Concept explainers
(a)
Interpretation:
The value of
Concept introduction:
The amount of heat consumed or given off during the course of a reaction is known as enthalpy of reaction. Heat is given off when bonds are formed and heat is consumed when bonds are broken.
Heat is one form of energy.
The amount of energy required to break a
(b)
Interpretation:
The value of
Concept introduction:
The amount of heat consumed or given off during the course of a reaction is known as enthalpy of reaction. Heat is given off when bonds are formed and heat is consumed when bonds are broken.
Heat is one form of energy.
The amount of energy required to break a chemical bond is referred to as bond dissociation enthalpy.
(c)
Interpretation:
It should be identified that whether the given reactions (addition of HCl to ethene and addition of dihydrogen to ethene) are exothermic or endothermic in nature.
Concept introduction:
The amount of heat consumed or given off during the course of a reaction is known as enthalpy of reaction. Heat is given off when bonds are formed and heat is consumed when bonds are broken.
Heat is one form of energy.
The amount of energy required to break a chemical bond is referred to as bond dissociation enthalpy.
A reaction with a negative
A reaction with a positive
(d)
Interpretation: It should be identified that whether the given reactions (addition of HCl to ethene and addition of dihydrogen to ethene) are exergonic or endergonic in nature.
Concept introduction:
The amount of heat consumed or given off during the course of a reaction is known as enthalpy of reaction (H). Heat is given off when bonds are formed and heat is consumed when bonds are broken.
Heat is one form of energy.
The amount of energy required to break a chemical bond is referred to as bond dissociation enthalpy.
The mathematical relationship between enthalpy (H) and free energy (G) is,
In an exergonic reaction the products have a lower free energy than it consumes.
In an endergonic reaction the product have a higher free energy than it consumes.
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Chapter 5 Solutions
Modified Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Organic Chemistry (8th Edition)
- Calculate ΔH° for each reaction. a. HO• + CH4 → •CH3 + H2O b. CH3OH + HBr → CH3Br + H2Oarrow_forwardWhat is the Born-Haber process and how is it important to the world’s economyarrow_forwardConsider the following reaction: 4 FeS2 (s) + 11 O2 (g) ↔ 2 Fe2O3 (s) + 8 SO2 (g) What is true about this process? A. ΔH > 0 and the reactants are energetically favored B. ΔH < 0 and the reactants are energetically favored C. ΔH < 0 and the products are energetically favored D. ΔH > 0 and the products are energetically favoredarrow_forward
- Calculate ΔH° for the reaction using the given bond dissociation energies. CH4(g)+2O2(g)⟶CO2(g)+2H2O(g) Bond ΔH° (kJ/mol) O–OO–O 142 H–OH–O 459 C−HC−H 411 C=OC=O 799 O=OO=O 498 C–OC–O 358 What type of reaction is this?arrow_forwardD. NO₂(g) → N2(g) + O₂( 12. Use the graphs below to determine the enthalpy of reaction for the conversion of butane, C4H10, to butanol, C4H,OH. Enthalpy, H (kJ) Enthalpy Change during the Combustion Reaction of Butane C₂H₁0 + 13/20₂ AH -2881.9 kJ/mol 4CO₂+ 5H₂0 Reaction progress A. 169 kJ/mol B. -169 kJ/mol C. 5594.8 kJ/mol D. -5594.8 kJ/mol Enthalpy, H (kJ) Enthalpy Change during the Combustion Reaction of Butanol C,H,OH+60₂ AH=-2712.9 kJ/mol 4C0₂ + 5H₂0 Reaction progress obtained:arrow_forwardUsing this reversible reaction, answer the following: N204= 2NO2 (colorless) (reddish-brown) 0° C 25° C 100° C Ice Water Room Temperature Hot Water -As the temperature increased, what happened to the [N204]? -Was the formation of reactants or products favored by the addition of heat? -Which reaction is exothermic? -If the change of enthalpy of this reaction when proceeding left to right is 14 kcal, which chemical equation is correct? N204= 2NO2 + 14 kcal N204= 2NO2, HR = +14 kcal N204 + 14 kcal = 2NO2 N204= 2NO2, HR = -14 kcalarrow_forward
- 2) The equilibrium constant Ke for the reaction A B is 1 x 105 at room temperature (25°C). a) You make a solution containing compound A at a concentration of 1 M and compound B at a concentration of 1 mM of B, and let the reaction proceed to equilibrium. What are the equilibrium concentrations of A and B? b) Calculate the standard free-energy change (AG) for this reaction. c) What is the standard free-energy change (AG) for the inverse reaction (BA)?arrow_forwardFf.316.arrow_forward6. Use the standard heat of formation AH to calculate the AH for the reaction: b. C2H4 (g) + C2H4(g)= 52 KJ H2 (g) → H2=0 KJ C₂H6 (g) C2H6(g) -84.7 KJarrow_forward
- CHOICES: A. If both statements are true B. If the 1st statement is false and the 2nd is true C. If the 1st statement is true and the 2nd is false D. If both statements are falsearrow_forwardCalculate the standard enthalpy difference between 2-ethyl-1-butene and 1-hexene to determine which molecule is more stable. The heats of formation are -55.8 kJ/mol for 2-ethyl-1-butene and -40.5 kJ/mol for 1-hexene. O a. 2-ethyl-1-butene is more stable by 15.3 kJ/mol O b. The two stabilities can't be compared because the molecules are not isomers. O c. 1-Hexene is more stable by 15.3 kJ/molarrow_forwardA.) What is the heat of reaction, ΔH°? CO2(g) + H2O(l) à H2CO3(aq) –20.2 kJ mol–1 –1379 kJ mol–1 –592 kJ mol–1 B.) What is the average bond energy in CO2? CO2(g) ΔH°f, = –393.5 kJ mol–1 CO(g) ΔH°f, = –110.5 kJ mol–1 C(g) ΔH°f, = +715 kJ mol–1 CO32–(aq) ΔH°f, = –676.3 kJ mol–1 O(g) ΔH°f, = +249.0 kJ mol–1 207 kJ mol–1 1607 kJ mol–1 804 kJ mol–1arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning