Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Chapter 5, Problem 5.68P
Interpretation Introduction
Interpretation:
It is to be explained how the results of specific reactions carried out on
Concept introduction:
A chiral compound contains at least one carbon which is bonded to four different atoms or groups. D-sugar is one in which the
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Students have asked these similar questions
(g) Using appropriate prefixes/infixes/suffixes (ketoheptose, aldoheptose, etc.), classify each of
the monosaccharides shown below.
CHO
CH2OH
Но
IH
но-
HO-
HO-
HO
H.
CH2OH
CH2OH
I
II
(h) Identify B-D-altrose and a-D-altrose from the monosaccharides shown below.
CH2OH
CH2OH
CH2OH
CH2OH
OH
OH
OH
ОН
OH
ОН
ОН
OH
OH
OH
OH
OH
OH
OH
OH
OH
I
II
II
IV
(i) Identify B-D-altrose and a-D-altrose from the monosaccharides shown below.
VI
I CH2OH O
CH2OH
II
H
V
ОН,
III
IV
OH
OH
H
5. Provide suitable responses for questions (a) – ().
6 CH2OH
4
OH
OH
3
OH
(a) What is the relative configuration of the above monosaccharide?
(b) Which labeled carbon is the anomeric carbon?
(c) Trace and identify the acetal in the above monosaccharide.
(d) Draw the hemiacetal that results from above acetal.
(e) Draw the open chain equivalent of the sugar in part (d).
(f) Classify the monosaccharide below as a D-sugar or an L-sugar.
H.
OH
O.
OH
CH,OH
OH
OH
4. An iterative approach to oligosaccharide synthesis involves the use of protected glycals (sugars with
C1-C2 double bond) as shown below. The product from the reaction of the first glycal with DMDO under
anhydrous conditions is treated with another suitably-protected glycal to form a disaccharide glycal, and
the process can be repeated to form a trisaccharide glycal, and so on... Crucial to the success of this
approach is the stereoselective formation of the intermediate A in the scheme below. Draw the
structure of A.
DMDO
CH₂Cl2
A
OH
ZnCl₂, THF
OH
Chapter 5 Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
Ch. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. 5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. 5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10P
Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. 5.32PCh. 5 - Prob. 5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. 5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. 5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. 5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. 5.48PCh. 5 - Prob. 5.49PCh. 5 - Prob. 5.50PCh. 5 - Prob. 5.51PCh. 5 - Prob. 5.52PCh. 5 - Prob. 5.53PCh. 5 - Prob. 5.54PCh. 5 - Prob. 5.55PCh. 5 - Prob. 5.56PCh. 5 - Prob. 5.57PCh. 5 - Prob. 5.58PCh. 5 - Prob. 5.59PCh. 5 - Prob. 5.60PCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67PCh. 5 - Prob. 5.68PCh. 5 - Prob. 5.69PCh. 5 - Prob. 5.70PCh. 5 - Prob. 5.71PCh. 5 - Prob. 5.72PCh. 5 - Prob. 5.73PCh. 5 - Prob. 5.74PCh. 5 - Prob. 5.75PCh. 5 - Prob. 5.76PCh. 5 - Prob. 5.77PCh. 5 - Prob. 5.78PCh. 5 - Prob. 5.79PCh. 5 - Prob. 5.1YTCh. 5 - Prob. 5.2YTCh. 5 - Prob. 5.3YTCh. 5 - Prob. 5.4YTCh. 5 - Prob. 5.5YTCh. 5 - Prob. 5.6YTCh. 5 - Prob. 5.7YTCh. 5 - Prob. 5.8YTCh. 5 - Prob. 5.9YTCh. 5 - Prob. 5.10YTCh. 5 - Prob. 5.11YTCh. 5 - Prob. 5.12YTCh. 5 - Prob. 5.13YTCh. 5 - Prob. 5.14YTCh. 5 - Prob. 5.15YTCh. 5 - Prob. 5.16YTCh. 5 - Prob. 5.17YT
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- The most stable conformation of the pyranose ring of most D-aldohexoses places the largest group, CH2OH, in the equatorial position. An exception to this is the aldohexose D-idose. Draw the two possible chair conformations of either the a or ß anomer of D-idose. Explain why the more stable conformation has the CH2OH group in the axial position.arrow_forwardConsider the following compound, which is used by insects and some fungi to store energy:arrow_forwardDraw the isomers for each aldotetrose and ketopentose in the figure below and designate each isomer as a D or L sugar and designate also the R and S in every chiral centers. Label the enantiomers and diastereomers respectively. CH,OH C=0 Н—С—ОН Н-С—ОН Н—С—ОН H-C-OH ČH,OH ČH,OHarrow_forward
