Concept explainers
Solve each system in Exercises 5–18.
17.
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Chapter 5 Solutions
COLLEGE ALGEBRA ESSENTIALS
- In Exercises 59–64, solve and check each linear equation. 59. 2x – 5 = 7 60. 5x + 20 = 3x 61. 7(x – 4) = x + 2 62. 1 - 2(6 – x) = 3x + 2 63. 2(x – 4) + 3(x + 5) = 2x – 2 64. 2x 4(5x + 1) = 3x + 17arrow_forwardIn Exercises 9–12, find all real solutions to the equations.arrow_forwardExercises 99–108: Solve the given equation for the specified variable. 101. P = 2L + 2W for Larrow_forward
- Exercises 7–12: Determine whether the equation is linear or nonlinear by trying to write it in the form ax + b = 0. 7. 3x – 1.5 = 7arrow_forwardIn Exercises 49–54, solve for y in terms of t or x, as appropriate.arrow_forwardExercises 86–88 will help you prepare for the material covered in the next section. If –9 is substituted for x in the equation 4x – 3 = 5x + 6, is the resulting statement true or false? Simplify: 13 – 3(x + 2). Зх + Simplify: 10(**1).arrow_forward
- In Exercises 20–21, solve each rational equation. 11 20. x + 4 + 2 x2 – 16 - x + 1 21. x? + 2x – 3 1 1 x + 3 x - 1 ||arrow_forwardExercises 43–52: Complete the following. (a) Solve the equation symbolically. (b) Classify the equation as a contradiction, an identity, or a conditional equation. 43. 5x - 1 = 5x + 4 44. 7- 9: = 2(3 – 42) – z 45. 3(x - 1) = 5 46. 22 = -2(2x + 1.4) 47. 0.5(x – 2) + 5 = 0.5x + 4 48. 눈x-2(x-1)3-x + 2 2x + 1 2x 49. 50. x – 1.5 2- 3r - 1.5 51. -6 52. 0.5 (3x - 1) + 0.5x = 2x – 0.5arrow_forwardCan u plzz provide its solution?arrow_forward
- Proof 2 implies 3 ,not type solution pleasearrow_forwardPlease solve Exercise 2.1.7... parts a and b with detailed explanationsarrow_forwardIn Exercises 43–54, solve each absolute value equation or indicate the equation has no solution. 43. |x – 2| = 7 45. |2x – 1| = 5 47. 2|3x – 2| = 14 44. |x + 1| = 5 46. |2r – 3| = 11 48. 3|2x – 1| = 21 %3D %3D 5 24 - + 6 = 18 50. 4 1 x + 7 = 10 51. |x + 1| + 5 = 3 53. |2x – 1| + 3 = 3 52. |x + 1| + 6 = 2 54. |3x – 2| + 4 = 4arrow_forward
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