Explanation Formula used: The expression for current is as follows, i = v R (1) Here, i is the current, v is the voltage and R is the resistance. Calculation: The circuit diagram is redrawn as shown in Figure 1, Refer to the redrawn Figure 1, For 2 V independent voltage source, Voltage source with series resistor can be converted in current source with same resistor connected in parallel. Substitute 2 V for v and 6 Ω for R in equation (1), i 2 = 2 V 6 Ω = 1 3 A So value of current i 2 is 1 3 A . For dependent voltage source, Substitute 2 v 3 for v and 2 Ω for R in equation (1), i = 2 v 3 V 2 Ω = v 3 A So value of dependent current source i 2 is v 3 A . The circuit diagram after source transformation is redrawn as shown in Figure 2, Refer to the redrawn Figure 2, The expression for KCL at node A is as follows, − i 2 + v A R 1 + i 1 + v A − v B R 2 = 0 (2) Here, v A is the voltage at node A , v B is the voltage at node B , i 2 and i 1 are the currents in the circuit and R 1 and R 2 are the resistances in the circuit. The expression for KCL at node B is as follows, v B − v A R 2 + v B R 3 − i 3 = 0 (3) Here, v A is the voltage at node A , v B is the voltage at node B , i 3 is the current in the circuit and R 2 and R 3 are the resistances in the circuit. The expression for voltage v 3 is as follows, v 3 = v A − v B (4) Here, v 3 , v A and v B are the voltages in the circuit. Substitute 1 3 A for i 2 , 6 Ω for R 1 , 4 v 3 for i 1 and 3 Ω for R 2 in equation (2), − 1 3 A + v A 6 Ω + 4 v 3 + v A − v B 3 Ω = 0 − 2 V+ v A + 24 v 3 + 2 ( v A − v B ) 6 Ω = 0 3 v A − 2 v B + 24 v 3 − 2 V 6 Ω = 0 (5) Rearrange equation (5), 3 v A − 2 v B + 24 v 3 = 2 V

Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf

9th Edition

ISBN: 9781259989452

Author: Hayt

Publisher: Mcgraw Hill Publishers

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Z parameter

The Z-parameters that are the impedance parameters of a two-port network are defined by expressing the two-port voltages V1 and V2 in terms of two-port currents I1 and I2. The Z-parameters are calculated by open circuiting one of the two ports at a time …

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Chapter 5, Problem 24E

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Chapter 5, Problem 23E

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Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf

Ch. 5.1 - For the circuit of Fig. 5.4, use superposition to...Ch. 5.2 - For the circuit of Fig. 5.7, use superposition to...Ch. 5.2 - For the circuit of Fig. 5.18, compute the current...Ch. 5.2 - For the circuit of Fig. 5.20, compute the voltage...Ch. 5.3 - Using repeated source transformations, determine...Ch. 5.3 - Use Thvenins theorem to find the current through...Ch. 5.3 - Determine the Thvenin and Norton equivalents of...Ch. 5.3 - Find the Thvenin equivalent for the network of...Ch. 5.3 - Find the Thvenin equivalent for the network of...Ch. 5.4 - Consider the circuit of Fig. 5.43. FIGURE 5.43...

