To find: the length of MN¯

Expert Solution & Answer

Answer to Problem 17CUR

MN=3r−s

Explanation of Solution

Given:

M and N are the midpoints of the legs of the trapezoid EFGH .

EF¯=2r+s

HG¯=4r−3s

Consider the figure shown below representing the given question:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 5, Problem 17CUR

Consider the trapezoid EFGH .

M and N are the midpoints of the legs of the trapezoid EFGH . So, MN¯ is the median of the trapezoid EFGH .

So, by theorem 5-19 part (2), the length of the median MN¯ is equal to the average of the base lengths EF¯ and HG¯ .

Thus,

MN=12(MN+HG)=12(2r+s+4r−3s)=12(6r−2s)=3r−s

Chapter 5, Problem 16CUR

Chapter 5, Problem 18CUR

Chapter 5 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

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Ch. 5.1 - Prob. 11CE Ch. 5.1 - Prob. 12CE Ch. 5.1 - Prob. 13CE Ch. 5.1 - Prob. 14CE Ch. 5.1 - Prob. 15CE Ch. 5.1 - Prob. 16CE Ch. 5.1 - Prob. 17CE Ch. 5.1 - Prob. 18CE Ch. 5.1 - Prob. 1WE Ch. 5.1 - Prob. 2WE Ch. 5.1 - Prob. 3WE Ch. 5.1 - Prob. 4WE Ch. 5.1 - Prob. 5WE Ch. 5.1 - Prob. 6WE Ch. 5.1 - Prob. 7WE Ch. 5.1 - Prob. 8WE Ch. 5.1 - Prob. 9WE Ch. 5.1 - Prob. 10WE Ch. 5.1 - Prob. 11WE Ch. 5.1 - Prob. 12WE Ch. 5.1 - Prob. 13WE Ch. 5.1 - Prob. 14WE Ch. 5.1 - Prob. 15WE Ch. 5.1 - Prob. 16WE Ch. 5.1 - Prob. 17WE Ch. 5.1 - Prob. 18WE Ch. 5.1 - Prob. 19WE Ch. 5.1 - Prob. 20WE Ch. 5.1 - Prob. 21WE Ch. 5.1 - Prob. 22WE Ch. 5.1 - Prob. 23WE Ch. 5.1 - Prob. 24WE Ch. 5.1 - Prob. 25WE Ch. 5.1 - Prob. 26WE Ch. 5.1 - Prob. 27WE Ch. 5.1 - Prob. 28WE Ch. 5.1 - Prob. 29WE Ch. 5.1 - Prob. 30WE Ch. 5.1 - Prob. 31WE Ch. 5.1 - Prob. 32WE Ch. 5.1 - Prob. 33WE Ch. 5.1 - Prob. 34WE Ch. 5.1 - Prob. 35WE Ch. 5.1 - Prob. 36WE Ch. 5.1 - Prob. 37WE Ch. 5.1 - Prob. 38WE Ch. 5.1 - Prob. 39WE Ch. 5.2 - Prob. 1CE Ch. 5.2 - 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