Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Textbook Question
Chapter 5, Problem 18P
The
a. From these data, can you conclude that Rh and
b. What is
c. Over what range of w do lod scores indicate significantevidence in favor of genetic linkage?
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The mother of a family with 10 children has blood typeRh+. She also has a very rare condition (elliptocytosis,phenotype E) that causes red blood cells to be oval rather than round in shape but that produces no adverseclinical effects. The father is Rh− (lacks the Rh+ antigen)and has normal red blood cells (phenotype e). The children are 1 Rh+ e, 4 Rh+ E, and 5 Rh− e. Information isavailable on the mother’s parents, who are Rh+ E andRh− e. One of the 10 children (who is Rh+ E) marriessomeone who is Rh+ e, and they have an Rh+ E child.a. Draw the pedigree of this whole family.b. Is the pedigree in agreement with the hypothesisthat the Rh+ allele is dominant and Rh− is recessive?c. What is the mechanism of transmission ofelliptocytosis?d. Could the genes governing the E and Rh phenotypesbe on the same chromosome? If so, estimate the mapdistance between them, and comment on your result
autosomal recessive allele (not sex-linked).
Omplete the following monohybrid crosses for different types
neritance pattefh
autosomal dominant, sex linked recessive, and
dominant inheritance.
Inheritance of autosomal recessive traits
Female parent phenolype:
Example: Albinism
Albinism (lack of pigment in hair, eyes and skin) is inherited as an
Male parent phenatype:
Using the codes: PP
Pp
(normal)
(albino)
la) Enter the parent phenotypes and complete the Punnett
square for a cross between two carrier genotypes.
A Give the ratios for the phenotypes from this cross.
Pp (carrier)
eggs
sperm
Phenotype ratios:
Inheritance of autosomal dominant traits
Example: Woolly hair
Woolly hair is inherited as an autosomal dominant allele. Each
affected individual will have at least one affected parent.
Using the codes: WW (woolly hair)
Female parent phenotype:
Male parent phenotype:
Ww
(woolly hair, heterozygous)
W
w
(normal hair)
(a) Enter the parent phenotypes and complete the Punnett
square for a…
Mutations in the genes for clotting factor VIII and IX cause hemophilia A and B, respectively. A woman may be heterozygous for mutations in both genes, with a mutated factor VIII allele on one X chromosome, and a mutated factor IX allele on the other. All of her sons should have either hemophilia A or B. However, on rare occasions, one of these women gives birth to a son who does not have hemophilia, and his one X chromosome does not have either mutated allele. Explain.
Chapter 5 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 5 - For parts a, b, and c, draw a diagram illustrating...Ch. 5 - 5.2 In a diploid species of plant, the genes for...Ch. 5 - A pure-breeding tall plant producing oval fruit as...Ch. 5 - 5.4 Genes E and H are syntenic in an experimental...Ch. 5 - In tomato plants, purple leaf color is controlled...Ch. 5 - 5.6 In Drosophila, the map positions of genes are...Ch. 5 - 5.7 Genes A, B, and C are linked on a chromosome...Ch. 5 - Gene G recombines with gene T at a frequency of...Ch. 5 - Genes A, B, C, D, and E are linked on a...Ch. 5 - Syntenic genes can assort independently. Explain...
Ch. 5 - 5.11 The recombination frequency between linked...Ch. 5 - On the DrosophilaX chromosome, the dominant allele...Ch. 5 - Researchers cross a corn plant that is pure -...Ch. 5 - 5.14 syndrome is an autosomal disorder affecting...Ch. 5 - 5.15 Three dominant traits of corn seedlings,...Ch. 5 - 5.16 In a diploid plant species, an with the...Ch. 5 - Prob. 17PCh. 5 - The Rh blood group in humans is determined by a...Ch. 5 - 5.19 Genetic linkage mapping for a large number of...Ch. 5 - 5.20 with the genotype form tetrads in the...Ch. 5 -
Gene and gene are genetically linked. Answer...Ch. 5 -
T. H. Morgan’s data on eye color and wing form,...Ch. 5 - Prob. 23PCh. 5 -
The boss in your laboratory has just heard of a...Ch. 5 - In rabbits, chocolate-colored fur (w+) is dominant...Ch. 5 - Prob. 26PCh. 5 - 5.27 In tomatoes, the allele for tall plant height...Ch. 5 - 5.28 Neurofibromatosis is an autosomal dominant...Ch. 5 - A 2006 genetic study of a large American family...Ch. 5 - 5.30 A experiment examining potential genetic...Ch. 5 - A genetic study of an early onset form of heart...Ch. 5 - In experiments published in 1918 that sought to...Ch. 5 - DNA sequence for 10 individuals are Identify the...Ch. 5 - 5.34 The accompanying pedigree below shows a...Ch. 5 - 5.35 Based on previous family studies, an...Ch. 5 - Divide a clean sheet of paper into four quadrant...Ch. 5 - 5.37 For six genes known to be linked on chromosme...