Ch. 5.5 - Prob. 11P Ch. 5 - Linear systems are so easy to work with that...Ch. 5 - Prob. 2E Ch. 5 - Prob. 3E Ch. 5 - (a) Employ superposition to determine the current...Ch. 5 - (a) Using superposition to consider each source...Ch. 5 - (a) Determine the individual contributions of each...Ch. 5 - (a) Determine the individual contributions of each...Ch. 5 - After studying the circuit of Fig. 5.53, change...Ch. 5 - Consider the three circuits shown in Fig. 5.54....Ch. 5 - (a) Using superposition, determine the voltage...Ch. 5 - Employ superposition principles to obtain a value...Ch. 5 - (a) Employ superposition to determine the...Ch. 5 - Perform an appropriate source transformation on...Ch. 5 - (a) For the circuit of Fig. 5.59, plot iL versus...Ch. 5 - Determine the current labeled I in the circuit of...Ch. 5 - Verify that the power absorbed by the 7 resistor...Ch. 5 - (a) Determine the current labeled i in the circuit...Ch. 5 - (a) Using repeated source transformations, reduce...Ch. 5 - Prob. 19E Ch. 5 - (a) Making use of repeated source transformations,...Ch. 5 - Prob. 21E Ch. 5 - (a) With the assistance of source transformations,...Ch. 5 - For the circuit in Fig. 5.67 transform all...Ch. 5 - Prob. 24E Ch. 5 - (a) Referring to Fig. 5.69, determine the Thevenin...Ch. 5 - (a) With respect to the circuit depicted in Fig....Ch. 5 - (a) Obtain the Norton equivalent of the network...Ch. 5 - (a) Determine the Thevenin equivalent of the...Ch. 5 - Referring to the circuit of Fig. 5.71: (a)...Ch. 5 - Prob. 30E Ch. 5 - (a) Employ Thvenins theorem to obtain a...Ch. 5 - Prob. 32E Ch. 5 - Determine the Norton equivalent of the circuit...Ch. 5 - For the circuit of Fig. 5.75: (a) Employ Nortons...Ch. 5 - (a) Obtain a value for the Thvenin equivalent...Ch. 5 - Prob. 36E Ch. 5 - Obtain a value for the Thvenin equivalent...Ch. 5 - With regard to the network depicted in Fig. 5.79,...Ch. 5 - Determine the Thvenin and Norton equivalents of...Ch. 5 - Determine the Norton equivalent of the circuit...Ch. 5 - Prob. 41E Ch. 5 - Determine the Thvenin and Norton equivalents of...Ch. 5 - Prob. 43E Ch. 5 - Prob. 44E Ch. 5 - Prob. 45E Ch. 5 - (a) For the simple circuit of Fig. 5.87, find the...Ch. 5 - For the circuit drawn in Fig. 5.88, (a) determine...Ch. 5 - Study the circuit of Fig. 5.89. (a) Determine the...Ch. 5 - Prob. 49E Ch. 5 - Prob. 50E Ch. 5 - With reference to the circuit of Fig. 5.91, (a)...Ch. 5 - Prob. 52E Ch. 5 - Select a value for RL in Fig. 5.93 such that it...Ch. 5 - Determine what value of resistance would absorb...Ch. 5 - Derive the equations required to convert from a...Ch. 5 - Convert the - (or "-") connected networks in Fig....Ch. 5 - Convert the Y-(or T-) connected networks in Fig....Ch. 5 - For the network of Fig. 5.97, select a value of R...Ch. 5 - For the network of Fig. 5.98, select a value of R...Ch. 5 - Prob. 60E Ch. 5 - Calculate Rin as indicated in Fig.5.100. FIGURE...Ch. 5 - Employ Y conversion techniques as appropriate to...Ch. 5 - Prob. 63E Ch. 5 - (a) Use appropriate techniques to obtain both the...Ch. 5 - (a) For the network in Fig. 5.104, replace the...Ch. 5 - Prob. 66E Ch. 5 - Prob. 67E Ch. 5 - A 2.57 load is connected between terminals a and...Ch. 5 - A load resistor is connected across the open...Ch. 5 - A backup is required for the circuit depicted in...Ch. 5 - (a) Explain in general terms how source...Ch. 5 - The load resistor in Fig. 5.108 can safely...Ch. 5 - Prob. 74E Ch. 5 - As part of a security system, a very thin 100 ...Ch. 5 - With respect to the circuit in Fig. 5.90, (a)...

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Find value of voltage v 3 after transforming both voltage sources to current sources.

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Find value of voltage v3<m:math><m:mrow><m:msub><m:mi>v</m:mi><m:mn>3</m:mn></m:msub></m:mrow></m:math> after transforming both voltage sources to current sources.

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Find value of voltage $v3$ after transforming both voltage sources to current sources.