Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
2nd Edition
ISBN: 9780076602919
Author: McGraw-Hill Education
Publisher: McGraw-Hill Education
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Chapter 4.3, Problem 54PFA

a.

To determine

To write: The equation for the line containing the segment shown.

a.

Expert Solution
Check Mark

Answer to Problem 54PFA

The equation is 3x+5y15=0 .

Explanation of Solution

Given:

The line segment in the graph represents one side of a square.

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 4.3, Problem 54PFA

Calculation:

From the graph it is seen that the line segment is passing through the points (0,-3) and (-5,0).

So the equation of the line passing through these two points can be found out using two-point form, which is given as,

  yy1y2y1=xx1x2x1

So, plugging in the values as x1=0,y1=3,x2=5,y2=0 into the above equation we get,

  y+30+3=x050y+33=x55y15=3x3x+5y+15=0(2)

Conclusion:

Therefore equation 2 is the equation of the line containing the segment.

b.

To determine

To identify: What must be true about the sides adjacent and opposite the segment to form a square?

b.

Expert Solution
Check Mark

Answer to Problem 54PFA

The slope of the side opposite to the segment should be 35 .

And the slopes of the sides adjacent to the segment should be 53 .

Explanation of Solution

Given:

Equation of the line segment is 3x+5y+15=0 .

Calculation:

The segment adjacent to the given segment must have perpendicular slope.

Now, slope of the given segment is,

  m=ABm=35(1)

Slope of the opposite side of the square will be same as that of the above segment i.e. m=35

Now, the slope of the adjacent sides will be perpendicular to the above segment. So,

  m1=1mm1=53(2)

Conclusion:

c.

To determine

To write: The equations of the lines containing the sides of the square adjacent to the segment.

c.

Expert Solution
Check Mark

Answer to Problem 54PFA

1. 5x3y9=0

2. 5x3y+25=0

Explanation of Solution

Given:

Slopes of the lines containing the sides of the square adjacent to the segment has been found above as m1=53 .

Also these lines pass through the points (0,-3) and (-5,0).

Calculation:

Therefore equation of the line passing through the point (0,-3) and having slope m1=53 will be,

  yy1=m1(xx1)

  y+3=53(x0)3y+9=5x

  5x3y9=0(3)

And equation of the line passing through the point (-5,0) and having slope m1=53 will be,

  y0=m1(x+5)y=53(x+5)3y=5x+25

  5x3y+25=0(4)

Conclusion:

d.

To determine

To Find: The equation of the line containing the opposite segment passing through the vertex (3,2).

d.

Expert Solution
Check Mark

Answer to Problem 54PFA

The equation is 3x+5y19=0 .

Explanation of Solution

Given:

The vertex (3,2) lies on the opposite segment.

And the slope of opposite segment we found above as m=35 .

Calculation:

Therefore, the equation of the line passing through the segment having slope m=35 and (3,2) will be,

  yy1=m1(xx1)

  y2=35(x3)5y10=3x+9

  3x+5y19=0 …(5)

e.

To determine

To find: The 4 vertices of the square.

e.

Expert Solution
Check Mark

Answer to Problem 54PFA

The four vertices of the square are (0,-3), (-5,0), (3,2) and (-2,5).

Explanation of Solution

Given:

The three vertices are found above as (0,-3), (-5,0) and (3,2).

Calculation:

The fourth vertex should be the point of intersection of the sides with equations 5x3y+25=0 and 3x+5y19=0

So solve equations 5x3y=25 and 3x+5y=19 simultaneously to find the point of intersection of the two lines.

  5x3y=25 …(A)

  3x+5y=19 …(B)

So, multiplying equation A by 5 and equation B by 3 and then adding them, we get

  34x=68x=6834x=2

Plugging x=2 in equation B, we find the value of y as follows:

  3(2)+5y=196+5y=195y=19+65y=25y=255

  y=5

Therefore, the fourth vertex of the square is (-2,5)

Conclusion:

f.

To determine

To find: The quadrilateral figure is a square or not.

f.

Expert Solution
Check Mark

Answer to Problem 54PFA

The quadrilateral figure is a square.

Explanation of Solution

Given:

The four vertices of the square are given as (0,-3), (-5,0), (3,2) and (-2,5).

Calculation:

Therefore, one diagonal of the square will pass through the vertices (0,-3) and (-2,5).

And the other diagonal will pass through the vertices (-5,0) and (3,2).