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- Achondroplasia is a rare dominant autosomal defect resulting in dwarfism. The unaffected brother of an individual with achondroplasia is seeking counsel on the likelihood of his being a carrier of the mutant allele. What is the probability that the unaffected client is carrying the achondroplasia allele?arrow_forwardState whether each of the following genetic defects is inherited as an autosomal recessive, autosomal dominant, or X-linked recessive trait: phenylketonuria (PKU), sickle cell anemia, cystic fibrosis, Tay-Sachs disease, Huntingtons disease, and hemophilia A.arrow_forwardA couple are both phenotypically normal but their son suffers from hemophilla, a sex linked recessive disorder. What fraction of their children are likely to suffer from hemophilia. what fraction are likely to be carriers.arrow_forward
- Describe the genetics of Hemophilia A O Disease-causing alleles are full or partial loss-of-function alleles Late age of onset Recessive Rare O X-linked Autosomal Dominantarrow_forwardRhesus factor is a protein found onlthe surface of the red blood cells. Having Rhesus factor (Rh+) is dominant over having none (Rh-). What cross could result to Rhesus factor incompatibility? Rh- mother x Rh+ father O Rh- father x Rhesus+ mother O Rh- mother x Rh- father O Rh+ father x Rh+ motherarrow_forwardThe gene that is responsible for producing clotting factor VIII is located on the X chromosome. A recessive mutation in this gene causes the most common type of hemophilia; it is known as hemophilia A. If this gene is mutated in the hemophilia, but it will always cause this type of hemophilia if mutated in the This is because have two X chromosomes; since this is a recessive mutation, more than likely the other X chromosome has the normal gene. View Available Hint(s) Omale: female; females O female: male: females O male; female, males. O child; adult; adults it sometimes causes this type ofarrow_forward
- In humans, the Rh factor genetic information is inherited from our parents, but it is inherited independently of the ABO blood type alleles. In humans, Rh+ individuals have the Rh antigen on their red blood cells, while Rh- individuals do not. There are two different alleles for the Rh factor known as Rh+ and rh. Assume that a dominant gene Rh produces the Rh+ phenotype, and that the recessive rh allele produces the Rh- phenotype. In a population that is in Hardy-Weinberg equilibrium, if 160 out of 200 individuals are Rh+, calculate the frequencies of both alleles.arrow_forwardA woman homozygous for normal height, with freckles, almond-shaped eyes, small nose, and Type A blood, has a Type O mother with no freckles and a type AB father with round eyes. She is engaged to a man with achondroplasia, round eyes and medium sized nose. Unlike his father, hismother is of normal height. Both his parents have Type O blood but nobody from both sides of his family has or had freckles. a. Write the COMPLETE genotypes of the man and the woman. Clearly indicate which genotype belongs to whom. b. Based on their genotypes, what is the probability that they will have: b.1 a child with Achondroplasia? b.2 a child of normal height? b.3 a child with type AB blood? b.4 a daughter with round eyes, freckles, and medium sized nose? b.5 a son with almond eyes, no freckles, and small nose?b.6 a daughter with same genotype as the woman? b.7 a son with same genotype as the man?arrow_forwardb. The following diagram shows a family tree of individuals with haemophilia. B i. Based on an X-linked recessive pattern of inheritance, work out the likely genotypes of the individuals indicated by the letters. Individual A Individual B Individual C GENOTYPE ii. If individual C has children with a normal male, what are the chances that they will have haemophilia? Explain your answer fully. iii. If individual C has children with a normal male, what are the chances that their daughters will be carriers of the condition? Explain your answer fully.arrow_forward
- Review the process of autosomal dominant inheritance by coloring the following figures. In this instance the father is affected in the mother is unaffected to illustrate the transmission of the disorder from the father to the children color the figures as described.arrow_forwardO. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S Farrow_forwardA female patient 19 years old, whose symptoms areanemia and internal bleeding due to a massive buildupof leukemic white blood cells, is diagnosed withchronic myelogenous leukemia (CML). Karyotypeanalysis shows that the leukemic cells of this patientare heterozygous for a reciprocal translocation involving chromosomes 9 and 22. However, none of thenormal, nonleukemic cells of this patient contain thetranslocation. Which of the following statements istrue and which is false?a. The translocation results in the inactivation (loss offunction) of a tumor-suppressor gene.b. The translocation results in the inactivation (loss offunction) of an oncogene.c. There is a 50% chance that any child of this patientwill have CML.d. This patient is a somatic mosaic in terms of thekaryotype.e. DNA extracted from leukemic cells of this patient,if taken up by normal mouse tissue culture cells,could potentially transform the mouse cells intocells capable of causing tumors.f. The normal function of the…arrow_forward
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