Chapter 4.7, Problem 8PPS

To determine

To find: The inverse of the relation $\left\{\left(-5,13\right),\left(6,10.8\right),\left(3,11.4\right),\left(-10,14\right)\right\}$ .

Answer to Problem 8PPS

The inverse of the relation $\left\{\left(-5,13\right),\left(6,10.8\right),\left(3,11.4\right),\left(-10,14\right)\right\}$ is $\left\{\left(13,-5\right),\left(10.8,\right),\left(11.4,3\right),\left(14,-10\right)\right\}$ .

Explanation of Solution

Given:

The relation is $\left\{\left(-5,13\right),\left(6,10.8\right),\left(3,11.4\right),\left(-10,14\right)\right\}$ .

Calculation:

Exchange the x and y coordinates of the given relation $\left\{\left(-5,13\right),\left(6,10.8\right),\left(3,11.4\right),\left(-10,14\right)\right\}$ to obtain the inverse.

$\begin{array}{c}\left(-5,13\right)\to \left(13,-5\right)\\ \left(6,10.8\right)\to \left(10.8,6\right)\\ \left(3,11.4\right)\to \left(11.4,3\right)\\ \left(-10,14\right)\to \left(14,-10\right)\end{array}$

Thus, the inverse of the relation is $\left\{\left(13,-5\right),\left(10.8,\right),\left(11.4,3\right),\left(14,-10\right)\right\}$ .