McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
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Question
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Chapter 5.1, Problem 37WE

a)

To determine

To find: If line segments AX and BY are equal.

a)

Expert Solution
Check Mark

Answer to Problem 37WE

Thus, it proves that

  AX=BY .

Explanation of Solution

Given information: Plane P and plane Q are parallel to each other as well as two lines j and k passing from two planes are also parallel as shown in below figure,

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 5.1, Problem 37WE , additional homework tip  1

Concept used: Following concept of theorem 5.4 is used here, “The opposite sides of a parallelogram are congruent.”

Calculation: As plane P and plane Q are parallel, so the line segments lying on them will also be parallel to each other, so, AB||XY .

Also, as lines j and k are parallel, so their corresponding line segments AX and BY will also be parallel. And hence ABYX is a parallelogram. Accordingly, its opposite sides AX and BY will be equal to each other.

Conclusion: Thus, it is concluded that AX=BY .

b)

To determine

To find: The theorem about parallel planes and lines that are used to prove AX=BY .

b)

Expert Solution
Check Mark

Answer to Problem 37WE

Theorem 3.1 that is “If two parallel planes are cut by a third plane, then the lines of intersection are parallel.” Is used here.

Explanation of Solution

Given information: Plane P and plane Q are parallel to each other as well as two lines j and k passing from two planes are also parallel as shown in below figure,

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 5.1, Problem 37WE , additional homework tip  2

Concept used: Following concept of theorem 3.1 to be used here, ” If two parallel planes are cut by a third plane, then the lines of intersection are parallel.”

Calculation: By using the concept of theorem 3.1 that says that If two parallel planes are cut by a third plane, then the lines of intersection are parallel.” , it is proved here that ABYX is a parallelogram. Accordingly, its opposite sides AX and BY will be equal to each other.

Conclusion: So, statement of theorem 3.1 is used here to prove AX=BY .

Chapter 5 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 5.1 - Prob. 11CECh. 5.1 - Prob. 12CECh. 5.1 - Prob. 13CECh. 5.1 - Prob. 14CECh. 5.1 - Prob. 15CECh. 5.1 - Prob. 16CECh. 5.1 - Prob. 17CECh. 5.1 - Prob. 18CECh. 5.1 - Prob. 1WECh. 5.1 - Prob. 2WECh. 5.1 - Prob. 3WECh. 5.1 - Prob. 4WECh. 5.1 - Prob. 5WECh. 5.1 - Prob. 6WECh. 5.1 - Prob. 7WECh. 5.1 - Prob. 8WECh. 5.1 - Prob. 9WECh. 5.1 - Prob. 10WECh. 5.1 - Prob. 11WECh. 5.1 - Prob. 12WECh. 5.1 - Prob. 13WECh. 5.1 - Prob. 14WECh. 5.1 - Prob. 15WECh. 5.1 - Prob. 16WECh. 5.1 - Prob. 17WECh. 5.1 - Prob. 18WECh. 5.1 - Prob. 19WECh. 5.1 - Prob. 20WECh. 5.1 - Prob. 21WECh. 5.1 - Prob. 22WECh. 5.1 - Prob. 23WECh. 5.1 - Prob. 24WECh. 5.1 - Prob. 25WECh. 5.1 - Prob. 26WECh. 5.1 - Prob. 27WECh. 5.1 - Prob. 28WECh. 5.1 - Prob. 29WECh. 5.1 - Prob. 30WECh. 5.1 - Prob. 31WECh. 5.1 - Prob. 32WECh. 5.1 - Prob. 33WECh. 5.1 - Prob. 34WECh. 5.1 - Prob. 35WECh. 5.1 - Prob. 36WECh. 5.1 - Prob. 37WECh. 5.1 - Prob. 38WECh. 5.1 - Prob. 39WECh. 5.2 - Prob. 1CECh. 5.2 - Prob. 2CECh. 5.2 - Prob. 3CECh. 5.2 - Prob. 4CECh. 5.2 - 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Prob. 24CURCh. 5 - Prob. 25CURCh. 5 - Prob. 26CURCh. 5 - Prob. 27CURCh. 5 - Prob. 28CURCh. 5 - Prob. 29CURCh. 5 - Prob. 30CURCh. 5 - Prob. 31CUR
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