Find slope of the diagonal passing through the points (0,-3) and (-2,5) by using,

  m3=y2y1x2x1m3=5+320m3=82m3=4

Find slope of the diagonal passing through the points (-5,0) and (3,2) by using,

  m4=y2y1x2x1m4=203+5m4=28m4=14

Two lines are perpendicular, then the product of their slopes is -1.

And from above,

  m3×m4=(4)(14)m3×m4=1

Conclusion:

Now, since the two diagonals of the quadrilateral are perpendicular, also its adjacent sides are perpendicular to each other, the quadrilateral is a square.

Chapter 4 Solutions

Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)

Ch. 4.1 - Prob. 5CYUCh. 4.1 - Prob. 6CYUCh. 4.1 - Prob. 7CYUCh. 4.1 - Prob. 8CYUCh. 4.1 - Prob. 9CYUCh. 4.1 - Prob. 10PPSCh. 4.1 - Prob. 11PPSCh. 4.1 - Prob. 12PPSCh. 4.1 - Prob. 13PPSCh. 4.1 - Prob. 14PPSCh. 4.1 - Prob. 15PPSCh. 4.1 - Prob. 16PPSCh. 4.1 - Prob. 17PPSCh. 4.1 - Prob. 18PPSCh. 4.1 - Prob. 19PPSCh. 4.1 - Prob. 20PPSCh. 4.1 - Prob. 21PPSCh. 4.1 - Prob. 22PPSCh. 4.1 - Prob. 23PPSCh. 4.1 - Prob. 24PPSCh. 4.1 - Prob. 25PPSCh. 4.1 - Prob. 26PPSCh. 4.1 - Prob. 27PPSCh. 4.1 - Prob. 28PPSCh. 4.1 - Prob. 29PPSCh. 4.1 - Prob. 30PPSCh. 4.1 - Prob. 31PPSCh. 4.1 - Prob. 32PPSCh. 4.1 - Prob. 33PPSCh. 4.1 - Prob. 34PPSCh. 4.1 - Prob. 35PPSCh. 4.1 - Prob. 36PPSCh. 4.1 - Prob. 37PPSCh. 4.1 - Prob. 38PPSCh. 4.1 - Prob. 39PPSCh. 4.1 - Prob. 40PPSCh. 4.1 - Prob. 41PPSCh. 4.1 - Prob. 42PPSCh. 4.1 - Prob. 43PPSCh. 4.1 - Prob. 44PPSCh. 4.1 - Prob. 45PPSCh. 4.1 - Prob. 46PPSCh. 4.1 - Prob. 47HPCh. 4.1 - Prob. 48HPCh. 4.1 - Prob. 49HPCh. 4.1 - Prob. 50HPCh. 4.1 - Prob. 51HPCh. 4.1 - Prob. 52HPCh. 4.1 - Prob. 53PFACh. 4.1 - Prob. 54PFACh. 4.1 - Prob. 55PFACh. 4.1 - Prob. 56PFACh. 4.1 - Prob. 57PFACh. 4.1 - Prob. 58PFACh. 4.2 - Prob. 1GPCh. 4.2 - Prob. 2GPCh. 4.2 - Prob. 3AGPCh. 4.2 - Prob. 3BGPCh. 4.2 - Prob. 4AGPCh. 4.2 - Prob. 4BGPCh. 4.2 - Prob. 1CYUCh. 4.2 - Prob. 2CYUCh. 4.2 - Prob. 3CYUCh. 4.2 - Prob. 4CYUCh. 4.2 - Prob. 5CYUCh. 4.2 - Prob. 6CYUCh. 4.2 - Prob. 7CYUCh. 4.2 - Prob. 8CYUCh. 4.2 - Prob. 9CYUCh. 4.2 - Prob. 10CYUCh. 4.2 - Prob. 11CYUCh. 4.2 - Prob. 12CYUCh. 4.2 - Prob. 13PPSCh. 4.2 - Prob. 14PPSCh. 4.2 - Prob. 15PPSCh. 4.2 - Prob. 16PPSCh. 