McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 5.2, Problem 9WE

a)

To determine

To find: The theorem that is converse to said theorems 5.1.

a)

Expert Solution
Check Mark

Answer to Problem 9WE

Theorem 5.4 is converse of theorem 5.1, that states that If both pairs of opposite sides of a quadrilateral are congruent, then quadrilateral is a parallelogram.”

Explanation of Solution

Given information: Statements of following theorem is given,

Theorem 5.1: “Opposite sides of a parallelogram are congruent.’

Concept used: Converse of a theorem is a statement that is formed by interchanging the given section of a theorem by what to prove and what to prove section by given section of the theorem.

Calculation: On observing different sections given, it is found that the converse to theorem 5.1 is theorem 5.4 that’s statement is, “If both pairs of opposite sides of a quadrilateral are congruent, then quadrilateral is a parallelogram.”

Conclusion: Thus, theorem 5.4 is the converse of given theorem 5.1.

b)

To determine

To find: The theorem that is converse to said theorems 5.2.

b)

Expert Solution
Check Mark

Answer to Problem 9WE

Theorem 5.6 is converse of theorem 5.2, that states that If both pairs of opposite angles of a quadrilateral are congruent, then the quadrilateral is a parallelogram.”

Explanation of Solution

Given information: Statements of following theorems are given,

Theorem 5.2: “Opposite angles of a parallelogram are congruent.”

Concept used: Converse of a theorem is a statement that is formed by interchanging the given section of a theorem by what to prove and what to prove section by given section of the theorem.

Calculation: On observing different sections given, it is found that the converse to theorem 5.2 is theorem 5.6 that’s statement is, “If both pairs of opposite angles of a quadrilateral are congruent, then the quadrilateral is a parallelogram.”

Conclusion: Thus, theorem 5.6 is the converse of given theorem 5.2.

c)

To determine

To find: The theorem that is converse to said theorems 5.3.

c)

Expert Solution
Check Mark

Answer to Problem 9WE

Theorem 5.7 is converse of theorem 5.3, that states that “If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.”

Explanation of Solution

Given information: Statements of following theorems are given,

Theorem 5.3: ”Diagonals of a parallelogram bisect each other.”

Concept used: Converse of a theorem is a statement that is formed by interchanging the given section of a theorem by what to prove and what to prove section by given section of the theorem.

Calculation: On observing different sections given, it is found that the converse to theorem 5.3 is theorem 5.7 that’s statement is, “If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.”

Conclusion: Thus, theorem 5.7 is the converse of given theorem 5.3.

a)

To determine

To find: The theorems that are converse to said theorems 5.1,5.2 and 5.3.

a)

Expert Solution
Check Mark

Answer to Problem 9WE

Theorem 5.4 is converse of theorem 5.1, theorem 5.6 is converse of theorem 5.2 and theorem 5.7 is converse of theorem 5.3.

Explanation of Solution

Given information: Statements of following theorems are given,

Theorem 5.1: “Opposite sides of a parallelogram are congruent.’

Theorem 5.2: “Opposite angles of a parallelogram are congruent.”

Theorem 5.3: ”Diagonals of a parallelogram bisect each other.”

Concept used: Converse of a theorem is a statement that is formed by interchanging the given section of a theorem by what to prove and what to prove section by given section of the theorem.

Calculation: On observing different sections given, it is found that the converse to theorem 5.1 is theorem 5.4 that’s statement is, “If both pairs of opposite sides of a quadrilateral are congruent, then quadrilateral is a parallelogram.”

Converse to theorem 5.2 is theorem 5.6 that’s statement is, “If both pairs of opposite angles of a quadrilateral are congruent, then the quadrilateral is a parallelogram.”

Converse to theorem 5.3 is theorem 5.7 that’s statement is, “If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.”

Conclusion: Thus, theorem 5.4, theorem 5.6 and theorem 5.7 are the converse of given theorems.

