A couple are both phenotypically normal but their son suffers from hemophilla, a sex linked recessive disorder. What fraction of their children are likely to suffer from hemophilia. what fraction are likely to be carriers.
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- A form of hemophilia is caused by a sex-linked (X-linked) recessive gene. A phenotypically normal woman whose father had hemophilia marries a man who suffers with hemophilia. What is the probability that their first daughter will have hemophilia?In humans, hemophilia is a sex-linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won’t ever be carriers). X H X H = female, non-hemophilic X H X h = female, carrier X h X h = female, hemophilia X H Y = male, non-hemophilic X h Y= male, hemophiliac a.) Show the cross of a man who has hemophilia with a woman who is a carrier. What is the probability that their children will have the disease? b.) A woman who is a carrier marries a non-hemophilic man. Show the cross. What is the probability that their children will have hemophilia? What sex will a child in the family with hemophilia be? c.) A woman who has hemophilia marries a non-hemophilic man. How many of their children will have hemophilia, and what is their sex?A woman homozygous for normal height, with freckles, almond-shaped eyes, small nose, and Type A blood, has a Type O mother with no freckles and a type AB father with round eyes. She is engaged to a man with achondroplasia, round eyes and medium sized nose. Unlike his father, hismother is of normal height. Both his parents have Type O blood but nobody from both sides of his family has or had freckles. a. Write the COMPLETE genotypes of the man and the woman. Clearly indicate which genotype belongs to whom. b. Based on their genotypes, what is the probability that they will have: b.1 a child with Achondroplasia? b.2 a child of normal height? b.3 a child with type AB blood? b.4 a daughter with round eyes, freckles, and medium sized nose? b.5 a son with almond eyes, no freckles, and small nose?b.6 a daughter with same genotype as the woman? b.7 a son with same genotype as the man?
- Hemophilia is a sex-linked recessive trait. A male hemophiliac and phenotypically normal female have a son with hemophilia. They would like to have one more child. What is the probability of having a child without hemophilia? Explain using a Punnett square. Is it possible for a girl to be born with hemophilia? Explain.Hemophilia is due to a sex-linked gene. It is recessive and found on the X chromosome. A woman who is a carrier for hemophilia marries a normal man. What will be the possible phenotypes of their children? (use the letter “H”)O. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S F
- A man with hemophilia (a recessive, sex-linkedcondition) has a daughter without the condition.She marries a man who does not have hemophilia.What is the probability that their daughter willhave hemophilia? Their son? If they have foursons, what is the probability that all will be affected?Suppose a woman who is a carrier of sickle-cell trait (making her a heterozygote) has children with a man who is totally healthy and does not carry the gene for sickle-cell trait at all. Which one of the following is true about their potential children? (Draw a Punnett square on scratch paper if it helps you.) A) None of their children will have sickle-cell disease. B) All of their children will have sickle-cell disease. C) All of the couple's children would be heterozygous carriers like the mother.A form of hemophilia is caused by a sex-linked (X-linked) recessive gene. A phenotypically normal woman whose father had hemophilia marries a phenotypically normal man with no family history of hemophilia. What is the probability that their first son will have hemophilia? 1/4 1 3/4 0 1/2
- Haemophilia A is a severe coagulation disorder that shows X-linked recessive inheritance. Red-green colour blindness also shows X- linked recessive inheritance. A man with both haemophilia A and colour blindness is referred for genetic counselling. Assume that his partner is not a carrier of either of these conditions. Which of the following is correct? OA. The probability that each of his daughters will be a carrier of haemophilia A is 1 in 2. OB. The probability that each of his sons will be affected with haemophilia A is 1 in 2. OC. he probability that each of his daughters will be a carrier of haemophilia A and colour blindness is 1 in 2. D. The probability that each of his sons will be affected with both haemophilia A and colour blindness is 1 in 2. OE. The probability that each of his daughters will be a carrier of both haemophilia A and colour blindness conditions is 1.Hemophilia A, a condition in which blood does not clot properly, is a recessive trait located on the X chromosome (Xh). A woman heterozygous for the trait marries a normal male. What is the probability that this couple will have hemophiliac daughters? What is the probability that this couple will have hemophiliac sons?If a male who is non-hemophiliac is crossed with a female carrier of both colorblindness and hemophilia, what is the probability that a female child will be phenotypically normal?