Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 5, Problem 5.13P
To determine
Find the maximum relative density of compaction.
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A cylindrical specimen of dry sand with a minimum and maximum void ratio (emin and emax) of 0.5 and 0.8 respectively has a relative density of 45%. If the specimen is compacted such that the relative density is 60%, what will be the decrease in height of the sample if the initial height was 15cm?
Assume that the specimen diameter remains constant such that any volume change occurs only as a change in height.
Data from an oedometer test for a clay layer are plotted in the graph shown below. Calculate the compression index of the clay specimen. (Answer tolerance = 2%). Data points not to scale.
A consolidated-undrained tri-axial test was conducted on a normally conslidated clay sample and the results are follows:
Chamber confining pressure= 119kpa
Deviator Stress at failure=90 kpa
Pore water pressure= 58kpa
These results were used to determine the drained friction angle of the soil. Compute the deviator stress (kpa) at failure when the drained test was conducted with the chamber confining pressure changed to 156 kpa.
Use stored value. Answer to 5 decimal places.
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Fundamentals of Geotechnical Engineering (MindTap Course List)
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- (From Chapter 7) 6. A sample of normally consolidated clay was obtained by a Shelby tube sampler from the midheight of a normally consolidated clay layer (see Figure 7-34). A consolidation test was conducted on a portion of this sample, the results of which are given as follows: FIGURE 7-34 Water Table 9 ft. square Sand and Gravel Unit Weight = 120 lb/ft³ Normally Consolidated Clay Unit Weight = 103 lb/ft³ Gravel and Sand Unit Weight = 125 lb/ft³ p (tons/ft²) 0.250 0.500 1.00 2.00 4.00 8.00 16.00 e Elevation 100 ft 1.72 1.70 1.64 1.51 1.34 1.15 0.95 Elevation 94 ft 1. Natural (initial) void ratio of the clay existing in the field (eo) = 1.80. 2. Pressure-void ratio relationships are as follows: Elevation 85 ft Elevation 76 ft A footing is to be constructed 6 ft below ground surface, as shown in Figure 7-34. The base of the footing is 9 ft by 9 ft, and it carries a total load of 200 tons, which includes the column load, weight of footing, and weight of soil surcharge on the footing. a.…arrow_forwardGiven: Weight of wet sand sample (Ww) = 500 g Weight of Dry sand sample (Wd) = 490 g Moisture content of the given sand is: 5% 4% 2% 1%arrow_forwardThe height of the sample sand to be tested = 20 cm and the height of the saturated sand = 16 cm. Find the bulking of sand. 1. 20% 2. 55.5% 3. 25% 4. 80%arrow_forward
- 6 A consolidated-undrained test was conducted on a normally consolidated clay sample. The results are as follows: Undrained angle of friction = 36.90°, Drained angle of friction = 67.62°, Deviator stress at failure = 573 lb/ft^2. Determine the pore water stress at failure in lb/ft^2. Round off to three decimal places.arrow_forward4.15 The following results were obtained from a liquid limit test on a clay using the Casagrande cup device. Number of blows 6 12 20 28 32 Water content (%) 52.5 47.1 43.2 38.6 37.0 (а) Determine the liquid limit of this clay. (b) If the natural water content is 38% and the plastic limit is 23%, calculate the liquidity index. (c) Do you expect a brittle type of failure for this soil? Justify your answer.arrow_forwardFor a sand with 4% finer than No. 200 sieve, estimate the maximum relative density ofcompaction that may be obtained from a modified Proctor test. Given D50 = 1.4 mm.arrow_forward
- 1. A wet sand sample has a volume of 4.64 x 10⁻⁴ and weighs 8N. After oven drying, the weight reduces to 7.5N. Calculate the water content, void ratio and degree of saturation.(use Gs = 2.7) 2. A contractor has compacted the base course for a new road and found that the mean value of the test sample shows, w = 14.6%, Gs =2.81, and γ= 18.2 KN/m³. The specification require thate ≤0.8. has the contractor complied with the specifications? 3. The moist unit weight of soil is 16.5 KN/m³. Given that the w=15% and Gs = 2.70. Find:1) dry unit weight2) porosity3) degree of saturationarrow_forwardFollowing are the results of a consolidation test on a sample of undisturbed clay obtained from the field. Pressure ơ' (kN/m²) Final Height of Specimen (mm) 24 10 23.78 20 23.30 50 22.22 100 20.58 200 19.04 400 17.52 800 16.31 17.75 The height of the specimen at the beginning of the test was 24 mm and the area of specimen was 50 cm? volume of specimen was 120 cm³. The mass of dry specimen was 180.4 g. Gs= 2.68. 1. Plot the e-log ơ' curve, 2. Using Casagrande's method, determine the preconsolidation pressure. 3. Calculate the compression index, Ccarrow_forwardA consolidated-undrained test was conducted on a normally consolidated clay sample. The results are as follows: Undrained angle of friction = 38.65°, Drained angle of friction = 62.59°, Deviator stress at failure = 509 lb/ft^2. Determine the pore water stress at failure in lb/ft^2.arrow_forward
- A consolidated-undrained test was conducted on a normally consolidated clay sample. The results are as follows: Undrained angle of friction = 37.16 degrees, Drained angle of friction = 63.71 degrees, Deviator stress at failure = 530 lb/ft^2. Determine the pore water stress at failure in lb/ft^2arrow_forward3- Following are the results of a laboratory consolidation test on a sample of undisturbed clay obtained from the field. Final height of specimen (in) Pressure, o' (lb/ft') 1 0.9917 1,000 2,000 4,000 0.9843 0.956 0.9142 8,000 0.8685 16,000 0.8228 32.000 The height of the specimen at the beginning of the test was 1.0 inch, and the diameter was 2.5 inches. The moist specimen weighed 0.31 lb and the water content was determined to be 19%. Estimate the compression index and the preconsolidation pressure from the e-log o' curve. (Plot in Excel) Given: Gs = 2.7.arrow_forwardZAIN IQ I. Homework 4... During an oedometer test on a specimen of saturated clay, the thickness of the specimen decreased from 19.931 mm to 19.720 mm under an increment of stress from 200 to 400 kPa which was maintained for 24 hours. The stress was then removed from the specimen, its thickness was measured water content determined as 26.8%. 19.842 mm, and its Taking Gs of the particles to be 2.70, calculate the void ratio before and after the application of the stress increment, and the coefficient of volume decrease (m,) for this stress range. (Ans: e,= 0.731, e2= 0.713, m, = 0.052 m/MN)arrow_forward
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