Chapter 5.2, Problem 46E

a)

To determine

To find probability of other.

Answer to Problem 46E

The probability of other = 0.09

Explanation of Solution

Given:

Language:	English	French	Asian/Pacific	Other
Probability	0.63	0.22	0.06	?

The conditions of probability distribution are:

1)The probabilities should be $0\le p\le 1$

2)Sum of all the probabilities should be 1.

Using condition 2,

0.63+0.22+0.06+P(other) = 1

P(Other)=1-0.91 = 0.09

b)

To determine

To find probability of not English.

Answer to Problem 46E

The probability of not English=0.37

Explanation of Solution

Given:

Language:	English	French	Asian/Pacific	Other
Probability	0.63	0.22	0.06	0.09

Formula:

P(A^c)=1-P(A)

Using formula of complementary probability,

P(not English) = 1-P(English) = 1-0.63 = 0.37

c)

To determine

To find probability that language other than English or French.

Answer to Problem 46E

The probability is 0.15

Explanation of Solution

Given:

Language:	English	French	Asian/Pacific	Other
Probability	0.63	0.22	0.06	0.09

Formula:

  $P(AorB)=P(A)+P(B)$

The probability that Canadians mother tongue language is other than English or French means the language Asian/Pacific or Other.

Using formula,

  $\begin{array}{l}P\left(\text{Asian/Pacific }or\text{ Other}\right)=P\left(\text{Asian/Pacific}\right)+P\left(\text{Other}\right)\hfill \\ P\left(\text{Asian/Pacific }or\text{ Other}\right)=0.06+0.09=0.15\hfill \end{array}$