Chapter 5.2, Problem 5.1BFP

Interpretation Introduction

Interpretation:

The pressure of carbon dioxide $\left({\text{CO}}_{\text{2}}\right)$ in $\text{mmHg}$, $\text{pascals}$ and ${\text{lb/in}}^2$ is to be calculated.

Concept introduction:

The Pressure of a gas can be measured with the help of a device known as manometer.

There are basically the two types of manometer. First one is closed-end manometer and the second one is open-end manometer.

In closed-end manometer the difference in column height $\left(\Delta h\right)$ is equal to the gas pressure.

$P_{\text{gas}}=\Delta h$

In an open-end manometer the gas pressure is being measured either by adding or subtracting $\Delta h$ from the atmospheric pressure $\left(P_{\text{atm}}\right)$ of the gas.

Case I: When $P_{\text{gas}}$ is less than $P_{\text{atm}}$ then the gas pressure is being calculated as follows:

$P_{\text{gas}}=P_{\text{atm}}-\Delta h$

Case II: When $P_{\text{gas}}$ is more than $P_{\text{atm}}$ then the gas pressure is being calculated as follows:

$P_{\text{gas}}=P_{\text{atm}}+\Delta h$

The conversion factor to convert $\text{torrs}$ to $\text{mmHg}$ is as follows:

$\text{1 torr}=1\text{mmHg}$

The conversion factor to convert $\text{mmHg}$ to $\text{atm}$ is as follows:

$\text{760 mmHg}=\text{1 atm}$

The conversion factor to convert $\text{atm}$ to $\text{pascal}$ is as follows:

$\text{1 atm}=\text{1}{\text{.01325×10}}^{\text{5}}\text{ pascals}$

The conversion factor to covert $\text{atm}$ to ${\text{lb/in}}^{\text{2}}$ is as follows:

$\text{1 atm}=\text{14}{\text{.7 lb/in}}^{\text{2}}$