(a)
To determine: The change in P when the width and length of the beam are doubled.
There will be no change in P.
Given information:
The load P (in pounds) that can be safely supported by a horizontal beam varies jointly with the beam's width W and the square of its depth D and inversely with its unsupported length L.
Formula used:
Two variables x and y show inverse variation if they are related as below:
y=ax.
Two variables x and y show direct variation if they are related as below:
y=ax.
z varies jointly with x and y is shown as:
z=axy.
Where, a is a constant.
Explanation:
The load P varies jointly with the beam's width W and the square of its depth D , so
P=aWD2 …… (1)
The load P varies inversely with its unsupported length L , so
P=aL …… (2)
From (1) and (2),
P=aWD2L
Now, if the width and length of the beam are doubled, then
P=a2WD22L=aWD2L
Therefore, there will be no change in P.
(b)
To determine: The change in P when the width and depth of the beam are doubled.
The value of P will increase by eight times.
Given information:
The load P (in pounds) that can be safely supported by a horizontal beam varies jointly with the beam's width W and the square of its depth D and inversely with its unsupported length L.
Formula used:
Two variables x and y show inverse variation if they are related as below:
y=ax.
Two variables x and y show direct variation if they are related as below:
y=ax.
z varies jointly with x and y is shown as:
z=axy.
Where, a is a constant.
Explanation:
The load P varies jointly with the beam's width W and the square of its depth D , so
P=aWD2 …… (1)
The load P varies inversely with its unsupported length L , so
P=aL …… (2)
From (1) and (2),
P=aWD2L
Now, if the width and depth of the beam are doubled, then
P=a(2W)(2D)2L=8aWD2L
Therefore, the value of P will increase by eight times.
(c)
To determine: The change in P when all the three dimensions are doubled.
The value of P will increase by four times.
Given information:
The load P (in pounds) that can be safely supported by a horizontal beam varies jointly with the beam's width W and the square of its depth D and inversely with its unsupported length L.
Formula used:
Two variables x and y show inverse variation if they are related as below:
y=ax.
Two variables x and y show direct variation if they are related as below:
y=ax.
z varies jointly with x and y is shown as:
z=axy.
Where, a is a constant.
Explanation:
The load P varies jointly with the beam's width W and the square of its depth D , so
P=aWD2 …… (1)
The load P varies inversely with its unsupported length L , so
P=aL …… (2)
From (1) and (2),
P=aWD2L
Now, if all the three dimensions are doubled, then
P=a(2W)(2D)22L=4aWD2L
Therefore, the value of P will increase by four times.
(d)
To determine: The ways a beam can be modified if the safe load it is required to support is increased by a factor of 4.
The unsupported length will be multiplied by the same factor of 4.
Given information:
The load P (in pounds) that can be safely supported by a horizontal beam varies jointly with the beam's width W and the square of its depth D and inversely with its unsupported length L.
Formula used:
Two variables x and y show inverse variation if they are related as below:
y=ax.
Two variables x and y show direct variation if they are related as below:
y=ax.
z varies jointly with x and y is shown as:
z=axy.
Where, a is a constant.
Explanation:
Consider the equation P=aWD2L.
The factors of 4=1,2, and 4.
If the safe load it is required to support is increased by 2 , then
2P=aWD2LP=aWD22L
If the safe load it is required to support is increased by 4 , then
4P=aWD2LP=aWD24L
Therefore, if the safe load it is required to support is increased by a factor of 4 then the unsupported length will be multiplied by the same factor of 4.
Chapter 5 Solutions
Holt Mcdougal Larson Algebra 2: Student Edition 2012
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