College Physics
College Physics
OER 2016 Edition
ISBN: 9781947172173
Author: OpenStax
Publisher: OpenStax College
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Chapter 5, Problem 10PE

Calculate the deceleration of a snow boarder going up a 5.0°, slope assuming the coefficient of friction for waxed wood on wet snow. The result of Exercise 5.9 may be useful, but be careful to consider the fact that the snow boarder is going uphill. Explicitly show how you follow the steps in Problem-Solving Strategies.

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Calculate the acceleration along the direction of the motion of a snowboarder that is initially going up a 5.00° slope, assuming the coefficient of friction for waxed wood on wet snow. Express your answer on three significant figures.
Write legibly, provide given, step by step manual solution, and diagram for below given differential equation problem.  A 4-lb body moves in a straight line on horizontal plane whose coefficient of friction is 1/4. The air resistance amounts to v^2/16. The force acting upon the body is 4 lb, if v= 0 when s = 4ft. Find v when s = 12 ft. Use g = 32ft/s^2.    Ans. 6.91 ft/s
Calculate the deceleration of a snow boarder going up a 5.0, slope assuming the coefficient of friction for waxed wood on wet snow. The result of Exercise 5.9 may be useful, but be careful to consider the fact that the snow boarder is going uphill. Explicitly show how you follow the steps in Problem-Solving Strategies.

Chapter 5 Solutions

College Physics

Ch. 5 - Examine different types of shoes, including sports...Ch. 5 - Would you expect your height to be different...Ch. 5 - Why can a squirrel from a tree branch to the...Ch. 5 - Explain why pregnant women often suffer from back...Ch. 5 - An old carpenter's trick to keep nails from...Ch. 5 - When a glass bottle full of vinegar warms up, both...Ch. 5 - A physics major is cooking breakfast when he...Ch. 5 - (a) When rebuilding her car's engine, a physics...Ch. 5 - (a) What is the maximum frictional force in the...Ch. 5 - Suppose you have a 120-kg wooden crate resting on...Ch. 5 - (a) If half of the weight of a small 1.00103 kg...Ch. 5 - A team of eight dogs pulls a sled with waxed wood...Ch. 5 - Consider the 65.0-kg ice skater being pushed by...Ch. 5 - Show that the acceleration of any object down a...Ch. 5 - Show that the acceleration of any object down an...Ch. 5 - Calculate the deceleration of a snow boarder going...Ch. 5 - (a) Calculate the acceleration of a skier heading...Ch. 5 - If an object is to rest on an incline without...Ch. 5 - Calculate the maximum deceleration of a car that...Ch. 5 - Calculate the maximum acceleration of a car that...Ch. 5 - Repeat Exercise 5.14 for a car with four-wheel...Ch. 5 - A freight train consists of two 8.00105 -kg...Ch. 5 - Consider the 52.0-kg mountain climber in Figure...Ch. 5 - A contestant in a winter sporting event pushes a...Ch. 5 - Repeat Exercise 5.18 with the contestant pulling...Ch. 5 - The terminal velocity of a person falling in air...Ch. 5 - A 60-kg and a go-kg skydiver jump from an airplane...Ch. 5 - A 560-g squirrel with a surface area of 930 cm2...Ch. 5 - To maintain a constant speed, the force provided...Ch. 5 - By what factor does the drag force on a car...Ch. 5 - Calculate the speed a spherical rain drop would...Ch. 5 - Using Stokes' law, verify that the units for...Ch. 5 - Find the terminal velocity of a spherical...Ch. 5 - Stokes' law describes sedimentation of particles...Ch. 5 - During a circus act, one performer swings upside...Ch. 5 - During a wrestling match, a 150 kg wrestler...Ch. 5 - (a) The "lead" in pencils is a graphite...Ch. 5 - TV broadcast antennas are the tallest artificial...Ch. 5 - (a) By how much does a 65.0-kg mountain climber...Ch. 5 - A 20.0-m tall hollow aluminum flagpole is...Ch. 5 - As an oil well is drilled, each new section of...Ch. 5 - Calculate the force a piano tuner applies to...Ch. 5 - A vertebra is subjected to a shearing force of 500...Ch. 5 - A disk between vertebrae in the spine is subjected...Ch. 5 - When using a pencil eraser, you exert a vertical...Ch. 5 - To consider the effect of wires hung on poles, we...Ch. 5 - A farmer making grape juice fills a glass bottle...Ch. 5 - (a) When water freezes, its volume increases by...Ch. 5 - This problem returns to the tightrope walker...Ch. 5 - The pole in Figure 5.24 is at a 90.0° bend in a...Ch. 5 - Prob. 1TPCh. 5 - Prob. 2TPCh. 5 - Prob. 3TPCh. 5 - Prob. 4TP

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Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY