
Concept explainers
To explain: Why the given equation is not an identity and find one value of the variable for which the equation is not true.

Explanation of Solution
Given information:
The following equation:
√sec2x−1=tanx
Formula used:
The following identity:
1+tan2x=sec2x
The equation can be simplified as:
√sec2x−1=tanx√tan2x=tanx [Pythagorean identity]±tanx≠tanx [Square root]
The left hand side is not equal to the right hand side. Hence the equation is not an identity.
Let x=2π3
Substituting value of x on left hand side of the equation,
√sec2x−1=√sec22π3−1 [Substitute value of x]=√(−2)2−1 [Put value of sec 2π3]=√4−1 [Square]=√3 [Subtract]
Substituting value of x on right hand side of the equation,
tanx=tan2π3 [Substitute value of x]=−√3 [Put value of tan2π3]
The value on the left hand side is not equal to the value on the right hand side.
Hence for x=2π3 , the equation is not true
Also, the given equation is not an identity because the expressions on the left hand side and the right hand side when plotted on a graph, do not coincide.
Graph:
Sketch the graph using graphing utility.
Step 1: Press WINDOW button to access the Window editor.
Step 2: Press Y= button.
Step 3: Enter the expressions Y1=√sec2x−1 and Y2=tanx which is required to graph.
Step 4: Press GRAPH button to graph the function.
The graph is obtained as:
Interpretation:
The graphs of the left hand side expression and the right hand side expression do no coincide.
Chapter 5 Solutions
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