Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 5, Problem 5.4P
To determine
Find the maximum dry unit weight of compaction and the optimum moisture content.
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The results of a standard Proctor test are given in the following table. Determine the maximum dry unit weight of compaction and the optimum moisture content. Also determine the moisture content required to achieve 90% of ꙋd (max).
Q7: The Table 4 shows the results of a Standard Proctor Compaction test.
Satisfactory
Y
Based on the information provided, determine the following values.
The maximum dry unit weight and the OMC.
The degree of saturation at the maximum dry density if Gs = 2.70.
What is the dry unit weight and the moisture range at 95% relative compaction
(RC)?
The degree of saturation at the maximum dry density if Gs = 2.70.
Table 4: Results of a standard Proctor compaction test
Trial No.
1
4
13.2
Moisture content, w (%)
6.2
8.1
9.8
11.5
12.3
20.1
Bulk unit weight (kN/m³)
16.9
18.7
19.5
20.5
20.4
17.8
Dry unit weight (kN/m³)
15.9
17.3
17.8
18.4
18.2
The results of a standard Proctor test are given in the following table. Determine the maximum dry unit weight of compaction and the optimum moisture content. Also determine the moisture content required to achieve 95% of γd(max). Calculate and plot the 80% and 100% saturation lines.
Chapter 5 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
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- the following data have been obtained in a standard laboratory proctor compaction test : Trial No. moisture content. % 1 9 2 3 4 6 11.9 14.6 15-8 19.0 21.6 weight of container and compacted soil 137.43 38.16 38-67 38-8439-06 38.76 (N) The container is 943 cm³ ih volume and its weight is 201 A-Determine the optimum moisture content and the maximum dry unit weight B-what is the dry uhit weight and water content at 95% standard compaction in the field ?arrow_forwardA standard compaction test was performed in the laboratory and the results are tabulated as follows: 3 4 Trial Number 1 2 Moist Unit Weight (Ib/ft) 120.2 128.4 134.2 134.4 130.9 Moisture Content (%) 7.1 10.0 13.4 16.7 20.1 Determine the soil's optimum moisture content (%) LOarrow_forwardThe results of a standard and a modified Proctor tests ate given in the table below. a) Generate a plot of dry unit weight as a function of water content including the zero air voids (ZAV) curve (note that the units are in cm³ and kg). b) Determine the maximum dry unit weight of compaction and the optimum moisture content. Show calculation on how to determine the maximum dry density and the optimum moisture content. STANDARD PROCTOR TEST DATA MODIFIED PROCTOR TEST DATA Volume of Mass of Wet Soil Water Content, Mass of wet soil Water Content, Mold (cm?) in the mold (kg) wC in the mold (kg) wC 1.68 0.099 1.83 0.059 1.71 0.106 1.89 0.066 1.77 0.121 1.95 0.081 1.83 0.138 2.00 0.098 943.3 1.86 0.151 2.03 0.111 1.88 0.174 2.05 0.134 1.87 0.194 2.04 0.154 1.85 0.212 2.00 0.172arrow_forward
- A standard compaction test was performed in the laboratory and the results are tabulated as follows: Trial Number 1 2 3 4 5 Moist Unit Weight (Ib/ft) 120.2 128.4 134.2 134.4 130.9 Moisture Content (%) 7.1 10.0 13.4 16.7 20.1 Determine the soil's maximum dry unit weight (drawing a plot may prove useful)arrow_forwardDetermine the maximum dry unit weight of compaction and the optimum moisture content for the results of a standard proctor test that is shown in the table below.arrow_forward6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 943.3 1.68 9.9 2 943.3 1.71 10.6 3 943.3 1.77 12.1 943.3 1.83 13.8 943.3 1.86 15.1 6. 943.3 1.88 17.4 7 943.3 1.87 19.4 943.3 1.85 21.2arrow_forward
- A compacted fill with a unit weight of 121 lb/ft^3 and a moisture content of 12.5% will be used for construction of a warehouse. Proctor compaction test was performed on a sample of the fill material. The test results revealed a maximum dry unit weight of 117 lb/ft^3 and an optimum moisture content of 13.0%. Compute the relative compaction based on the results of the Proctor compaction test.arrow_forward6. Following is the result of 8 trials of à standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 943.3 1.68 9.9 2 943.3 1.71 10.6 943.3 1.77 12.1 4 943.3 1.83 13.8 943.3 1.86 15.1 6 943.3 1.88 17.4 943.3 1.87 19.4 8 943.3 1.85 21.2arrow_forwardThe following are the data of the compaction test: Volume of mold = 0.000945 m^3 Determine the degree of saturation at the optimum moisture content if Gs= 2.60arrow_forward
- The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold (cu.m) Wt. of wet soil in mold (kg) Moisture (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture contentarrow_forwardA modified proctor compaction test is performed on a sample of silty sand in a 150 mm diameter mold. The maximum dry unit weight is 19.6 kN/m3 and optimum water content is 11%. If the specific gravity solids is 2.65, draw the three-phase diagram of the sample in the mold and calculate all volumes and weight for that sample. What is the degree of saturation?arrow_forwardTwo types of compaction tests are typically performed in the laboratory. These tests are the standard proctor test and the modified proctor test. O True Falsearrow_forward
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