Chapter 5.2, Problem 47E

a)

To determine

To find probability that other education.

Answer to Problem 47E

The probability of other education = 0.28

Explanation of Solution

Given:

P(did not complete high school) = 0.13

P(Complete high school diploma) = 0.29

P(Bachelors degree) = 0.30

The conditions of probability distribution are:

1)The probabilities should be $0\le p\le 1$

2)Sum of all the probabilities should be 1.

Using condition 2,

0.13+0.29+0.30+P(other) = 1

P(Other)=1-0.72 = 0.28

b)

To determine

To find probability of completing at least high school

Answer to Problem 47E

The probability of completing at least high school=0.87

Explanation of Solution

Given:

P(did not complete high school) = 0.13

P(Complete high school diploma) = 0.29

P(Bachelors degree) = 0.30

Formula:

P(A^c)=1-P(A)

Using formula of complementary probability,

P(at least high school) = 1-P(not high school) = 1-0.13 = 0.87