In Exercises 47–52, solve each system by the method of your choice.
49.
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COLLEGE ALGEBRA ESSENTIALS
- Exercises 143–145 will help you prepare for the material covered in the next section. y2 - yı 143. If (x1, yı) = (-3, 1) and (x2, y2) = (-2, 4), find X2 - X1 144. Find the ordered pairs (- 0) and (0, 4х — Зу - 6 % 0. satisfying 145. Solve for y: 3x + 2y – 4 = 0.arrow_forwardFor Exercises 73–80, (a) evaluate the discriminant and (b) determine the number and type of solutions to each equation. (See Example 9) 73. Зх? 4х + 6 3D 0 74. 5x - 2x + 4 = 0 75. - 2w? + 8w = 3 76. -6d + 9d = 2 77. Зx(х — 4) 3D х — 4 78. 2x(x – 2) = x + 3 79. –1.4m + 0.1 = -4.9m² 80. 3.6n + 0.4 = -8.1n?arrow_forwardIn Exercises 20–21, solve each rational equation. 11 20. x + 4 + 2 x2 – 16 - x + 1 21. x? + 2x – 3 1 1 x + 3 x - 1 ||arrow_forward
- Exercises 59–66: Use the intersection-of-graphs method to solve the equation. Then solve symbolically. 63. -х + 4 %3D 3хarrow_forwardFor Exercises 81–100, make an appropriate substitution and solve the equation. (See Examples 10–11) 81. (2x + 5)? – 7(2x + 5) - 30 = 0 82. (Зх — 7)? - 6(3х — 7)-16 3D 0 83. (x + 2x)? – 18(r + 2x) = -45 84. (x + 3x)? - 86. (у? — 3)? — 9(y? — 3) — 52 %3D 0 14(x + 3x) = -40 85. (x + 2)2 + (x + 2) – 42 = 0 10 2 10 - 61 m - - 27 = 0 x + + 35 = 0 87. 88. - 121 x + т - m m 89. 2 + 2 + = 12 90. + 3 + 6 + 3 = -8 91. 5c2/5 11c/5 + 2 = 0 92. З3 d'/3 – 4 = 0 93. y'/2 – y/4 6 = 0 94. n'/2 + 6n/4 – 16 = 0 95. 9y 10y + 1 = 0 96. 100х-4 29x-2 + 1 = 0 | 97. 4t – 25 Vi = 0 98. 9m – 16Vm = 0 100. 392 + 16q -1 99. 30k-2 – 23k- + 2 = 0 + 5 = 0arrow_forwardExercises 86–88 will help you prepare for the material covered in the next section. If –9 is substituted for x in the equation 4x – 3 = 5x + 6, is the resulting statement true or false? Simplify: 13 – 3(x + 2). Зх + Simplify: 10(**1).arrow_forward
- In Exercises 105–107, solve each equation using a graphing utility. Graph each side separately in the same viewing rectangle. The solutions are the x-coordinates of the intersection points. 105. |x + 1|| 106. 13(x + 4)| = 12 107. 12x – 3| = 19 – 4x|arrow_forwardSolve the equations * 2x – y + 3z = -3, 3.x + 3y – z = 10, -x – y + z = -4 O x = 2, y = 1, z = -4 Ox = 4, y = 2, z = -4 O x = 1, y = 2, z = -4 O x = 1, y = 2, z = -1arrow_forwardFor Exercises 5–10, a. Simplify the expression. b. Substitute 0 for h in the simplified expression. 2(x + h)? + 3(x + h) · 5. (2x + 3x) 3(x + h - 4(x + h) – (3x - 4x) 6. h 1 1 1 1 (x + h) – 2 7. x - 2 2(x + h) + 5 8. 2x + 5 h (x + h) – x 9. (x + h) 10. - X h harrow_forward
- I want to know in solutionarrow_forwardExercises 59-66: Use the intersection-of-graphs method to solve the equation. Then solve symbolically. 59. x + 4 = 1 - 2x 60. 2x = 3x – 1 61. x = 4 - x 62. 3 – x = 2x 63. -x + 4 = 3x 64. 1- 2x = x + 4 65. 2(x – 1) – 2 = x 66. - (x + 1) – 2 = 2xarrow_forwardPart 4. 2 Please show complete solution.arrow_forward
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