Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN: 9781305079243
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Cengage Learning
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Chapter 6, Problem 124CP

a)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

a)

Expert Solution
Check Mark

Answer to Problem 124CP

Volume of stock solution is 10mL

Explanation of Solution

Record the given data

Mass of solute= 100ppm standard

Volume of stock solution= 1000ppm

The mass of the solute and volume of stock solution are recorded as shown above.

To calculate the volume of stock solution to make 100mLof100ppmsolution Cuinwater

100.µgCumL×100 mL=1×104µgCuneeded1×104µgCu×1mLstock1000µgCu=10mL ofstocksolution

Transfer 10mL of the 1000ppm stock solution to a 100mL volumetric flask, and dilute to the mark.

Requiredvolumestocksolutionis10mL

The volume of stock solution is calculated by plugging in the values of concentration of stock solution and mass of copper along with required volume of the solution. The volume of stock solution copper is 10mL .

b)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

b)

Expert Solution
Check Mark

Answer to Problem 124CP

Volume of stock solution is 7.5mL

Explanation of Solution

Record the given data

Mass of solute= 75ppm standard

Volume of stock solution= 1000ppm

The mass of the solute and volume of stock solution are recorded as shown above.

To calculate the volume of stock solution to make 100mLof75ppmsolution Cuinwater

75.µgCumL×100 mL=7.5×103µgCuneeded7.5×103µgCu×1mLstock1000µgCu=7.5mL ofstocksolution

Transfer 5mL of the 1000ppm stock solution to a 100mL volumetric flask, and dilute to the mark.

Requiredvolumestocksolutionis7.5mL

The volume of stock solution is calculated by plugging in the values of concentration of stock solution and mass of copper along with required volume of the solution. The volume of stock solution copper is 7.5mL .

c)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

c)

Expert Solution
Check Mark

Answer to Problem 124CP

Volume of stock solution is 5mL

Explanation of Solution

Record the given data

Mass of solute= 50ppm standard

Volume of stock solution= 1000ppm

The mass of the solute and volume of stock solution are recorded as shown above.

To calculate the volume of stock solution to make 100mLof50ppmsolution Cuinwater

50.µgCumL×100 mL=5×103µgCuneeded5×103µgCu×1mLstock1000µgCu=5mL ofstocksolution

Transfer 5mL of the 1000ppm stock solution to a 100mL volumetric flask, and dilute to the mark.

Requiredvolumestocksolutionis5mL

The volume of stock solution is calculated by plugging in the values of concentration of stock solution and mass of copper along with required volume of the solution. The volume of stock solution copper is 5mL .

d)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

d)

Expert Solution
Check Mark

Answer to Problem 124CP

Volume of stock solution is 2.5mL

Explanation of Solution

Record the given data

Mass of solute= 25ppm standard

Volume of stock solution= 1000ppm

The mass of the solute and volume of stock solution are recorded as shown above.

To calculate the volume of stock solution to make 100mLof25ppmsolution Cuinwater

25.µgCumL×100 mL=2.5×103µgCuneeded2.5×103µgCu×1mLstock1000µgCu=2.5mL ofstocksolution

Transfer 2.5mL of the 1000ppm stock solution to a 100mL volumetric flask, and dilute to the mark.

Requiredvolumestocksolutionis2.5mL

The volume of stock solution is calculated by plugging in the values of concentration of stock solution and mass of copper along with required volume of the solution. The volume of stock solution copper is 2.5mL .

e)

Interpretation Introduction

Interpretation: The volume of stock solution of each sub-division has to be calculated.

Concept Introduction: Concentration of solution can be defined in terms of molarity as moles of solute to the volume of solution. The concentration of solution can be given by,

Molarity(inM)=Molesofsolute(ingrams)Volumeofsolution(inlitres)

Volumeofsolution(inlitres)=Molesofsolute(ingrams)Molarity(inM)

e)

Expert Solution
Check Mark

Answer to Problem 124CP

Volume of stock solution is 1mL

Explanation of Solution

Record the given data

Mass of solute= 10ppm standard

Volume of stock solution= 1000ppm

The mass of the solute and volume of stock solution are recorded as shown above.

To calculate the volume of stock solution to make 100mLof10ppmsolution Cuinwater

10.µgCumL×100 mL=1×103µgCuneeded1×103µgCu×1mLstock1000µgCu= 1mL ofstocksolution

Transfer 1mL of the 1000ppm stock solution to a 100mL volumetric flask, and dilute to the mark.

Requiredvolumestocksolutionis1mL

The volume of stock solution is calculated by plugging in the values of concentration of stock solution and mass of copper along with required volume of the solution. The volume of stock solution copper is 1mL .

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Chapter 6 Solutions

Chemistry: An Atoms First Approach

Ch. 6 - Prob. 2ALQCh. 6 - You have a sugar solution (solution A) with...Ch. 6 - Prob. 4ALQCh. 6 - Prob. 5ALQCh. 6 - Prob. 6ALQCh. 6 - Consider separate aqueous solutions of HCl and...Ch. 6 - Prob. 8ALQCh. 6 - Prob. 9ALQCh. 6 - The exposed electrodes of a light bulb are placed...Ch. 6 - Differentiate between what happens when the...Ch. 6 - Consider the following electrostatic potential...Ch. 6 - Prob. 15QCh. 6 - A typical solution used in general chemistry...Ch. 6 - Prob. 17QCh. 6 - A student wants to prepare 1.00 L of a 1.00-M...Ch. 6 - List the formulas of three soluble bromide salts...Ch. 6 - When 1.0 mole of solid lead nitrate is added to...Ch. 6 - What is an acid and what is a base? An acid-base...Ch. 6 - A student had 1.00 L of a 1.00-M acid solution....Ch. 6 - Prob. 23QCh. 6 - Prob. 24QCh. 6 - Prob. 25ECh. 6 - Match each name below with the following...Ch. 6 - Prob. 27ECh. 6 - Commercial cold packs and hot packs are available...Ch. 6 - Calculate the molarity of each of these solutions....Ch. 6 - A solution of ethanol (C2H5OH) in water is...Ch. 6 - Calculate the concentration of all ions present in...Ch. 6 - Prob. 32ECh. 6 - Prob. 33ECh. 6 - Prob. 34ECh. 6 - Prob. 35ECh. 6 - Prob. 36ECh. 6 - Prob. 37ECh. 6 - Prob. 38ECh. 6 - A solution is prepared by dissolving 10.8 g...Ch. 6 - A solution was prepared by mixing 50.00 mL of...Ch. 6 - Calculate the sodium ion concentration when 70.0...Ch. 6 - Suppose 50.0 mL of 0.250 M CoCl2 solution is added...Ch. 6 - Prob. 43ECh. 6 - A stock solution containing Mn2+ ions was prepaned...Ch. 6 - On the basis of the general solubility rules given...Ch. 6 - On the basis of the general solubility rules given...Ch. 6 - When the following solutions are mixed together,...Ch. 6 - When the following solutions are mixed together,...Ch. 6 - For the reactions in Exercise 47, write the...Ch. 6 - For the reactions in Exercise 48, write the...Ch. 6 - Write the balanced formula and net ionic equation...Ch. 6 - Give an example how each of the following...Ch. 6 - Write net ionic equations for the reaction, if...Ch. 6 - Write net ionic equations for the reaction, if...Ch. 6 - Prob. 55ECh. 6 - Prob. 56ECh. 6 - What mass of Na2CrO4 is required to precipitate...Ch. 6 - What volume of 0.100 M Na3PO4 is required to...Ch. 6 - What mass of solid aluminum hydroxide can be...Ch. 6 - What mass of barium sulfate can be produced when...Ch. 6 - What mass of solid AgBr is produced when 100.0 mL...Ch. 6 - What mass of silver chloride can be prepared by...Ch. 6 - A 100.0-mL aliquot of 0.200 M aqueous potassium...Ch. 6 - A 1.42-g sample of a pure compound, with formula...Ch. 6 - You are given a 1.50-g mixture of sodium nitrate...Ch. 6 - Write the balanced formula, complete ionic, and...Ch. 6 - Write the balanced formula, complete ionic, and...Ch. 