4.2 - Prob. 17PPSCh. 4.2 - Prob. 18PPSCh. 4.2 - Prob. 19PPSCh. 4.2 - Prob. 20PPSCh. 4.2 - Prob. 21PPSCh. 4.2 - Prob. 22PPSCh. 4.2 - Prob. 23PPSCh. 4.2 - Prob. 24PPSCh. 4.2 - Prob. 25PPSCh. 4.2 - Prob. 26PPSCh. 4.2 - Prob. 27PPSCh. 4.2 - Prob. 28PPSCh. 4.2 - Prob. 29PPSCh. 4.2 - Prob. 30PPSCh. 4.2 - Prob. 31PPSCh. 4.2 - Prob. 32PPSCh. 4.2 - Prob. 33PPSCh. 4.2 - Prob. 34PPSCh. 4.2 - Prob. 35PPSCh. 4.2 - Prob. 36PPSCh. 4.2 - Prob. 37PPSCh. 4.2 - 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Prob. 14PPSCh. 4.6 - Prob. 15HPCh. 4.6 - Prob. 16HPCh. 4.6 - Prob. 17HPCh. 4.6 - Prob. 18HPCh. 4.6 - Prob. 19PPSCh. 4.6 - Prob. 20PPSCh. 4.6 - Prob. 21PPSCh. 4.6 - Prob. 22PPSCh. 4.6 - Prob. 23PPSCh. 4.7 - Prob. 1AGPCh. 4.7 - Prob. 1BGPCh. 4.7 - Prob. 2AGPCh. 4.7 - Prob. 2BGPCh. 4.7 - Prob. 3AGPCh. 4.7 - Prob. 3BGPCh. 4.7 - Prob. 4AGPCh. 4.7 - Prob. 4BGPCh. 4.7 - Prob. 4CGPCh. 4.7 - Prob. 1CYUCh. 4.7 - Prob. 2CYUCh. 4.7 - Prob. 3CYUCh. 4.7 - Prob. 4CYUCh. 4.7 - Prob. 5CYUCh. 4.7 - Prob. 6CYUCh. 4.7 - Prob. 7CYUCh. 4.7 - Prob. 8PPSCh. 4.7 - Prob. 9PPSCh. 4.7 - Prob. 10PPSCh. 4.7 - Prob. 11PPSCh. 4.7 - Prob. 12PPSCh. 4.7 - Prob. 13PPSCh. 4.7 - Prob. 14PPSCh. 4.7 - Prob. 15PPSCh. 4.7 - Prob. 16PPSCh. 4.7 - Prob. 17PPSCh. 4.7 - Prob. 18PPSCh. 4.7 - Prob. 19PPSCh. 4.7 - Prob. 20PPSCh. 4.7 - Prob. 21PPSCh. 4.7 - Prob. 22PPSCh. 4.7 - Prob. 23PPSCh. 4.7 - Prob. 24PPSCh. 4.7 - Prob. 25PPSCh. 4.7 - Prob. 26PPSCh. 4.7 - Prob. 27PPSCh. 4.7 - Prob. 28PPSCh. 4.7 - Prob. 29PPSCh. 4.7 - Prob. 30PPSCh. 4.7 - Prob. 31PPSCh. 4.7 - Prob. 32PPSCh. 4.7 - Prob. 33PPSCh. 4.7 - Prob. 34PPSCh. 4.7 - Prob. 35PPSCh. 4.7 - Prob. 36PPSCh. 4.7 - Prob. 37PPSCh. 4.7 - Prob. 38HPCh. 4.7 - Prob. 39HPCh. 4.7 - Prob. 40HPCh. 4.7 - Prob. 41HPCh. 4.7 - Prob. 42HPCh. 4.7 - Prob. 43HPCh. 4.7 - Prob. 44PFACh. 4.7 - Prob. 45PFACh. 4.7 - Prob. 46PFACh. 4.7 - Prob. 47PFACh. 4.7 - Prob. 48PFACh. 4.7 - Prob. 49PFACh. 4.7 - Prob. 50PFACh. 4.7 - Prob. 51PFACh. 4.7 - Prob. 52PFACh. 4 - Prob. 1MCQCh. 4 - Prob. 2MCQCh. 4 - Prob. 3MCQCh. 4 - Prob. 4MCQCh. 4 - Prob. 5MCQCh. 4 - Prob. 6MCQCh. 4 - Prob. 7MCQCh. 4 - Prob. 8MCQCh. 4 - Prob. 9MCQCh. 4 - Prob. 10MCQCh. 4 - Prob. 11MCQCh. 