Chapter 5 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 5.1 - Prob. 11CECh. 5.1 - Prob. 12CECh. 5.1 - Prob. 13CECh. 5.1 - Prob. 14CECh. 5.1 - Prob. 15CECh. 5.1 - Prob. 16CECh. 5.1 - Prob. 17CECh. 5.1 - Prob. 18CECh. 5.1 - Prob. 1WECh. 5.1 - Prob. 2WECh. 5.1 - Prob. 3WECh. 5.1 - Prob. 4WECh. 5.1 - Prob. 5WECh. 5.1 - Prob. 6WECh. 5.1 - Prob. 7WECh. 5.1 - Prob. 8WECh. 5.1 - Prob. 9WECh. 5.1 - Prob. 10WECh. 5.1 - Prob. 11WECh. 5.1 - Prob. 12WECh. 5.1 - Prob. 13WECh. 5.1 - Prob. 14WECh. 5.1 - Prob. 15WECh. 5.1 - Prob. 16WECh. 5.1 - Prob. 17WECh. 5.1 - Prob. 18WECh. 5.1 - Prob. 19WECh. 5.1 - Prob. 20WECh. 5.1 - Prob. 21WECh. 5.1 - Prob. 22WECh. 5.1 - Prob. 23WECh. 5.1 - Prob. 24WECh. 5.1 - Prob. 25WECh. 5.1 - Prob. 26WECh. 5.1 - Prob. 27WECh. 5.1 - Prob. 28WECh. 5.1 - Prob. 29WECh. 5.1 - Prob. 30WECh. 5.1 - Prob. 31WECh. 5.1 - Prob. 32WECh. 5.1 - Prob. 33WECh. 5.1 - Prob. 34WECh. 5.1 - Prob. 35WECh. 5.1 - Prob. 36WECh. 5.1 - Prob. 37WECh. 5.1 - Prob. 38WECh. 5.1 - Prob. 39WECh. 5.2 - Prob. 1CECh. 5.2 - Prob. 2CECh. 5.2 - Prob. 3CECh. 5.2 - Prob. 4CECh. 5.2 - Prob. 5CECh. 5.2 - Prob. 6CECh. 5.2 - Prob. 7CECh. 5.2 - Prob. 8CECh. 5.2 - Prob. 9CECh. 5.2 - Prob. 10CECh. 5.2 - Prob. 11CECh. 5.2 - Prob. 12CECh. 5.2 - Prob. 13CECh. 5.2 - Prob. 1WECh. 5.2 - Prob. 2WECh. 5.2 - Prob. 3WECh. 5.2 - Prob. 4WECh. 5.2 - Prob. 5WECh. 5.2 - Prob. 6WECh. 5.2 - Prob. 7WECh. 5.2 - Prob. 8WECh. 5.2 - Prob. 9WECh. 5.2 - Prob. 10WECh. 5.2 - Prob. 11WECh. 5.2 - Prob. 12WECh. 5.2 - Prob. 13WECh. 5.2 - Prob. 14WECh. 5.2 - Prob. 15WECh. 5.2 - Prob. 16WECh. 5.2 - Prob. 17WECh. 5.2 - Prob. 18WECh. 5.2 - Prob. 19WECh. 5.2 - Prob. 20WECh. 5.2 - Prob. 21WECh. 5.2 - Prob. 22WECh. 5.2 - Prob. 23WECh. 5.2 - Prob. 24WECh. 5.2 - Prob. 25WECh. 5.3 - Prob. 1CECh. 5.3 - Prob. 2CECh. 5.3 - Prob. 3CECh. 5.3 - Prob. 4CECh. 5.3 - Prob. 5CECh. 5.3 - Prob. 6CECh. 5.3 - Prob. 7CECh. 5.3 - Prob. 8CECh. 5.3 - Prob. 9CECh. 5.3 - Prob. 1WECh. 5.3 - Prob. 2WECh. 5.3 - Prob. 3WECh. 5.3 - Prob. 4WECh. 5.3 - Prob. 5WECh. 5.3 - Prob. 6WECh. 5.3 - Prob. 7WECh. 5.3 - Prob. 8WECh. 5.3 - Prob. 9WECh. 5.3 - Prob. 10WECh. 5.3 - Prob. 11WECh. 5.3 - Prob. 12WECh. 5.3 - Prob. 13WECh. 5.3 - Prob. 14WECh. 5.3 - Prob. 15WECh. 5.3 - Prob. 16WECh. 5.3 - Prob. 17WECh. 5.3 - Prob. 18WECh. 5.3 - Prob. 19WECh. 5.3 - Prob. 20WECh. 5.3 - Prob. 21WECh. 5.3 - Prob. 22WECh. 5.3 - Prob. 23WECh. 5.3 - Prob. 24WECh. 5.3 - Prob. 25WECh. 5.3 - Prob. 1ST1Ch. 5.3 - Prob. 2ST1Ch. 5.3 - Prob. 3ST1Ch. 5.3 - Prob. 4ST1Ch. 5.3 - Prob. 5ST1Ch. 5.3 - Prob. 6ST1Ch. 5.3 - Prob. 7ST1Ch. 5.3 - Prob. 8ST1Ch. 5.3 - Prob. 1ECh. 5.3 - Prob. 2ECh. 5.3 - Prob. 3ECh. 5.3 - Prob. 4ECh. 5.3 - Prob. 5ECh. 5.3 - Prob. 6ECh. 5.4 - Prob. 1CECh. 5.4 - Prob. 2CECh. 5.4 - Prob. 3CECh. 5.4 - Prob. 4CECh. 5.4 - Prob. 5CECh. 5.4 - Prob. 6CECh. 5.4 - Prob. 7CECh. 5.4 - Prob. 8CECh. 5.4 - Prob. 9CECh. 5.4 - Prob. 10CECh. 5.4 - Prob. 11CECh. 5.4 - Prob. 1WECh. 5.4 - Prob. 2WECh. 5.4 - Prob. 3WECh. 5.4 - Prob. 4WECh. 5.4 - Prob. 5WECh. 5.4 - Prob. 6WECh. 5.4 - Prob. 7WECh. 5.4 - Prob. 8WECh. 5.4 - Prob. 9WECh. 5.4 - Prob. 10WECh. 5.4 - Prob. 11WECh. 5.4 - Prob. 12WECh. 5.4 - Prob. 13WECh. 5.4 - Prob. 14WECh. 5.4 - Prob. 15WECh. 5.4 - Prob. 16WECh. 5.4 - Prob. 17WECh. 5.4 - Prob. 18WECh. 5.4 - Prob. 19WECh. 5.4 - Prob. 20WECh. 5.4 - Prob. 21WECh. 5.4 - Prob. 22WECh. 5.4 - Prob. 23WECh. 5.4 - Prob. 24WECh. 5.4 - Prob. 25WECh. 5.4 - Prob. 26WECh. 5.4 - Prob. 27WECh. 5.4 - Prob. 28WECh. 5.4 - Prob. 29WECh. 5.4 - Prob. 30WECh. 5.4 - Prob. 31WECh. 5.4 - Prob. 32WECh. 5.4 - Prob. 33WECh. 5.4 - Prob. 34WECh. 5.4 - Prob. 35WECh. 5.4 - Prob. 36WECh. 5.4 - Prob. 37WECh. 5.4 - Prob. 38WECh. 5.4 - Prob. 39WECh. 5.4 - Prob. 40WECh. 5.4 - Prob. 41WECh. 5.4 - Prob. 42WECh. 5.4 - Prob. 1MRECh. 5.4 - Prob. 2MRECh. 5.4 - Prob. 3MRECh. 5.4 - Prob. 4MRECh. 5.4 - Prob. 5MRECh. 5.4 - Prob. 6MRECh. 5.4 - Prob. 7MRECh. 5.4 - Prob. 8MRECh. 5.4 - Prob. 9MRECh. 5.5 - Prob. 1CECh. 5.5 - Prob. 2CECh. 5.5 - Prob. 3CECh. 5.5 - Prob. 4CECh. 5.5 - Prob. 5CECh. 5.5 - Prob. 6CECh. 5.5 - Prob. 7CECh. 5.5 - Prob. 8CECh. 5.5 - Prob. 9CECh. 5.5 - Prob. 10CECh. 5.5 - Prob. 11CECh. 5.5 - Prob. 1WECh. 5.5 - Prob. 2WECh. 5.5 - Prob. 3WECh. 5.5 - Prob. 4WECh. 5.5 - Prob. 5WECh. 5.5 - Prob. 6WECh. 5.5 - Prob. 7WECh. 5.5 - Prob. 8WECh. 5.5 - Prob. 9WECh. 5.5 - Prob. 10WECh. 5.5 - Prob. 11WECh. 5.5 - Prob. 12WECh. 5.5 - Prob. 13WECh. 5.5 - Prob. 14WECh. 5.5 - Prob. 15WECh. 5.5 - Prob. 16WECh. 5.5 - Prob. 17WECh. 5.5 - Prob. 18WECh. 5.5 - Prob. 19WECh. 5.5 - Prob. 20WECh. 5.5 - Prob. 21WECh. 5.5 - Prob. 22WECh. 5.5 - Prob. 23WECh. 5.5 - Prob. 24WECh. 5.5 - Prob. 25WECh. 5.5 - Prob. 26WECh. 5.5 - Prob. 27WECh. 5.5 - Prob. 28WECh. 5.5 - Prob. 29WECh. 5.5 - Prob. 30WECh. 5.5 - Prob. 31WECh. 5.5 - Prob. 32WECh. 5.5 - Prob. 33WECh. 5.5 - Prob. 34WECh. 5.5 - Prob. 35WECh. 5.5 - Prob. 36WECh. 