- b) Compounds A and B have the following properties: Compound A (C5H1005) is an optically active D-pentose that exists exclusively as an acyclic molecule. (Hint: that sentence alone completely determines the structure of A! But we generously give you more information.) • Compound A does not react with Br₂/H₂O. • Reduction of A with NaBH4 gives only one product, B (C5H12O5), which is optically active. Write acyclic Fischer projection structures of A and B.arrow_forwardClassify the following monosaccharides as an aldose or ketose. I need help on number 5, a-d.arrow_forwardThe disaccharide lactose is built up by one D-galacto- and one D-gluco monosaccharide unit. Draw L-galactose in the Fischer projection (open) form and in its most stable pyranose ring conformation form and determine if the latter is a 1C4 or a 4C1 conformation.arrow_forward
- Two sugars differing in configuration at a single asymmetric carbon atom are known as epimers. D-mannose is a C-2 epimer of glucose (Structure I), while D-galactose is a C-4 epimer of glucose. Structure Il and IIl are H- -OH но- -H H OH HO H но- H HO H H -OH H- -OH HO OH H -OH H- -OH H OH HO. HO, OH II II Which of the following represents an aldopentose? OH H O HO O HO H но н HO H но- HO H HO H HO- H OH H OH H OH H OH OH HO Он of но" HO O OH он III IV These are chemical messengers that are secreted by endocrine glands and carried through the bloodstream to target tissues. prostaglandin deoxysugar glycoside hormones Which of the following is NOT correctly paired? cellulose: beta-1,4-glycosidic linkage amylose: alpha-1,4-glycosidic linkage chitosan: alpha-1,4-glycosidic linkage cellubiose: beta-1,4-glycosidic linkagearrow_forwarda) The D-aldopentose A, C5H1005, reacts with HNO3 to yield an optically active aldaric acid B. Kiliani-Fischer chain extension of A produces a pair of D-aldohexoses C and D. C is converted by HNO3 to an optically active aldaric acid, but D is converted by HNO3 to an optically inactive aldaric acid. Write acyclic Fischer projections for A, B, C, D. b) Disaccharide E is a reducing sugar. It is hydrolyzed by an α-glycosidase enzyme, which means it contains an α- glycoside link. Treatment of E with Ag2O and excess Mel gives an octamethyl derivative F. Hydrolysis of F in dilute aqueous acid gives the pair of molecules shown below. Write the structures of E and F. (If the stereochemistry at a particular carbon is not determined by the above data, indicate this with a wavy line as shown below.) HO OMe OMe MeO MeO MOH OMe mOH OMe OMearrow_forwarda) The D-aldopentose A, C5H1005, reacts with HNO3 to yield an optically active aldaric acid B. Kiliani-Fischer chain extension of A produces a pair of D-aldohexoses C and D. C is converted by HNO3 to an optically active aldaric acid, but D is converted by HNO3 to an optically inactive aldaric acid. Write acyclic Fischer projections for A, B, C, D.arrow_forward
- OH ОН Which monosaccharide has a greater heat of combustion, B-D-glucopyranose or B-D-allopyranose? Explain. но НО Но OH OH OH OH OH B-D-Glucopyranose B-D-Allopyranosearrow_forwardThe structure of 4 isomers of an aldotetrose carbohydrate are given. 1) select every structure that is a diastereomer of structure D A, B, or C? 2) select every structure that is a enantiomer of structure C D, B, or A? 3) select every structure that is a stereoisomer of structure D A, B, or Carrow_forwardDraw the structures (using chair conformations of pyranoses) of the following disaccharides.(a) 4-O-(a-d-glucopyranosyl)-d-galactopyranose(arrow_forward
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