fixtures and their sodium vapor bulbs for a two-block area of a large city need to be installed at a first
cost (investment cost) of $120,000. Annual maintenance expenses are expected to be $6,650 for the first 10 years
and $10,000 each year thereafter upto 25 years. With an interest rate of 10% per year, what is the present worth cost
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Choose the closest answer below.
OA. The present worth cost of the project is $251,632.
OB. The present worth cost of the project is $271,133.
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Choose the formula that you will use for the following case:
A major repair on the suspension system of a 5-year-old car cost $2000. The cost of
periodic maintenance has been $800 every 2 years. If the owner donates the car to charity
after 8 years of ownership, what is the quivalent annual cost of the repair and
maintenance in the 8-year period of ownership? Use an interest rate of 8% per year, and
assume that the owner paid the $800 maintenance cost immediately before donating the
car in year 8.
AW = -2000 (A/P, 8%, 8) - 800 (A/P, 8%, 2) - 800 (A/P,8%, 4) - 800 (A/P, 8%, 6) - 800 (A/P,8%, 8)
PW = -2000 (P/A, 8%, 8) - 800 (P/A, 8%, 2) - 800 (PIA, 8%, 4) - 800 (P/A, 8%, 6) - 800 (P/A, 8%, 8)
PW = -2000 (P/F, 8%, 8) - 800 (P/F, 8%, 2) - 800 (P/F, 8%, 4) - 800 (P/F, 8%, 6) - 800 (P/F, 8%, 8)
AW = -2000 (A/F, 8%, 8) - 800 (A/F, 8%, 2) - 800 (A/F,8%, 4) - 800 (A/F, 8%, 6) - 800 (A/F,8%, 8)
Identify the engineering economy symbols and their values. Use a question mark with the symbol whose value is to be determined.
Fifteen years ago your grandfather invested $18,000 in a stock fund to pay for your college education. Each year thereafter, he deposited $2,600 into the fund. If the investments grew at a rate of 8% per year over the 15 years, how much is in the fund now?
$18,000 = (Click to select) n A i F P
$2,600 = (Click to select) F i A n P
0.08 = (Click to select) P n i A F
15 = (Click to select) n P i A F
? = (Click to select) P n i A F
Chapter 6 Solutions
Basics Of Engineering Economy
Ch. 6 - Prob. 1PCh. 6 - Prob. 2PCh. 6 - Prob. 3PCh. 6 - Prob. 4PCh. 6 - Prob. 5PCh. 6 - Prob. 6PCh. 6 - Prob. 7PCh. 6 - Prob. 8PCh. 6 - A University of Massachusetts study found that...Ch. 6 - Prob. 10P
Ch. 6 - The Closing the Gaps initiative by the Texas...Ch. 6 - Prob. 12PCh. 6 - Prob. 13PCh. 6 - Prob. 14PCh. 6 - Prob. 15PCh. 6 - Prob. 16PCh. 6 - Prob. 17PCh. 6 - Prob. 18PCh. 6 - Prob. 19PCh. 6 - Prob. 20PCh. 6 - Prob. 21PCh. 6 - Prob. 22PCh. 6 - Prob. 23PCh. 6 - Prob. 24PCh. 6 - Prob. 25PCh. 6 - A company that manufactures rigid shaft couplings...Ch. 6 - For each of the following scenarios, state whether...Ch. 6 - Prob. 28PCh. 6 - Prob. 29PCh. 6 - Prob. 30PCh. 6 - Prob. 31PCh. 6 - Prob. 32PCh. 6 - Prob. 33PCh. 6 - Prob. 34PCh. 6 - Prob. 35PCh. 6 - The four alternatives described below are being...Ch. 6 - Prob. 37PCh. 6 - Prob. 38PCh. 6 - Ashley Foods, Inc. has determined that only one of...Ch. 6 - Five revenue projects are under consideration by...Ch. 6 - Four different machines are under consideration...Ch. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45PCh. 6 - Prob. 46PCh. 6 - Prob. 47PCh. 6 - Prob. 48PCh. 6 - Prob. 49PCh. 6 - Prob. 50PCh. 6 - Prob. 51PCh. 6 - Prob. 52PCh. 6 - Prob. 53PCh. 6 - Prob. 54PCh. 6 - Prob. 55PCh. 6 - Prob. 56PCh. 6 - Prob. 57PCh. 6 - Prob. 58PCh. 6 - Prob. 59PCh. 6 - Prob. 60APQCh. 6 - Prob. 61APQCh. 6 - Prob. 62APQCh. 6 - Prob. 63APQCh. 6 - Prob. 64APQCh. 6 - Prob. 65APQCh. 6 - Prob. 66APQCh. 6 - Prob. 67APQCh. 6 - Prob. 68APQCh. 6 - Prob. 69APQCh. 6 - Prob. 70APQ
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