6 - Write the balanced formula equation for the...Ch. 6 - Prob. 70ECh. 6 - What volume of each of the following acids will...Ch. 6 - Prob. 72ECh. 6 - Hydrochloric acid (75.0 mL of 0.250 M) is added to...Ch. 6 - Prob. 74ECh. 6 - A 25.00-mL sample of hydrochloric acid solution...Ch. 6 - A 10.00-mL sample of vinegar, an aqueous solution...Ch. 6 - What volume of 0.0200 M calcium hydroxide is...Ch. 6 - A 30.0-mL sample of an unknown strong base is...Ch. 6 - A student titrates an unknown amount of potassium...Ch. 6 - The concentration of a certain sodium hydroxide...Ch. 6 - Assign oxidation states for all atoms in each of...Ch. 6 - Assign the oxidation state for nitrogen in each of...Ch. 6 - Prob. 84ECh. 6 - Specify which of the following are...Ch. 6 - Specify which of the following equations represent...Ch. 6 - Consider the reaction between sodium metal and...Ch. 6 - Consider the reaction between oxygen (O2) gas and...Ch. 6 - Balance each of the following oxidationreduction...Ch. 6 - Balance each of the following oxidationreduction...Ch. 6 - Prob. 91AECh. 6 - Prob. 92AECh. 6 - Prob. 93AECh. 6 - Prob. 94AECh. 6 - Prob. 95AECh. 6 - Consider a 1.50-g mixture of magnesium nitrate and...Ch. 6 - A 1.00-g sample of an alkaline earth metal...Ch. 6 - A mixture contains only NaCl and Al2(SO4)3. A...Ch. 6 - The thallium (present as Tl2SO4) in a 9.486-g...Ch. 6 - Prob. 100AECh. 6 - A student added 50.0 mL of an NaOH solution to...Ch. 6 - Prob. 102AECh. 6 - Acetylsalicylic acid is the active ingredient in...Ch. 6 - When hydrochloric acid reacts with magnesium...Ch. 6 - A 2.20-g sample of an unknown acid (empirical...Ch. 6 - Carminic acid, a naturally occurring red pigment...Ch. 6 - Chlorisondamine chloride (C14H20Cl6N2) is a drug...Ch. 6 - Prob. 108AECh. 6 - Prob. 109AECh. 6 - Many oxidationreduction reactions can be balanced...Ch. 6 - Prob. 111AECh. 6 - Calculate the concentration of all ions present...Ch. 6 - A solution is prepared by dissolving 0.6706 g...Ch. 6 - For the following chemical reactions, determine...Ch. 6 - What volume of 0.100 M NaOH is required to...Ch. 6 - Prob. 116CWPCh. 6 - A 450.0-mL sample of a 0.257-M solution of silver...Ch. 6 - The zinc in a 1.343-g sample of a foot powder was...Ch. 6 - Prob. 119CWPCh. 6 - When organic compounds containing sulfur are...Ch. 6 - Prob. 121CWPCh. 6 - Prob. 122CPCh. 6 - The units of parts per million (ppm) and parts per...Ch. 6 - Prob. 124CPCh. 6 - Prob. 125CPCh. 6 - Prob. 126CPCh. 6 - Consider the reaction of 19.0 g of zinc with...Ch. 6 - A mixture contains only sodium chloride and...Ch. 6 - Prob. 129CPCh. 6 - Prob. 130CPCh. 6 - Prob. 131CPCh. 6 - Consider reacting copper(II) sulfate with iron....Ch. 6 - Prob. 133CPCh. 6 - Prob. 134CPCh. 6 - What volume of 0.0521 M Ba(OH)2 is required to...Ch. 6 - A 10.00-mL sample of sulfuric acid from an...Ch. 6 - Prob. 137CPCh. 6 - A 6.50-g sample of a diprotic acid requires 137.5...Ch. 6 - Citric acid, which can be obtained from lemon...Ch. 6 - Prob. 140CPCh. 6 - Prob. 141CPCh. 6 - Tris(pentatluorophenyl)borane, commonly known by...Ch. 6 - In a 1-L beaker, 203 mL of 0.307 M ammonium...Ch. 6 - The vanadium in a sample of ore is converted to...Ch. 6 - The unknown acid H2X can be neutralized completely...Ch. 6 - Three students were asked to find the identity of...Ch. 6 - You have two 500.0-mL aqueous solutions. Solution...
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