4 - Prob. 12MCQCh. 4 - Prob. 13MCQCh. 4 - Prob. 14MCQCh. 4 - Prob. 15MCQCh. 4 - Prob. 16MCQCh. 4 - Prob. 17MCQCh. 4 - Prob. 18MCQCh. 4 - Prob. 19MCQCh. 4 - Prob. 20MCQCh. 4 - Prob. 21MCQCh. 4 - Prob. 22MCQCh. 4 - Prob. 23MCQCh. 4 - Prob. 1SGRCh. 4 - Prob. 2SGRCh. 4 - Prob. 3SGRCh. 4 - Prob. 4SGRCh. 4 - Prob. 5SGRCh. 4 - Prob. 6SGRCh. 4 - Prob. 7SGRCh. 4 - Prob. 8SGRCh. 4 - Prob. 9SGRCh. 4 - Prob. 10SGRCh. 4 - Prob. 11SGRCh. 4 - Prob. 12SGRCh. 4 - Prob. 13SGRCh. 4 - Prob. 14SGRCh. 4 - Prob. 15SGRCh. 4 - Prob. 16SGRCh. 4 - Prob. 17SGRCh. 4 - Prob. 18SGRCh. 4 - Prob. 19SGRCh. 4 - Prob. 20SGRCh. 4 - Prob. 21SGRCh. 4 - Prob. 22SGRCh. 4 - Prob. 23SGRCh. 4 - Prob. 24SGRCh. 4 - Prob. 25SGRCh. 4 - Prob. 26SGRCh. 4 - Prob. 27SGRCh. 4 - Prob. 28SGRCh. 4 - Prob. 29SGRCh. 4 - Prob. 30SGRCh. 4 - Prob. 31SGRCh. 4 - Prob. 32SGRCh. 4 - Prob. 33SGRCh. 4 - Prob. 34SGRCh. 4 - Prob. 35SGRCh. 4 - Prob. 36SGRCh. 4 - Prob. 37SGRCh. 4 - Prob. 38SGRCh. 4 - Prob. 39SGRCh. 4 - Prob. 40SGRCh. 4 - Prob. 41SGRCh. 4 - Prob. 42SGRCh. 4 - Prob. 43SGRCh. 4 - Prob. 44SGRCh. 4 - Prob. 45SGRCh. 4 - Prob. 46SGRCh. 4 - Prob. 47SGRCh. 4 - Prob. 48SGRCh. 4 - Prob. 49SGRCh. 4 - Prob. 50SGRCh. 4 - Prob. 51SGRCh. 4 - Prob. 52SGRCh. 4 - Prob. 53SGRCh. 4 - Prob. 54SGRCh. 4 - Prob. 55SGRCh. 4 - Prob. 56SGRCh. 4 - Prob. 57SGRCh. 4 - Prob. 58SGRCh. 4 - Prob. 59SGRCh. 4 - Prob. 60SGRCh. 4 - Prob. 61SGRCh. 4 - Prob. 62SGRCh. 4 - Prob. 63SGRCh. 4 - Prob. 64SGRCh. 4 - Prob. 65SGRCh. 4 - Prob. 66SGRCh. 4 - Prob. 67SGRCh. 4 - Prob. 1PTCh. 4 - Prob. 2PTCh. 4 - Prob. 3PTCh. 4 - Prob. 4PTCh. 4 - Prob. 5PTCh. 4 - Prob. 6PTCh. 4 - Prob. 7PTCh. 4 - Prob. 8PTCh. 4 - Prob. 9PTCh. 4 - Prob. 10PTCh. 4 - Prob. 11PTCh. 4 - Prob. 12PTCh. 4 - Prob. 13PTCh. 4 - Prob. 14PTCh. 4 - Prob. 15PTCh. 4 - Prob. 16PTCh. 4 - Prob. 17PTCh. 4 - Prob. 18PTCh. 4 - Prob. 19PTCh. 4 - Prob. 20PTCh. 4 - Prob. 1CRCh. 4 - Prob. 2CRCh. 4 - Prob. 3CRCh. 4 - Prob. 4CRCh. 4 - Prob. 5CRCh. 4 - Prob. 6CRCh. 4 - Prob. 7CRCh. 4 - Prob. 8CRCh. 4 - Prob. 9CRCh. 4 - Prob. 10CRCh. 4 - Prob. 11CRCh. 4 - Prob. 12CRCh. 4 - Prob. 13CRCh. 4 - Prob. 14CRCh. 4 - Prob. 15CR
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