5.5 - Prob. 1ST2Ch. 5.5 - Prob. 2ST2Ch. 5.5 - Prob. 3ST2Ch. 5.5 - Prob. 4ST2Ch. 5.5 - Prob. 5ST2Ch. 5.5 - Prob. 6ST2Ch. 5.5 - Prob. 7ST2Ch. 5.5 - Prob. 8ST2Ch. 5 - Prob. 1CRCh. 5 - Prob. 2CRCh. 5 - Prob. 3CRCh. 5 - Prob. 4CRCh. 5 - Prob. 5CRCh. 5 - Prob. 6CRCh. 5 - Prob. 7CRCh. 5 - Prob. 8CRCh. 5 - Prob. 9CRCh. 5 - Prob. 10CRCh. 5 - Prob. 11CRCh. 5 - Prob. 12CRCh. 5 - Prob. 13CRCh. 5 - Prob. 14CRCh. 5 - Prob. 15CRCh. 5 - Prob. 16CRCh. 5 - Prob. 17CRCh. 5 - Prob. 18CRCh. 5 - Prob. 19CRCh. 5 - Prob. 20CRCh. 5 - Prob. 21CRCh. 5 - Prob. 22CRCh. 5 - Prob. 1CTCh. 5 - Prob. 2CTCh. 5 - Prob. 3CTCh. 5 - Prob. 4CTCh. 5 - Prob. 5CTCh. 5 - Prob. 6CTCh. 5 - Prob. 7CTCh. 5 - Prob. 8CTCh. 5 - Prob. 9CTCh. 5 - Prob. 10CTCh. 5 - Prob. 11CTCh. 5 - Prob. 12CTCh. 5 - Prob. 13CTCh. 5 - Prob. 14CTCh. 5 - Prob. 15CTCh. 5 - Prob. 16CTCh. 5 - Prob. 17CTCh. 5 - Prob. 18CTCh. 5 - Prob. 19CTCh. 5 - Prob. 1CURCh. 5 - Prob. 2CURCh. 5 - Prob. 3CURCh. 5 - Prob. 4CURCh. 5 - Prob. 5CURCh. 5 - Prob. 6CURCh. 5 - Prob. 7CURCh. 5 - Prob. 8CURCh. 5 - Prob. 9CURCh. 5 - Prob. 10CURCh. 5 - Prob. 11CURCh. 5 - Prob. 12CURCh. 5 - Prob. 13CURCh. 5 - Prob. 14CURCh. 5 - Prob. 15CURCh. 5 - Prob. 16CURCh. 5 - Prob. 17CURCh. 5 - Prob. 18CURCh. 5 - Prob. 19CURCh. 5 - Prob. 20CURCh. 5 - Prob. 21CURCh. 5 - Prob. 22CURCh. 5 - Prob. 23CURCh. 5 - Prob. 24CURCh. 5 - Prob. 25CURCh. 5 - Prob. 26CURCh. 5 - Prob. 27CURCh. 5 - Prob. 28CURCh. 5 - Prob. 29CURCh. 5 - Prob. 30CURCh. 5 - Prob. 31CUR

Additional Math Textbook Solutions

Find more solutions based on key concepts
Knowledge Booster
Background pattern image
Geometry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Elementary Geometry For College Students, 7e
Geometry
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Cengage,
Text book image
Elementary Geometry for College Students
Geometry
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Cengage Learning
Polynomials with Trigonometric Solutions (2 of 3: Substitute & solve); Author: Eddie Woo;https://www.youtube.com/watch?v=EnfhYp4o20w;License: Standard YouTube License, CC-BY
Quick Revision of Polynomials | Tricks to Solve Polynomials in Algebra | Maths Tricks | Letstute; Author: Let'stute;https://www.youtube.com/watch?v=YmDnGcol-gs;License: Standard YouTube License, CC-BY
Introduction to Polynomials; Author: Professor Dave Explains;https://www.youtube.com/watch?v=nPPNgin7W7Y;License: Standard Youtube License