The more stable carbocation in the given pair is to be identified. Concept introduction: The carbocation becomes stable when atoms or groups attached to it stabilize the positive charge on it. The induced polarization of sigma bond is called inductive effect. The electron donating atom or group has a positive inductive effect that stabilizes the positive charge on carbon. The electron withdrawing atom or group has negative inductive effect that destabilizes the positive charge on carbon. The alkyl groups have electron donating inductive effect and stabilize carbocation (carbon with positive charge). The alkyl groups also show delocalization of electrons in sigma bonds through hyperconjugation and stabilized carbocation. Hyperconjugation is the delocalization of electrons in C-H sigma bond of methyl/alkyl group.

Question

Want to see the full answer?

Answer 1

Question

Chapter 5.9, Problem 13P

Interpretation Introduction

Interpretation:

The more stable carbocation in the given pair is to be identified.

Concept introduction:

The carbocation becomes stable when atoms or groups attached to it stabilize the positive charge on it.

The induced polarization of sigma bond is called inductive effect.

The electron donating atom or group has a positive inductive effect that stabilizes the positive charge on carbon.

The electron withdrawing atom or group has negative inductive effect that destabilizes the positive charge on carbon.

The alkyl groups have electron donating inductive effect and stabilize carbocation (carbon with positive charge).

The alkyl groups also show delocalization of electrons in sigma bonds through hyperconjugation and stabilized carbocation.

Hyperconjugation is the delocalization of electrons in C-H sigma bond of methyl/alkyl group.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Hi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!

. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. < cleavage Bond A • CH3 + 26. t cleavage 2°C• +3°C• Bond C Cleavage CH3 ZC '2°C. 26. E Strongest 3°C. 2C. Gund Largest BDE weakest bond In that molecule a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest C bond Produces A Weakest Bond Most Strongest Bond Stable radical Strongest Gund produces least stable radicals b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 人 8°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. methyl radical •CH3 formed in bund A Cleavage